python-3.7

问题 I am running a simple example: import gmaps import gmaps.datasets gmaps.configure(api_key="...") earthquake_df = gmaps.datasets.load_dataset_as_df( 'earthquakes' ) locations = earthquake_df[[ 'latitude' , 'longitude' ]] weights = earthquake_df[ 'magnitude' ] fig = gmaps.figure() fig.add_layer(gmaps.heatmap_layer(locations, weights=weights)) fig but instead of seeing a heatmap, the output shows this: Figure(layout=FigureLayout(height='420px')) I am using Spyder (Python 3.7) 回答1: ( Spyder

问题 I am trying to login to Instagram with python. I am able to get the csrf Token but the requests.Session().post() doesn't seem to post the login data to the website correctly. I always get the class="no-js not-logged-in client-root" . I've been searching for a while and also tried to login into some random sites which seemed to work. In the login method I just start a requests.Session() and make a post request to the https://www.instagram.com/accounts/login/ with the login name and password as

问题 I am trying to login to Instagram with python. I am able to get the csrf Token but the requests.Session().post() doesn't seem to post the login data to the website correctly. I always get the class="no-js not-logged-in client-root" . I've been searching for a while and also tried to login into some random sites which seemed to work. In the login method I just start a requests.Session() and make a post request to the https://www.instagram.com/accounts/login/ with the login name and password as

问题 I am trying to login to Instagram with python. I am able to get the csrf Token but the requests.Session().post() doesn't seem to post the login data to the website correctly. I always get the class="no-js not-logged-in client-root" . I've been searching for a while and also tried to login into some random sites which seemed to work. In the login method I just start a requests.Session() and make a post request to the https://www.instagram.com/accounts/login/ with the login name and password as

问题 if cake == "delicious": return "yes" SyntaxError: 'return' outside function Why I get like this? 回答1: You can create some functions like this. text ="delicious" def check(text): if text=="delicious": return 'yes' check(text) 回答2: return is a keyword which can only appear in a function definition (as the syntax error says). You can simply print your output in an if/else block if cake == 'delicious': print('yes') 来源： https://stackoverflow.com/questions/52773539/why-am-i-getting-this-error-in

问题 Like the title says, I'm trying to do guild edits but on an events. Here's part of my code: @commands.guild_only() async def on_ready(self): server = self.bot.get_guild("serverid") while True: await self.bot.guild.edit(guild=server, name="foo") await asyncio.sleep(1) await self.bot.guild.edit(guild=server, name="bar") await asyncio.sleep(1) I've already tested it with a standalone command, so I know that ctx.guild.edit works but I'm not sure how to get it to work in an event. 回答1: You should

问题 import asyncio import httpx from datetime import datetime async def request_test(url): async with httpx.AsyncClient() as client: r = await client.get(url, timeout=None, headers=None) return len(r.text) async def main(rest_api_url_list ): futures = [asyncio.ensure_future(request_test(url)) for url in rest_api_url_list ] results = await asyncio.gather(*futures) print(results) print(len(results)) start = datetime.now() rest_api_url_list = [~~~~~~~~~~~~~] # 2000EA loop = asyncio.get_event_loop()

问题 Below I have added my game of life code. The rules are defined correctly, and it runs smoothly. However, the game does not work as supposed. It is not updating to the next generation, but it seems to be overwriting the current generation. As an example: Three horizontal dots are supposed to turn into three vertical dots in the next generation, but this does not happen. The solution: I have two generations, the current and the next generation. It has to apply the rules to the current

问题 I have multiple webcams connected to my PC and I would like to select one camera based on its info (name, resolution etc.). Is there a way to list all the cameras available on a PC, instead of trying all the indices in cv2.VideoCapture()? 回答1: The answer is negative. OpenCV doesn't have a method for listing the available video capture devices on your system. If you look at the code you see how currently OpenCV handles invalid device indices that don't exist. For instance for MacOS here is the

问题 I'm about to use Python.requests to get data from my own online api to my local pc. My api requires authentication which for now is done trough simply posting user/pass: params = {'user': 'username', 'pass':'password'} requests.post(url, params=params) Are this requests safe or is it going to allow a middle-man to capture that user/pass? P.S My api is using a letsencrypt ssl certificate. Python version 3.7.0 回答1: this has nothing to do with the python-requests package, but with the HTTP (and