os.path

After upgrade pycharm to 2018.1, and upgrade python to 3.6.5, pycharm reports "unresolved reference 'join'". The last version of pycharm doesn't show any warning for the line below: from os.path import join, expanduser May I know why? (I used python 3.6.? before) I tried almost everything I can find, such as delete and recreate interpreter, invalidate cache and restart, delete and recreate virtualenv... how do I fix this? (I can run my program without any error.) Sadly, it seems that PyCharm will try to evaluate the path to an existing file/folder, which in some cases will not exist and thus

Scenario: I am trying to read a excel file from a server folder and after that read each worksheet of that file into a dataframe and perform some operations. Issue: I have trying multiple approaches but facing different situations: either I read the file, but it is seen as a str and the operations cannot be performed, or the file is not read. What I tried so far: #first attempt os.path(r'\\X\str\Db\C\Source\selection\Date\Test','r') #second attempt directory = os.getcwd() + "\\C\\Source\\selection\\Date\\Test" #third attempt f = os.getcwd() + "\\C\\Source\\selection\\Date\\Test\\12.xlsx"

I am still very new to Python (3). I have a BUNCH of sensor data, but the download limit forces me to retrieve the data in chunks instead of all at once (each .zip file downloaded contains a folder of .csv files for each sensor's data during a given time period). Thus, I have dozens of large .csv files distributed among several folders that I would eventually like to concat/merge/append into one .csv file for each sensor's full data. To make things more complicated, .csv file names for each sensor are identical across the folders. I have developed the following code to rename and move the

os.path.sep is the character used by the operating system to separate pathname components. But when os.path.sep is used in os.path.join() , why does it truncate the path? Example: Instead of 'home/python' , os.path.join returns '/python' : >>> import os >>> os.path.join('home', os.path.sep, 'python') '/python' I know that os.path.join() inserts the directory separator implicitly. Where is os.path.sep useful? Why does it truncate the path? Where os.path.sep is usefull? I suspect that it exists mainly because a variable like this is required in the module anyway (to avoid hardcoding), and if it

I've always been sort of confused on the subject of directory traversal in Python, and have a situation I'm curious about: I have a file that I want to access in a directory essentially parallel to the one I'm currently in. Given this directory structure: \parentDirectory \subfldr1 -testfile.txt \subfldr2 -fileOpener.py I'm trying to script in fileOpener.py to get out of subfldr2, get into subfldr1, and then call an open() on testfile.txt. From browsing stackoverflow, I've seen people use os and os.path to accomplish this, but I've only found examples regarding files in subdirectories beneath