pojo

问题 How would you deserialize a JSON document to a POJO using Jackson if you didn't know exactly what type of POJO to use without inspecting the message. Is there a way to register a set of POJOs with Jackson so it can select one based on the message? The scenario I'm trying to solve is receiving JSON messages over the wire and deserializing to one of several POJOs based on the content of the message. 回答1: I'm not aware of a mechanism that you are describing. I think you will have to inspect the

问题 I have used default HttpUrlConnection class to make api calls and GSON to convert Java Objects into json request and json response into equivalent Java object.I have created various models(pojo class) to convert the request/response to model objects.My doubt is that is it ideal to implement Serializable to all those models since GSON is serialization/deserialization library? public class Contact implements Serializable { private String name; private String email; public String getName() {

问题 final Map<String, Class<?>> properties = new HashMap<String, Class<?>>(); properties.put("jobName", String.class); properties.put("companyName", String.class); properties.put("totalApplicantForJob", String.class); final Class<?> beanClass = createBeanClass("ApplicantCountVsJobBoards", properties); public static Class<?> createBeanClass (final String className, final Map<String, Class<?>> properties) { final BeanGenerator beanGenerator = new BeanGenerator(); // NamingPolicy policy = /

问题 I am using both JPA and hibernate in my project. I have created a query in which i made join operation on many tables. So I created a native one. The results that i get are in a list of object[] but i would like the results to be converted automatically to a java POJO class . You can check both the query syntax and POJO java class below. JPA Query @Query(value = "SELECT obsp.Identifier, obs.phenomenontimestart, nv.value " + "From Series s " + "INNER JOIN Featureofinterest fi on s

问题 I am trying to print the current date when the template is activated. I have read that I have to pass a new Date() Java object to the template, but I don't know how to do that or where to put it in the code. Does someone know how to pass a Java object to the template in this case? Thank you !! 回答1: Actually you don't have to pass a new Date() to your template, because placing a timestamp into a template's output is quite common and therefore FreeMarker provides a special variable called .now

问题 I want to create POJO class for Kotlin, as we know that www.jsonschema2pojo.org converts JSON to POJO so we can use it with gson. Anyone know how to create Gson POJO for Kotlin QUICKLY? Edited: I know its use Data classes, but is there any simplest way to create it? 回答1: I think this should be the Plugin what you want https://github.com/wuseal/JsonToKotlinClass 回答2: Yes, I got solution for Example: { "foo": "string", "bar": "integer", "baz": "boolean" } My POJO Class Created using http://www

问题 I am using snakeYaml to parse certain configuration/property values to a Configuration object. My yaml file looks like this - #Thread batchLimit: 1000 threadCountLimit: 2 #Some More Config key: value #MAP keyMapping: <What goes here?> My Configuration class looks like this - public class Configuration{ int batchlimit; int threadCountLimit; ... Map<String,String> keyMapping; } How do I define the keyMapping in the YAML file so it reads directly through SnakeYAML? 回答1: Here is how it can look

问题 I am trying fetch data from this api: http://www.omdbapi.com/ I am using Retrofit 2 and created a pojo for first json. The thing I am curious about is how to convert my pojo to second one when data is not available. When there is data available, It returns this json: http://www.omdbapi.com/?t=Suits { Title: "Suits", Year: "2011–", Rated: "TV-14", Released: "23 Jun 2011", Runtime: "44 min", Genre: "Comedy, Drama", Director: "N/A", Writer: "Aaron Korsh", Actors: "Gabriel Macht, Patrick J. Adams

问题 This is my sample JSON: { "open":true, "total_products":100, "product":[ { "p_id":1, "price":"5.00", "name":"blah one" }, { "p_id":2, "price":"15.00", "name":"blah two" }, ... ] } This is my POJO class: @Entity(nameInDb = "products") public class ProductsPOJO { @SerializedName("open") @Property(nameInDb = "open") private boolean open; @SerializedName("total_products") @Property(nameInDb = "total_products") private Long total_products; @Convert(converter = ProductConverter.class, columnType =

问题 This question already has answers here : What is a NullPointerException, and how do I fix it? (12 answers) Closed 3 years ago . GSON throwing null pointer exception when a field is missing in json ReviewClass: public class ReviewClass { private String name; private List<Review> reviews; public String getName() { return name; } public void setName(String name) { this.name = name; } public List<Review> getReviews() { return reviews; } public void setReviews(List<Review> reviews) { this.reviews