postdata

Grails: where does request.JSON come from, and how do I put things there with jQuery's .ajax() or .post()?

老子叫甜甜 提交于 2019-12-05 08:02:34
I have a controller that takes some json in the ?request body? and does awesome things with it: def myController(){ def myAction(){ println "Here is request.JSON: ${request.JSON as JSON}" println "Here is params: $params" //do awesome stuff with request.JSON only return } } So I can hit this with cURL like so: curl -i -H "content-type: application/json" -d "{\"someVariable\":\"Absolutely\"}" And my grails controller prints: Here is request.JSON: {"someVariable":"Absolutely"} Here is params: [controller:'myController', action:'myAction'] So far so good, but when I try to do this with jQuery it

How to dump the whole POST data to a file in ASP.NET

强颜欢笑 提交于 2019-12-05 06:14:54
I'm currently trying to port an app from asp.net to php, however I just hit a wall and need a hand with this. I need to dump all the data an .aspx recieves via POST to a file, but I have no clue on how to do this any ideas ? You can use the InputStream property of the Request object. This will give you the raw data of the http request. Generally you might want to do this as a custom http handler, but I believe you can do it any time. if (Request.RequestType == "POST") { using (StreamReader reader = new StreamReader(Request.InputStream)) { // read the stream here using reader.ReadLine() and do

ASP.NET custom control: when is LoadPostData() called?

我们两清 提交于 2019-12-05 04:48:38
I have developed a custom control that extends ListBox. The idea is that the control 'remembers' modifications to its elements which occurred client-side, e.g. as a result of an AJAX request. The way it works is that the control also renders a hidden input, and the result of the AJAX request is stored in the hidden input. This is posted back, and the control's LoadPostData() method looks for the hidden input, and if the hidden input has data, creates the ListItem collection from it. This works perfectly so long as the user has made a selection from the list box . If they have not, the

Prevent duplicate record insertion on refresh without redirecting

三世轮回 提交于 2019-12-02 04:24:36
I have this bit of script: if (isset($_POST['comment_posted'])) { $user_comment = mysql_real_escape_string($_POST['user_comment']); $add_user_comment = Event::addUserComment($id,$user->user_id,$user_comment); } After a user submits his comment, and refreshes the page, he is being presented with the "you are going to resend the post data" warning. And if the user accepts, it will re-insert the user comment. I understand that I can prevent that by adding using the header function and redirect the member to the same page. Is it possible to solve this issue without redirecting the member? No. You

Variables in wget post data

爷,独闯天下 提交于 2019-11-30 06:20:38
I am working on a simple bash script to download images from the website Tumblr. The idea is to use read to get login info from the user, and wget --post-data to log in, and this is what I have: read -p "Tumblr login email: " EMAIL read -p "Tumblr login password: " PASSWRD wget --user-agent=Mozilla/5.0 --save-cookies cookies.txt --post-data 'email=$EMAIL&password=$PASSWRD' --no-check-certificate https://www.tumblr.com/login However, it is sending "$EMAIL" and "$PASSWRD" instead of the strings for the variables, is there any way to get it to send values that have been inputted by the user? kev

Variables in wget post data

故事扮演 提交于 2019-11-29 05:03:48
问题 I am working on a simple bash script to download images from the website Tumblr. The idea is to use read to get login info from the user, and wget --post-data to log in, and this is what I have: read -p "Tumblr login email: " EMAIL read -p "Tumblr login password: " PASSWRD wget --user-agent=Mozilla/5.0 --save-cookies cookies.txt --post-data 'email=$EMAIL&password=$PASSWRD' --no-check-certificate https://www.tumblr.com/login However, it is sending "$EMAIL" and "$PASSWRD" instead of the strings

Android HTTPUrlConnection : how to set post data in http body?

﹥>﹥吖頭↗ 提交于 2019-11-28 20:02:32
I've already created my HTTPUrlConnection : String postData = "x=val1&y=val2"; URL url = new URL(strURL); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setRequestMethod("POST"); conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); conn.setRequestProperty("Set-Cookie", sessionCookie); conn.setRequestProperty("Content-Length", "" + Integer.toString(postData.getBytes().length)); // How to add postData as http body? conn.setUseCaches(false); conn.setDoInput(true); conn.setDoOutput(true); I don't know how to set postData in http body. How to do so?

Adding HTTP Headers and Post data in a System.Windows.Forms.WebBrowser

折月煮酒 提交于 2019-11-28 06:01:01
问题 I'm trying to use the System.Windows.Forms.WebBrowser to make a request that both sends POST data and custom HTTP headers. I'd like to set the user-agent of the request as well. How could I do this? 回答1: You can send POST data and additional HTTP headers using this Navigate overload. But to have complete control over the request form including user agent and suppressing headers that IE will send by default would (if even possible) require so much interop that you'd be better off just rolling

Android HTTPUrlConnection : how to set post data in http body?

你离开我真会死。 提交于 2019-11-27 20:38:51
问题 I've already created my HTTPUrlConnection : String postData = "x=val1&y=val2"; URL url = new URL(strURL); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setRequestMethod("POST"); conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); conn.setRequestProperty("Set-Cookie", sessionCookie); conn.setRequestProperty("Content-Length", "" + Integer.toString(postData.getBytes().length)); // How to add postData as http body? conn.setUseCaches(false); conn

Easiest way to parse “querystring” formatted data

∥☆過路亽.° 提交于 2019-11-27 14:57:49
With the following code: string q = "userID=16555&gameID=60&score=4542.122&time=343114"; What would be the easiest way to parse the values, preferably without writing my own parser? I'm looking for something with the same functionality as Request.querystring["gameID"] . Chris Shain Pretty easy... Use the HttpUtility.ParseQueryString method . Untested, but this should work: var qs = "userID=16555&gameID=60&score=4542.122&time=343114"; var parsed = HttpUtility.ParseQueryString(qs); var userId = parsed["userID"]; // ^^^^^^ Should be "16555". Note this will be a string of course. You can do it