punctuation

问题 I am stumped by this one. I am just learning regular expressions and cannot figure out why this will not return punctuation marks. here is a piece of the text file the regex is parsing: APRIL/NNP is/VBZ the/DT cruellest/JJ month/NN ,/, breeding/VBG Lilacs/NNP out/RB of/IN the/DT dead/JJ land/NN text = open_file.read() grammarList = raw_input("Enter your grammar string: "); tags = grammarList.split("^") tags_pattern = r'\s+'.join(r"([\w\,\:\;\"\-\.]+)/{0}".format(re.escape(tag)) for tag in

问题 I`m working with documents, and I need to have the words isolated without punctuation. I know how to use string.split(" ") to make each word just the letters, but the punctuation baffles me. 回答1: this is an example using regex, and the result is ['this', 'is', 'a', 'string', 'with', 'punctuation'] s = " ,this ?is a string! with punctuation. " import re pattern = re.compile('\w+') result = pattern.findall(s) print(result) 来源： https://stackoverflow.com/questions/37063500/strip-punctuation-from

问题 I'm trying to remove a list of punctuation from my text file but I have only one problem with words separated from hyphen. For example, if I have the word "post-trauma" I get "posttrama" conversely I want to get "post" "trauma". My code is: punct=['!', '#', '"', '%', '$', '&', ')', '(', '+', '*', '-'] with open(myFile, "r") as f: text= f.read() remove = '|'.join(REMOVE_LIST) #list of word to remove regex = re.compile(r'('+remove+r')', flags=re.IGNORECASE) out = regex.sub("", text) delta= " "

问题 Using php regexp in a simple way, is it possible to modify a string to add a space after periods that follow words but not after a period that is preceded and followed by a number such as 1.00? I also need it to ignore single letter abbreviations such as N.Y. String.Looks like this.With an amount of 1.00 and references N.Y. Needs to be changed to... String. Looks like this. With an amount of 1.00 and references N.Y. This should allow for multiple instances within the string of course... 回答1:

问题 Dealing with forms in PHP has always given me major headaches. Primarily formatting; handling punctuation inside a form input, manipulating strings for database insertions, stripping when retrieving from database, etc. Is there an easy alternative to strip_slashes and all that junk? I don't want a tool like a form wizard that does everything for you - I still would like a high level of customization. What would be nice though is a tool that says "I want this text field to connect to this

问题 Say I have a string of "10, 5, 3" How can I get rid of the commas so the string is just "10 5 3"? Should I be using strtok? 回答1: char *r, *w; for (w = r = str; *r; r++) { if (*r != ',') { *w++ = *r; } } *w = '\0'; 回答2: Create a new string with the same size (+1 for the terminating character) as your current string, copy each character one by one and replace ',' by ' '. In a for loop you would have something like this : if (old_string[i] == ',') new_string[i] = ' '; else new_string[i] = old

问题 I want to search 100,000 and 100000 only by querying 100000 (or only by querying 100,000). Is it possible to search like that. The purpose to perform this is, that user may add a comma at any place or no comma at all but the strings (100,000 or 100000) should be searched anyway... 回答1: Don't know if this is correct, but maybe you can write some kind of filter factory where numbers are always indexed as numbers formatted with commas and with out commas. Or you can have both the index & query

问题 I made this function to limit the length of a string in the output, /* limit the lenght of the string */ function limit_length($content, $limit) { # strip all the html tags in the content $output = strip_tags($content); # count the length of the content $length = strlen($output); # check if the length of the content is more than the limit if ($length > $limit) { # limit the length of the content in the output $output = substr($output,0,$limit); $last_space = strrpos($output, ' '); # add dots

问题 So I tried using join() after splitting a string into words and punctuation but it joins the string with a space in between the word and punctuation. b = ['Hello', ',', 'who', 'are', 'you', '?'] c = " ".join(b) But that returns: c = 'Hello , who are you ?' and I want: c = 'Hello, who are you?' 回答1: You could join on the punctuation first: def join_punctuation(seq, characters='.,;?!'): characters = set(characters) seq = iter(seq) current = next(seq) for nxt in seq: if nxt in characters:

问题 Is there any effective way to remove punctuation in text but keeping hyphenated expressions, such as "accident-prone"? I used the following function to clean my text clean.text = function(x) { # remove rt x = gsub("rt ", "", x) # remove at x = gsub("@\\w+", "", x) x = gsub("[[:punct:]]", "", x) x = gsub("[[:digit:]]", "", x) # remove http x = gsub("http\\w+", "", x) x = gsub("[ |\t]{2,}", "", x) x = gsub("^ ", "", x) x = gsub(" $", "", x) x = str_replace_all(x, "[^[:alnum:][:space:]'-]", " ")