projection

How to modify only one or two field(s) in LINQ projections?

岁酱吖の 提交于 2021-02-19 01:17:32
问题 I have this LINQ query: List<Customers> customers = customerManager.GetCustomers(); return customers.Select(i => new Customer { FullName = i.FullName, Birthday = i.Birthday, Score = i.Score, // Here, I've got more fields to fill IsVip = DetermineVip(i.Score) }).ToList(); In other words, I only want one or two fields of the list of the customers to be modified based on a condition, in my business method. I've got two ways to do this, Using for...each loop, to loop over customers and modify

Convert Latitude and Longitude values to a custom sized grid

橙三吉。 提交于 2021-02-18 17:13:13
问题 I am making a java program that classifies a set of lat/lng coordinates to a specific rectangle of a custom size, so in effect, map the surface of the earth into a custom grid and be able to identify what rectangle/ polygon a point lies in. The way to do this I am looking into is by using a map projection (possibly Mercator). For example, assuming I want to classify a long/lat into 'squares' of 100m x 100m, 44.727549, 10.419704 and 44.727572, 10.420460 would classify to area X and 44.732496,

Radius of projected sphere in screen space

不打扰是莪最后的温柔 提交于 2021-02-17 22:10:49
问题 I'm trying to find the visible size of a sphere in pixels, after projection to screen space. The sphere is centered at the origin with the camera looking right at it. Thus the projected sphere should be a perfect circle in two dimensions. I am aware of this 1 existing question. However, the formula given there doesn't seem to produce the result I want. It is too small by a few percent. I assume this is because it is not correctly taking perspective into account. After projecting to screen

Radius of projected sphere in screen space

蓝咒 提交于 2021-02-17 22:09:41
问题 I'm trying to find the visible size of a sphere in pixels, after projection to screen space. The sphere is centered at the origin with the camera looking right at it. Thus the projected sphere should be a perfect circle in two dimensions. I am aware of this 1 existing question. However, the formula given there doesn't seem to produce the result I want. It is too small by a few percent. I assume this is because it is not correctly taking perspective into account. After projecting to screen

Select multiple fields at different levels

[亡魂溺海] 提交于 2021-02-16 20:51:30
问题 I've a .json file that look like : [ { "network": "X.X.X.1", "defaultGateway": "X.X.X.X", "ipAddressTab": [ { "foo1": "10.0.0.1", "foo2": "network", "foo3": "reserved", "foo4": null, "foo5": null, "foo6": null, "foo7": null, "foo8": null, "foo9": null, "foo10": null, "foo11": null }, { "foo1": "10.0.0.2", "foo2": "network", "foo3": "reserved", "foo4": null, "foo5": null, "foo6": null, "foo7": null, "foo8": null, "foo9": null, "foo10": null, "foo11": null }, { "foo1": "10.0.0.3", "foo2":

Convert Cartesian (X,Y) to coordinates GPS (Latitude & Longitude)

南楼画角 提交于 2021-02-11 14:51:18
问题 I need to convert coordinates X, Y into Latitude and Longitude. I've read wikipedia map projections, similar stackoverflow forums, applied my custom solutions and still didn't work. The coordinates I get from my formula are wrong, Longitude is acceptable but Latitude is not. I don't see where my calculous is wrong. The X,Y Point is taken from a JLayeredPane with the size of a background Map image, once a smaller image is released on this Map image, the point is taken. public void

makegrid equivalent in cartopy, moving from basemap to cartopy

老子叫甜甜 提交于 2021-02-11 05:33:36
问题 So, I have been using Basemap for years in Python 2.7, I am moving to Python3.7 and would like to move to cartopy. I work with a lot of data where I have the projection info but I don't have lat and lon grids of the data. This is how I would handle things in Basemap. m=Basemap( llcrnrlon=-118.300, llcrnrlat=20.600, urcrnrlon=-58.958, urcrnrlat=51.02, projection='lcc', lat_1=38., lat_2=38., lon_0=-95., resolution ='l', area_thresh=1000. ) mwidth = 1008 #for 163 5km AWIPS2 grid mheight = 722

How to calculate ray in real-world coordinate system from image using projection matrix?

你说的曾经没有我的故事 提交于 2021-02-10 20:38:56
问题 Given n images and a projection matrix for each image, how can i calculate the ray (line) emitted by each pixel of the images, which is intersecting one of the three planes of the real-world coordinate system? The object captured by the camera is at the same position, just the camera's position is different for each image. That's why there is a separate projection matrix for each image. As far as my research suggests, this is the inverse of the 3D to 2D projection. Since information is lost

How to calculate ray in real-world coordinate system from image using projection matrix?

≡放荡痞女 提交于 2021-02-10 20:35:36
问题 Given n images and a projection matrix for each image, how can i calculate the ray (line) emitted by each pixel of the images, which is intersecting one of the three planes of the real-world coordinate system? The object captured by the camera is at the same position, just the camera's position is different for each image. That's why there is a separate projection matrix for each image. As far as my research suggests, this is the inverse of the 3D to 2D projection. Since information is lost

Spring Data Rest projection sorting

别说谁变了你拦得住时间么 提交于 2021-02-07 20:21:05
问题 I have a projection for my entity and I need to sort it by field of inner class. This is part of my entities: class Person { UUID guid; Set<DisabilityHistory> disabilityHistory; } class DisabilityHistory { Date createdDate; } I know about sort param but request like api/person/search?projection=myProjection&sort=disabilityHistory.createdDate,asc doesn't work. The only solution I have found is using @OrderBy annotation in my entity but in this case it will sorted always and I worried about