paginator

I have two models Users & Roles Here "Roles hasMany Users" and "Users belongsTo Roles" When the user saved we're also asking user's role & record saved. Problem : I have list of users with column firstname, lastname,roles. Each & Every column has sorting but on roles sorting is not working. Role Table contains "name" field for Role name. I have referred below link but it doesn't working for me. Pagination Sort in Cakephp 3.x UsersController: public function index() { $this->paginate = [ 'contain' => ['Roles'], 'conditions' => [ 'Users.user_type <>' => 1 ] ]; $this->set('users', $this->paginate

当在主页上看博客时，一般不会看到文章的正文，而是看一个摘要，如果没有摘要就看前面一小段，看正文则要在单独的博客页面上进行查看，因此有必要做一个链接可以链到单独博客页以进行continue reading... 适当修改index.html #/myblog/blog/templates/index.html 1 {% extends "base.html" %} 2 {% block content %} 3 <div class = "posts"> 4 {% for blog in blog_list %} 5 <section class="post"> 6 <header class="post-header"> 7 <h2 class= "post-title"><a href="{% url 'detail' id=blog.id %}">{{blog.title}}</a><h2> 8 <p class = "post-meta"> 9 Time: <a class="post-author" href="#">{{blog.date_time | date:'Y M d'}}</a>&nbsp 10 Tag: 11 {% for tag in blog.tags.all %} 12 <a class="post-category" href="#">{{tag

本单知识点： 创建表单并在视图中对其加以处理 从模型中创建表单 整合第三方应用程序Django-taggit使用tags功能 构建复杂的QuerySet 一、利用Django创建表单 Django包含两个基类可构建表单，如下所示： Form 可构建标准的表单 ModelForm 可构建与模型实例相关联的表单 1. 标准表单Form 首先 在应用程序目录中创建 forms.py 文件，代码如下： from django import forms class EmailPostForm(forms.Form): name = forms.CharField(max_length=25) email = forms.EmailField() to = forms.EmailField() comments = forms.CharField(required=False, widget=forms.Textarea) CharField 该字段类型显示为 <input type="text"> widget 为字段所使用的插件，在 comments 字段中使用了 Textarea 插件 EmailField 需要使用有效的电子邮件地址；否则，字段验证将抛出 forms.ValidationError 异常 required 表示该字段是否必填项 有效的表单字段列表请参照： 点击此处

I have a model formset that I want to display 10 forms at a time using Django's Paginator, but it can't be done like paginator = Paginator(formset, 10) . What's the correct way to do this, if there is a way? Filly This is a generic example of the solution I found to my problem: In the forms.py file: class MyForm(ModelForm): class Meta: model = MyModel fields = ('description',) In the views.py file: from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger FormSet = modelformset_factory(MyModel, form=MyForm, extra=0) if request.method == 'POST': formset = FormSet(request.POST,