os.path

问题 i have files in folders and subfolders. folder structure is like this 2020(folder) -01(sub folder) --14(sub-sub folder) ----abc1-2020-01-14.csv ----abc2-2020-01-14.csv -02(subfolder in 2020) --17(sub-sub folder in 02) ----abc1-2020-02-17.csv ----abc4-2020-02-17.csv i have list of file names. li = ['abc1','abc2','abc3','abc4'] i want to know if these file exists in directory or not. each subdirectory should have all 4 files. if not then code must return path where particular file doesnot exist

问题 I have a directory bar inside a directory foo , with file foo_file.txt in directory foo and file bar_file.txt in directory bar ; i.e. computer$ ls foo/ computer$ ls foo/ bar/ foo_file.txt computer$ ls foo/bar/ bar_file.txt Using the python os.path.relpath function, I expect: os.path.relpath('foo/bar/bar_file.txt', 'foo/foo_file.txt') to give me: 'bar/bar_file.txt' However, it actually gives me: '../bar/bar_file.txt' Why is this? Is there an easy way to get the behavior I want? EDIT: This is

问题 I have a directory bar inside a directory foo , with file foo_file.txt in directory foo and file bar_file.txt in directory bar ; i.e. computer$ ls foo/ computer$ ls foo/ bar/ foo_file.txt computer$ ls foo/bar/ bar_file.txt Using the python os.path.relpath function, I expect: os.path.relpath('foo/bar/bar_file.txt', 'foo/foo_file.txt') to give me: 'bar/bar_file.txt' However, it actually gives me: '../bar/bar_file.txt' Why is this? Is there an easy way to get the behavior I want? EDIT: This is

问题 I wrote up a function in Python that looks for a USB drive based on a key identifier file, however when called upon it returns 'There is no disk in the drive. Please insert a disk into drive D:/' (which is an SD card reader) - is there a way to have it search drive letters based on drives that are 'ready'? def FETCH_USBPATH(): for USBPATH in ascii_uppercase: if os.path.exists('%s:\\File.ID' % USBPATH): USBPATH='%s:\\' % USBPATH print('USB is mounted to:', USBPATH) return USBPATH + "" return "

问题 I'm learning Python and would like to search for a keyword in multiple files recursively. I have an example function which should find the *.doc extension in a directory. Then, the function should open each file with that file extension and read it. If a keyword is found while reading the file, the function should identify the file path and print it. Else, if the keyword is not found, python should continue. To do that, I have defined a function which takes two arguments: def find_word

问题 I have a folder, C:\temp, with subfolders and files like below: \11182014\ VA1122F.A14 VA9999N.A14 CT3452F.B13 CT1467A.B14 \12012014\ MT4312F.B14 MT4111N.B14 CT4111F.A12 The file extensions are always an ".A" or ".B" followed by 2 digits. The file names always end with an "F", "A", or "N". I would like to loop through all subfolders in C:\temp and: prefix each file with "My_X_" where X is either an F, N, or A (i.e., the last letter in the file name) suffix each file with "_" + the name of the

问题 I am still very new to Python (3). I have a BUNCH of sensor data, but the download limit forces me to retrieve the data in chunks instead of all at once (each .zip file downloaded contains a folder of .csv files for each sensor's data during a given time period). Thus, I have dozens of large .csv files distributed among several folders that I would eventually like to concat/merge/append into one .csv file for each sensor's full data. To make things more complicated, .csv file names for each

问题 Scenario: I am trying to read a excel file from a server folder and after that read each worksheet of that file into a dataframe and perform some operations. Issue: I have trying multiple approaches but facing different situations: either I read the file, but it is seen as a str and the operations cannot be performed, or the file is not read. What I tried so far: #first attempt os.path(r'\\X\str\Db\C\Source\selection\Date\Test','r') #second attempt directory = os.getcwd() + "\\C\\Source\

问题 I've always been sort of confused on the subject of directory traversal in Python, and have a situation I'm curious about: I have a file that I want to access in a directory essentially parallel to the one I'm currently in. Given this directory structure: \parentDirectory \subfldr1 -testfile.txt \subfldr2 -fileOpener.py I'm trying to script in fileOpener.py to get out of subfldr2, get into subfldr1, and then call an open() on testfile.txt. From browsing stackoverflow, I've seen people use os

问题 I get the path dire=os.path.abspath(".") and for fileName in filter(os.path.isfile, os.listdir(path=direc)) but dire has C:\\ and sends me the next error: TypeError: listdir() takes no keyword arguments when I print dire to see the content print next: C:\\user\\documents.... what can I do to get \ and not \\ in os.path.abspath(".") ? 回答1: I'm assuming that by print you mean repr . s = 'C:\\' s >>> 'C:\\' print(s) >> C:\ Note that while printing there aren't neither double \\ nor ' The other