python

问题 Look this code: class MyClass_1(): @staticmethod def method_1(func): return func(1, 2, 3) class MyClass_2(): my_func = lambda a,b,c : a*b*c # I need to call this method def method_2(self): result = MyClass_1.method_1(self.my_func) print(result) My error: TypeError: () takes 3 positional arguments but 4 were given I need to call the lambda function my_func in the same way as the code above, but a self is appearing from somewhere I don't know and causing this error. What am I missing? 回答1:

问题 Hour Site 01/08/2020 00:00 A 01/08/2020 00:00 B 01/08/2020 00:00 C 01/08/2020 00:00 D 01/08/2020 01:00 A 01/08/2020 01:00 B 01/08/2020 01:00 E 01/08/2020 01:00 F 01/08/2020 02:00 A 01/08/2020 02:00 E 01/08/2020 03:00 C 01/08/2020 03:00 G ….. 01/08/2020 04:00 x 01/08/2020 04:00 s ….. 01/08/2020 23:00 G 02/08/2020 00:00 G I have a dataframe like above. I want to count how many times a site comes in consecutive hours & start and end timestamp. wheres in each hour there are multiple sites. For

问题 Hour Site 01/08/2020 00:00 A 01/08/2020 00:00 B 01/08/2020 00:00 C 01/08/2020 00:00 D 01/08/2020 01:00 A 01/08/2020 01:00 B 01/08/2020 01:00 E 01/08/2020 01:00 F 01/08/2020 02:00 A 01/08/2020 02:00 E 01/08/2020 03:00 C 01/08/2020 03:00 G ….. 01/08/2020 04:00 x 01/08/2020 04:00 s ….. 01/08/2020 23:00 G 02/08/2020 00:00 G I have a dataframe like above. I want to count how many times a site comes in consecutive hours & start and end timestamp. wheres in each hour there are multiple sites. For

问题 i want to have default value in my form which should be current user's choice. For example, user chooses to give 5 for a movie and he should see 5 in form until he changes it. views.py class MovieDetailView(FormMixin, DetailView): model = Movie template_name = 'main/detail_movie.html' context_object_name = 'movie' form_class = RateForm def get_context_data(self, **kwargs): context = super(MovieDetailView, self).get_context_data(**kwargs) context['form'] = RateForm(initial={'movie': self

问题 i want to have default value in my form which should be current user's choice. For example, user chooses to give 5 for a movie and he should see 5 in form until he changes it. views.py class MovieDetailView(FormMixin, DetailView): model = Movie template_name = 'main/detail_movie.html' context_object_name = 'movie' form_class = RateForm def get_context_data(self, **kwargs): context = super(MovieDetailView, self).get_context_data(**kwargs) context['form'] = RateForm(initial={'movie': self

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 9 years ago . I've written a python script to convert a text file to html file. But that is kind of useless if I can't put them all together. What I'm supposed to do is display all the reports onto the website (the server part

问题 Im building a p2p system when the peers are constantly listening for incoming connections (new peers) and sending commands through the terminal (user input) to the other peers. I am having difficulty looking for user input from the keyboard while always looking for new peers. print 'Listening...' while not shutdown: while sys.stdin in select.select([sys.stdin], [], [], 0)[0]: #look for keyboard input... not working line = sys.stdin.readline() if line: send_message(line) else: # an empty line

问题 This question already has answers here : QtDesigner changes will be lost after redesign User Interface (2 answers) Closed 10 months ago . i have created a ui file, window.ui (consist with a tab widget) and a Widget file student (some buttons,functions) using qtDesigner and than convert into py file using pyuic5. and inherit in a separate file like mainWindow.py and mainStudent.py . i added a tabWidget into mainWindow.py and i want to call the page student.py from the tab . so i create a new

问题 Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). Question link is here The recursion method need to traverse the tree twice. But one of the comment provided a solution used a technique called 'Null check'. I can't understand why in this way can we avoid checking the tree twice? Here is his code in C++: bool isSymmetric(TreeNode* root) { if (!root) return true; return isSymmetric(root->left, root->right); } bool isSymmetric(TreeNode* t1, TreeNode*

问题 I searched a lot about it. All the articles i get include SQLAlchemy and none of them deal with mysql. I am working with flask and i have a database in mysql and i need to display the data in pages. Like 1000 images, per page 10 so 100 pages. In mysql we can do pagination with the help of limit. And the routes can be: @app.route('/images', defaults={'page':1}) @app.route('/images/page/<int:page>') I need to ask is this all that is needed for pagination? or am i forgetting something important