parseexception

问题 I have timestamp string like "2015-07-13T10:44:58Z" whe I try convert this in date object it always generates the exception Caused by: java.text.ParseException: Unparseable date: "2015-07-13T10:44:58Z" Code which I am using for parsing is like that DateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"); Date subscriptionDate = format.parse("2015-07-13T10:44:58Z"); I don't know what I am doing wrong. 回答1: The patterm SSS stands for Millisecond - which means that your input

问题 After looking after several existing posts, I am still not able to get my SimpleDateFormat parser working. Here is the code: SimpleDateFormat df = new SimpleDateFormat( "EEE, dd MMM yyyy HH:mm:ss Z", Locale.US); try { volcanoListDate = df.parse(currentValue); } catch (ParseException e) { Log.d("DEBUG", e.toString()); Log.d("DEBUG", currentValue); } I always end up with a ParseException. Here is the output of the debug messages: 06-09 23:52:17.478: DEBUG/DEBUG(2436): java.text.ParseException:

问题 I am getting ParseException for the following code String dateStr = "2011-12-22 10:56:24.389362"; String formatStr = "yyyy-MM-dd HH:mm:ss.SSSSSS"; Date testDate = null; SimpleDateFormat sdf= new SimpleDateFormat(formatStr); sdf.setLenient(false); testDate = sdf.parse(dateStr); System.out.println("CHECK DATE " + sdf.format(testDate)); Exception in thread "main" java.text.ParseException: Unparseable date: "2011-12-22 10:56:24.389362" at java.text.DateFormat.parse(DateFormat.java:337) If I

问题 This question already has answers here : Converting ISO 8601-compliant String to java.util.Date (28 answers) Java - SimpleDateFormat formatter to return epoch time with milliseconds [duplicate] (6 answers) Closed last year . I have date in the format "yyyy-MM-dd'T'HH:mm:ss.sssZ". for example the date is "2018-07-17T09:59:51.312Z". I am using the below code to parse the String in Java. String date="2018-07-17T09:59:51.312Z"; SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd

问题 Here is an example: public MyDate() throws ParseException { SimpleDateFormat sdf = new SimpleDateFormat("yyyy/MM/d"); sdf.setLenient(false); String t1 = "2011/12/12aaa"; System.out.println(sdf.parse(t1)); } 2011/12/12aaa is not a valid date string. However the function prints "Mon Dec 12 00:00:00 PST 2011" and ParseException isn't thrown. Can anyone tell me how to let SimpleDateFormat treat "2011/12/12aaa" as an invalid date string and throw an exception? 回答1: The JavaDoc on parse(...) states

问题 I am trying to copy data from Excel to a SQL table. I have dates generated in Excel file using RAND function. I am taking them as strings in an input and trying to convert them in date data type using tConvertType. I have setted its datatype as 'string' in initial input and as 'date' in tConvertType's output and in tMSSqlOutput. My job has work flow Excel input -> tConvertType -> tMap -> tMSSqlOutput. While running the job I am getting an error which says : java.text.ParseException:

问题 I am storing the current date in SQLite db using the variable CURRENT_DATE. I found that the date format used is yyyy-mm-dd in the same. I want to parse the date in the code but I get this error: java.lang.IllegalArgumentException: Parse error: at java.util.Date.parseError The code is shown below: SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd"); String formattedTaskDate = dateFormat.format(new Date(dateStoredAsStringFetchedFromDB)); Date d = new Date(formattedTaskDate); At

问题 I know this question was answered somewhere else but that didn't work for me so here i am. Basically my code will login to your e-mail and send messages to multiple people. of course its not done, i know that, but it has enough code to work because i based it off one of my command line programs that does the same thing. anyways here is some code. sender class : public class Sender { public static void send(JTextArea listRecepients, JTextField textSubject, JTextArea textBody, JTextField

问题 This question already has answers here : Can I set Eclipse to ignore “Unhandled exception type” (4 answers) Closed 3 years ago . I wrote the code below with eclipse: String d = "2014-6-1 21:05:36"; SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); Date date =sdf.parse(d); System.out.print(date); and the line 4 throws an Unhandled exception type ParseException. But if I write: try { String d = "2014-6-1 21:05:36"; SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm

问题 I'm making a JavaCC program to accept a certain language. I've done this but cannot understand how to use a generated ParseException to determine the issue in the input, and customise the output error message. So far my code looks like: try { task parser = new task(System.in); parser.start(); System.out.println("YES"); // If accepted print YES. } catch (ParseException e) { System.out.println("NO"); // If rejected print NO. switch (e) { case 1: System.err.println("Some error case") case 2: ...