processing-efficiency

Socket.IO bare-bones no-method objects or fully-equipped class-based objects for client updates?

℡╲_俬逩灬. 提交于 2019-12-25 06:31:08
问题 Say I have an array of players in my Node app, each player being an object. Every tick, I send my array to my clients, with Socket.IO. I'm not sure, out of the two following methods, would be the most efficient way of doing this: For each player , I add a basic object to my array, such as {id:1,x:10,y:20,color:"#000000"} . Then I can send the whole array, raw, to my clients. Functions that I need are non-object specific and handle the parsed object. This options is used in this Agar.io clone.

Prolog: efficiency

拜拜、爱过 提交于 2019-12-24 16:07:31
问题 Is there a way in prolog to make the following shorter: rule(prop, [1/2,2/2]). rule(prop, [1/3,2/3,3/3]). rule(prop, [1/4,2/4,3/4,4/4]). rule(prop, [1/5,2/5,3/5,4/5,5/5]). rule(prop, [1/6,2/6,3/6,4/6,5/6,6/6]). rule(prop, [1/7,2/7,3/7,4/7,5/7,6/7,7/7]). 回答1: The following code isn't necessarily "shorter" for the case of 6 different rules, but it is more scalable, which is probably what you really mean. You can break this down as follows. First, a rule that generates one list: list_props(N, N,

boost::multi_index composite keys efficiency

时间秒杀一切 提交于 2019-12-24 03:18:36
问题 Long time reader first time poster! I'm playing around with the boost::multi_index container stuff and have a rather in-depth question that hopefully a boost or C++ container expert might know (my knowledge in C++ containers is pretty basic). For reference, the boost documentation on composite keys can be found here: boost::multi_index composite keys. When using a composite key, the documentation states that "Composite keys are sorted by lexicographical order, i.e. sorting is performed by the

How do I optimize sapply in R to calculate running totals on a dataframe

六眼飞鱼酱① 提交于 2019-12-23 20:13:50
问题 I wrote a function in R to calculate cumulative totals by month number, but the execution time of my method grows exponentially as the dataset gets larger. I'm a novice R programmer, can you help me make this more efficient ? The function and the way I invoke the function: accumulate <- function(recordnum,df){ sumthese <- (df$subject == df$subject[recordnum]) & (df$month <= df$month[recordnum]) sum(df$measurement[sumthese]) } set.seed(42) datalength = 10 df <- data.frame(measurement = runif(1

Efficiency & speedup of parallel vs. serial

早过忘川 提交于 2019-12-21 19:48:23
问题 Currently, I am reading over a study a guide that my professor handed out in class. The study guide is not an assignment, just something to know what to expect on an exam. I've completed all but 1 problem and was hoping someone could help me out. Here is the question: Suppose Tserial = n and Tparallel = n/p + log2(p), where times are in miliseconds and p is the number of processes. If we increase p by a factor of k, find a formula for how much we’ll need to increase n in order to maintain

Technique to remove common words(and their plural versions) from a string

痴心易碎 提交于 2019-12-20 18:36:06
问题 I am attempting to find tags(keywords) for a recipe by parsing a long string of text. The text contains the recipe ingredients, directions and a short blurb. What do you think would be the most efficient way to remove common words from the tag list? By common words, I mean words like: 'the', 'at', 'there', 'their' etc. I have 2 methodologies I can use, which do you think is more efficient in terms of speed and do you know of a more efficient way I could do this? Methodology 1: - Determine the

Laravel eager loading vs explicit join

此生再无相见时 提交于 2019-12-18 03:11:39
问题 This might sound like an obvious question but I just want to get some reassurance. Using Laravel's eager loading functionality, from what I understand it will create two queries to return a whole list of related results (say if you're working with two tables). However, and correct me if I'm wrong, using a join statement will leave you with only one query , which creates one less round trip to the server's database (MySQL) and is a more efficient query. I know that you can write join queries

Laravel eager loading vs explicit join

旧城冷巷雨未停 提交于 2019-12-18 03:11:13
问题 This might sound like an obvious question but I just want to get some reassurance. Using Laravel's eager loading functionality, from what I understand it will create two queries to return a whole list of related results (say if you're working with two tables). However, and correct me if I'm wrong, using a join statement will leave you with only one query , which creates one less round trip to the server's database (MySQL) and is a more efficient query. I know that you can write join queries

fastest way to modify part of array

[亡魂溺海] 提交于 2019-12-13 06:37:27
问题 I want to perform not operation to a block of continous elements of a bool array and then read back the complete array. I am using the following code to perform the operation. bool arr[100000]={0}; cin>>x>>y; for(i=x; i<=y; i++) arr[i]=!arr[i]; //Some other operations on the array for(i=0; i<=100000; i++) arr+=arr[i]; This works fine but i am trying to increase the speed of the program. Is there a better way to perform the same operation? 回答1: Consider to use bitset. Compare performance -

Battery consumption with custom animated drawable

可紊 提交于 2019-12-13 06:10:04
问题 Loooong time viewer, finally getting round to signing up here at StackOverflow! After a very long time searching for a way to do a scrolling background of a ViewGroup in Android, I've developed the following: public class SlidingDrawable extends Drawable implements Drawable.Callback { private static final String TAG = "SlidingDraw"; private static float STEP_SIZE = 1.0f; private BitmapDrawable mBitmap; private Context mContext; private float mPosX; private int mBitmapWidth; private Runnable