python-dateutil

问题 I have gone through multiple links before posting this question so please read through and below are the two answers which have solved 90% of my problem: parse multiple dates using dateutil How to parse multiple dates from a block of text in Python (or another language) Problem : I need to parse multiple dates in multiple formats in Python Solution by Above Links : I am able to do so but there are still certain formats which I am not able to do so. Formats which still can't be parsed are:

问题 I'm using dateutil.parser.parse to format a date from a string. But now it mixes up the month and the day. I have a string that contains 05.01.2015 . After dateutil.parser.parse("05.01.2015") it returns: datetime.datetime(2015, 5, 1, 0, 0) I hoped the it would return (2015, 1, 5, 0, 0) How can I tell the code that the format is dd.mm.yyyy ? For the record, 25.01.2015 will be parsed as (2015, 1, 25, 0, 0) , as expected. 回答1: Specify dayfirst=True : >>> dateutil.parser.parse("05.01.2015",

问题 I am doing some time calculations in Python. Goal: Part of this is trying to : Given a date, add time interval (X years, X months, X weeks), return date ie input args: input_time (datetime.date), interval (datetime.timedelta) return: datetime.date I looked at the datetime and datetime.timedelta docs class datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0)¶. These seem to work well if I want to add a certain number of hours or weeks. However,

问题 I'm sure there's a really simple solution to this, but I'm still fairly new to Python. I'm trying to use dateutil.parser.parse() to parse a string with a timestamp in it: >>> import dateutil.parser >>> a = dateutil.parser.parse("2011-10-01 12:00:00+01:00") >>> print a 2011-10-01 12:00:00+01:00 This works fine on my Linux server, but on my Windows test box it gives an error: >>> import dateutil.parser >>> a = dateutil.parser.parse("2011-10-01 12:00:00+01:00") Traceback (most recent call last):

问题 Pandas internals question: I've been surprised to find a few times that explicitly passing a callable to date_parser within pandas.read_csv results in much slower read time than simply using infer_datetime_format=True . Why is this? Will timing differences between these two options be date-format-specific, or what other factors will influence their relative timing? In the below case, infer_datetime_format=True takes one-tenth the time of passing a date parser with a specified format. I would

问题 I am trying to dateutil.parser.parse() to parse the default str(datetime.datetime.now()) output using timezone-aware datetimes. However, parse() seems to lose the timezone information and replace it with the local time timezone. Below is the IPython output: In [1]: from django.utils.timezone import now In [3]: import dateutil In [4]: t = now() In [6]: print t 2014-07-14 08:51:49.123342+00:00 In [7]: st = unicode(t) In [8]: print dateutil.parser.parse(st) 2014-07-14 08:51:49.123342+02:00 As

问题 This question already has answers here : How to determine appropriate strftime format from a date string? (3 answers) Closed 2 years ago . I'm getting a date as a string, then I'm parsing it to datetime object. Is there any way to check what's is the date format of the object? Let's say that this is the object that I'm creating: modified_date = parser.parse("2015-09-01T12:34:15.601+03:00") How can i print or get the exact date format of this object, i need this in order to verify that it's in

问题 This should be very simple, but I can't quite figure it out in Python. I want to have a function which takes two arguments, a UTC time in seconds and a zoneinfo name like 'Europe/Vienna' and returns the offset in seconds from local time and UTC for that point in time. In C it would be: /* ... code to to set local time to the time zone I want to compare against, not shown here. Then call function below to get difference vs localtime. Hardly an ideal solution, but just to demonstrate what I

问题 The following date patterns 1st January 30th April are easily parsed into instances of datetime.date via dateutil.parser.parse() : In [1]:from dateutil.parser import parse In [2]: parse('1st January') Out[2]: datetime.datetime(2012, 1, 1, 0, 0) In [3]: parse('8th April') Out[3]: datetime.datetime(2012, 4, 30, 0, 0) How can a future date be returned from parsing? I.e. parsing '1st January' would return datetime.datetime(2013, 1, 1, 0, 0) , 1st January 2013 and not 1st January 2012. Any elegant

问题 I have a date which is in local time: date: "2013-12-02 22:00:00" and another value the tz: timezone_offset: "GMT-0800" If I : dateutil.parser.parse(date).isoformat() I will get: "2013-12-02T22:00:00+0000" I want to implement the date in ISO format with the tz info and get a result of: "2013-12-02T22:00:00-0800" Something close to: parse(date,tzinfos=??).isoformat() ? How can I get the tzinfo from the string timezone_offset ? 回答1: >>> from dateutil.parser import parse >>> dt = parse("2013-12