python-3.8

Pytube only works periodically (KeyError: 'assets')

自闭症网瘾萝莉.ら 提交于 2020-12-23 02:15:19
问题 Five out of ten times Pytube will send me this error when attempting to run my small testing script. Here's the script: import pytube import urllib.request from pytube import YouTube yt = YouTube('https://www.youtube.com/watch?v=3NCyD3XoJgM') print('Youtube video title is: ' + yt.title + '! Downloading now!') Here's what I get: Traceback (most recent call last): File "youtube.py", line 6, in <module> yt = YouTube('https://www.youtube.com/watch?v=3NCyD3XoJgM') File "C:\Users\test\AppData\Local

Can't use OpenCV-Python in AWS Lambda

こ雲淡風輕ζ 提交于 2020-12-12 06:28:41
问题 I've been trying to get OpenCV into an S3 bucket and then assign it to a lambda layer. Theres very little about this online and what I have seen hasn't worked. I've managed to use docker with the amazon linux environment, and followed this tutorial. https://aws.amazon.com/premiumsupport/knowledge-center/lambda-layer-simulated-docker/ I've added setuptools, wheel and opencv-python==4.4.0.42 to the requirements.txt file. setuptools and wheel because of an earlier error where the recommendation

Can't use OpenCV-Python in AWS Lambda

心已入冬 提交于 2020-12-12 06:28:31
问题 I've been trying to get OpenCV into an S3 bucket and then assign it to a lambda layer. Theres very little about this online and what I have seen hasn't worked. I've managed to use docker with the amazon linux environment, and followed this tutorial. https://aws.amazon.com/premiumsupport/knowledge-center/lambda-layer-simulated-docker/ I've added setuptools, wheel and opencv-python==4.4.0.42 to the requirements.txt file. setuptools and wheel because of an earlier error where the recommendation

How can I get user input in a python discord bot?

ⅰ亾dé卋堺 提交于 2020-12-08 07:10:15
问题 I have a python discord bot and I need it to get user input after a command, how can I do this? I am new to python and making discord bots. Here is my code: import discord, datetime, time from discord.ext import commands from datetime import date, datetime prefix = "!!" client = commands.Bot(command_prefix=prefix, case_insensitive=True) times_used = 0 @client.event async def on_ready(): print(f"I am ready to go - {client.user.name}") await client.change_presence(activity=discord.Activity(type

Walrus operator example in PEP572

回眸只為那壹抹淺笑 提交于 2020-12-06 07:07:31
问题 One of the examples given in PEP572 is # Reuse a value that's expensive to compute [y := f(x), y**2, y**3] currently in python, you'd have to do one of the following: # option 1 y = f(x) [y, y**2, y**3] or # option 2 [f(x), f(x)**2, f(x)**3] the example implies that option 2 here could be improved, but I have never seen that recommended over the first option. Is there ever a reason why option 2 (and therefore the walrus operator) would be better than option 1? 回答1: Just to make things clear:

Walrus operator example in PEP572

故事扮演 提交于 2020-12-06 07:06:45
问题 One of the examples given in PEP572 is # Reuse a value that's expensive to compute [y := f(x), y**2, y**3] currently in python, you'd have to do one of the following: # option 1 y = f(x) [y, y**2, y**3] or # option 2 [f(x), f(x)**2, f(x)**3] the example implies that option 2 here could be improved, but I have never seen that recommended over the first option. Is there ever a reason why option 2 (and therefore the walrus operator) would be better than option 1? 回答1: Just to make things clear:

Walrus operator example in PEP572

霸气de小男生 提交于 2020-12-06 07:06:23
问题 One of the examples given in PEP572 is # Reuse a value that's expensive to compute [y := f(x), y**2, y**3] currently in python, you'd have to do one of the following: # option 1 y = f(x) [y, y**2, y**3] or # option 2 [f(x), f(x)**2, f(x)**3] the example implies that option 2 here could be improved, but I have never seen that recommended over the first option. Is there ever a reason why option 2 (and therefore the walrus operator) would be better than option 1? 回答1: Just to make things clear:

Walrus operator example in PEP572

与世无争的帅哥 提交于 2020-12-06 07:06:11
问题 One of the examples given in PEP572 is # Reuse a value that's expensive to compute [y := f(x), y**2, y**3] currently in python, you'd have to do one of the following: # option 1 y = f(x) [y, y**2, y**3] or # option 2 [f(x), f(x)**2, f(x)**3] the example implies that option 2 here could be improved, but I have never seen that recommended over the first option. Is there ever a reason why option 2 (and therefore the walrus operator) would be better than option 1? 回答1: Just to make things clear: