post-increment

Is ++x more efficient than x++ in Java?

Deadly 提交于 2019-12-17 12:41:50
问题 During a programming class, the professor was teaching us about x++ and ++x , with x being an integer. He said that in the scenario we are able to just put either x++ or ++x , ++x is more efficient (by little, but still, in theory, more efficient nonetheless). But I forgot why . Anyone knows? This was with Java. 回答1: It's not more efficient in Java. It can be more efficient in languages where the increment/decrement operators can be overloaded, but otherwise the performance is exactly the

Is ++x more efficient than x++ in Java?

橙三吉。 提交于 2019-12-17 12:41:00
问题 During a programming class, the professor was teaching us about x++ and ++x , with x being an integer. He said that in the scenario we are able to just put either x++ or ++x , ++x is more efficient (by little, but still, in theory, more efficient nonetheless). But I forgot why . Anyone knows? This was with Java. 回答1: It's not more efficient in Java. It can be more efficient in languages where the increment/decrement operators can be overloaded, but otherwise the performance is exactly the

Array increment operator in C

拜拜、爱过 提交于 2019-12-17 06:12:24
问题 I don't understand the results of following code: #include <stdio.h> #include <conio.h> int main() { int a[4]={1, 3, 5, 6}; //suppose a is stored at location 2010 printf("%d\n", a + 2); printf("%d", a++); return 0; } Why does the second printf function produce following error? error: lvalue required as increment operand 回答1: Part-1: Array names are constant (not modifiable lvalue), your can add value to array name but can't modify it. Expression a + 2 doesn't modify a itself but when you do a

What is more efficient, i++ or ++i? [duplicate]

狂风中的少年 提交于 2019-12-17 03:37:26
问题 This question already has answers here : Closed 10 years ago . Exact Duplicate : Is there a performance difference between i++ and ++i in C++? Exact Duplicate : Difference between i++ and ++i in a loop? What is more efficient, i++ or ++i? I have only used this in Java and C/C++, but I am really asking for all languages that this is implemented in. In college I had a professor show us that ++i was more efficient, but it has been a couple of years, and I would like to get input from the Stack

c++ spaces in operators , what are the rules

↘锁芯ラ 提交于 2019-12-13 13:52:58
问题 Does spaces have any meaning in these expressions: assume: int a = 1; int b = 2; 1) int c = a++ +b; Or, 2) int c = a+ ++b; When I run these two in visual studio, I get different results. Is that the correct behavior, and what does the spec says? In general, what should be evaluated first, post-increment or pre-increment? Edit: I should say that c =a+++b; Does not compile on visual studio. But I think it should. The postfix++ seems to be evaluated first. 回答1: Is that the correct behavior Yes,

'In any case, follow the guideline “prefer ++i over i++” and you won't go wrong.' What is the reason behind this in C?

空扰寡人 提交于 2019-12-13 09:35:18
问题 I had come across this answer to this question. In one of the line, the author mention's: In any case, follow the guideline "prefer ++i over i++ " and you won't go wrong. I know that ++i is slightly faster than i++ , but thought that there is no reason for them to go wrong. I searched for a while, and the closest I could get to was this. It explained clearly that why is it preferred to use ++i , but not still how could you go wrong using i++ . So can anyone tell me how can i++ go wrong? NOTE:

unexpected behaviour of pre and post increment in c language gcc compiler [duplicate]

时光毁灭记忆、已成空白 提交于 2019-12-13 09:17:25
问题 This question already has answers here : Why are these constructs using pre and post-increment undefined behavior? (14 answers) printf(“%d %d %d\n”,++a, a++,a) output [duplicate] (3 answers) Closed 2 years ago . If n has the value 5 then output: printf("%d %d", n++, ++n); //should be 5 and 7 But I get as output 6 and 7. 回答1: Multiple unsequenced modifications result to such kind of Undefined Behavior . There are tons of results if you search for it, e.g. this question. Next time compile with

Why does post increment operator not work although preincrement does work in this code?

谁都会走 提交于 2019-12-13 03:38:36
问题 I am really new to programming (I'm an electronics and comm. engineer) and I am not able to figure out why one program works and the other one doesn't. I'd like to get a good understanding of recursive functions before going any further with my learning. I would appreciate any help regarding this. I know the difference between the x++ and --x. But in this context of this program, I thought both of these programs should run the same way. But they don't. void rec(int x) { if(x>0) rec(x--);

I embedded a countdown timer in this code, but it didn

你离开我真会死。 提交于 2019-12-13 02:41:50
问题 package com.android.tapme; import android.os.Bundle; import android.app.Activity; import android.widget.*; import android.view.*; public class TapMe extends Activity { private int countValue=0; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_tap_me); checkTapValue(); } private void checkTapValue() { Button tapButton=(Button)findViewById(R.id.tapButton); tapButton.setOnClickListener(new View.OnClickListener() {

K&R seems to prefer pre-increment

泪湿孤枕 提交于 2019-12-12 20:06:35
问题 I'm working through K&R and am presently on Exercise 1-16. It occurs to me that thus far only pre-increment has been used in the book. Most other tutorial books and indeed source code I've seen tend to favour post-increment, except where there is an obvious affect such as in while loops etc. Is this a stylistic or technical consideration on the part of K&R? Or do I just need to be further through the book to get my answer?! 回答1: There are several aspects to this. Semantics The semantics of