pure

Is it possible to compile LLVM libraries to android/ARM

匿名 (未验证) 提交于 2019-12-03 02:47:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm fascinated by the Pure algebraic/functional language . The Pure interpreter uses the LLVM JIT compiler as its backend. I would like to compile Pure so that it runs on Android(ARM). Pure has a dependency on the LLVM JIT. So I need to compile LLVM source for Pure to run. Is it possible to compile LLVM source for Android (ARM) devices? There really seems to be no information about this on the web. Maybe my search terms are wrong. Searching for Android LLVM does not bring up many good hits either. 回答1: It now seems possible, the NDK now

Is it possible to implement MonadFix for `Free`?

匿名 (未验证) 提交于 2019-12-03 02:06:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: http://hackage.haskell.org/package/free in Control.Monad.Free.Free allows one to get access to the "free monad" for any given Functor . It does not, however, have a MonadFix instance. Is this because such an instance cannot be written, or was it just left out? If such an instance cannot be written, why not? 回答1: Consider the description of what mfix does: The fixed point of a monadic computation. mfix f executes the action f only once, with the eventual output fed back as the input. The word "executes", in the context of Free , means

pure-specifier on function-definition

匿名 (未验证) 提交于 2019-12-03 01:20:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: While compiling on GCC I get the error: pure-specifier on function-definition , but not when I compile the same code using VS2005. class Dummy { //error: pure-specifier on function-definition, VS2005 compiles virtual void Process() = 0 {}; }; But when the definition of this pure virtual function is not inline, it works: class Dummy { virtual void Process() = 0; }; void Dummy::Process() {} //compiles on both GCC and VS2005 What does the error means? Why cannot I do it inline? Is it legal to evade the compile issue as shown in the second code

Use pure Ant to implement if else condition (check command line input)

匿名 (未验证) 提交于 2019-12-03 01:06:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am a newbie in Ant. My ant script receives a user input variable named " env " from command line: e.g. ant doIt -Denv=test The user input value could be " test "," dev " or " prod ". I also have the " doIt " target: //What to do here? In my target, I would like to create the following if else condition for my ant script: if(env == "test") echo "test" else if(env == "prod") echo "prod" else if(env == "dev") echo "dev" else echo "You have to input env" That's to check which value user has inputted from command line, then, print a message

C++ ― why should we define the pure virtual destructor outside the class definition?

匿名 (未验证) 提交于 2019-12-03 00:48:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: class Object { public: ... virtual ~Object() = 0; ... }; Object::~Object() {} // Should we always define the pure virtual destructor outside? Question: Should we always define the pure virtual destructor outside the class definition? In other words, it is the reason that we should not define any virtual function inline? Thank you 回答1: You can define virtual functions inline. You cannot define pure virtual functions inline. The following syntax variants are simply not permitted: virtual ~Foo() = 0 { } virtual ~Foo() { } = 0; But this is fully

[杂题]:staGame(博弈论+Trie树+DFS)

天大地大妈咪最大 提交于 2019-11-30 16:24:50
题目描述 $pure$和$dirty$决定玩$T$局游戏。对于每一局游戏,有$n$个字符串,并且每一局游戏由$K$轮组成。具体规则如下:在每一轮游戏中,最开始有一个空串,两者轮流向串的末尾添加一个字符,并且需要保证该串为$n$个字符串中任意一个串的前缀,不能操作的人输掉这一轮,并且在下一轮游戏中由该轮输掉的人先手。另外为了遵循女士优先的原则,在每一局游戏的第一轮均由$pure$先手。 玩家的目标是获得整局游戏的胜利,一局游戏的胜利条件是:对手输掉最后一轮游戏。我们可以假定$pure$和$dirty$都足够聪明。 现在,对于每一局游戏,$pure$想知道获胜者是谁。 输入格式 第一行一个整数$T$,表示游戏局数。 接下来$T$组数据,每组数据第一行两个整数$n,K$,表示字符串数和轮数,接下来$n$行,每行一个字符串。 输出格式 对于每一局游戏,输出一行$"Pure"$或者$"Dirty"$表示获胜者。 样例 样例输入: 2 2 3 a b 1 2 ab 样例输出: Pure Dirty 数据范围与提示 对于$10\%$的数据,字符串总长不超过$5$,且$K\leqslant 2$; 对于$20\%$的数据,字符串总长不超过$5$; 对于另外$20\%$的数据,$K=1$; 对于$100\%$的数据,$1\leqslant n\le 10^5;1\leqslant K