Pre increment and post increment function call
问题 #include<stdio.h> int main() { void add(); int i=2; add(i++,--i); print("%d",i) } void add(int a,int b) { print("%d %d",a,b); } /*what are a and b's value i am actually not getting the answer why b is 2 */ 回答1: in line 6 where add() is called first args is i++ so it will send value 2 ie value of i to the function and then add 1 now i=3. second args is --i now it will subtract 1 and iwill now be 2 again and then send value 2 to function So I think your answer will print 2 2 (that is value of a