in-operator

The Groovy "in" operator seems to mean different things in different cases. Sometimes x in y means y.contains(x) and sometimes it seems to call y.isCase(x) . How does Groovy know which one to call? Is there a particular class or set of classes that Groovy knows about which use the .contains method? Or is the behavior triggered by the existence of a method on one of the objects? Are there any cases where the in operator gets changed into something else entirely? Dónal I did some experimentation and it looks like the in operator is based on the isCase method only as demonstrated by the following

How does SQL engines differ when we use equal sign and IN operator have same value? Does execution time changes? 1st one using equality check operator WHERE column_value = 'All' 2nd one using OR operator and single value WHERE column_value IN ('All') Does SQL engine changes IN to = if only one value is there? Is there any difference for same in MySQL and PostgreSQL? sagi There is no difference between those two statements, and the optimiser will transform the IN to the = when IN have just one element in it. Though when you have a question like this, just run both statements, run their

i am beginner in cakephp , and i want use SQL IN operator in find method , i have words table. my code is : $this->Word->find('Word.wordid in (83,82)'); , and this code create this query : SELECT `Userword`.`userwordid`, `Userword`.`userid`, `Userword`.`wordid`, `Userword`.`date`, `Userword`.`levelid` FROM `userwords` AS `Userword` WHERE `Userword`.`wordid` = (82) but i need this query SELECT `Userword`.`userwordid`, `Userword`.`userid`, `Userword`.`wordid`, Userword`.`date`, `Userword`.`levelid` FROM `userwords` AS `Userword` WHERE `Userword`.`wordid` IN (83,82) how can getting like this

We are trying to dynamically generate an IN clause for a native sql query to return a JPA entity. Hibernate is our JPA provider. Our code looks something like this. @NamedQuery( name="fooQuery", queryString="select f from Foo f where f.status in (?1)" ) .... Query q = entityManager.createNamedQuery("fooQuery"); q.setParameter(1, "('NEW','OLD')"); return q.getResultList(); This doesn't work, the in clause does not recognize any of the values passed in via this manner. Does anyone know of a solution to this problem? topchef JPA supports named list parameters, in your case: @NamedQuery( name=

For the one millionth time, I would have liked to use an IN operator in Java, similar to the IN operator in SQL. It could just be implemented as compiler syntactic sugar. So this if (value in (a, b, c)) { } else if (value in (d, e)) { } ...would really be awesome. In fact, the above is the same as the rather verbose (and not adapted for primitives) construct here: if (Arrays.asList(a, b, c).contains(value)) { } else if (Arrays.asList(d, e).contains(value)) { } Or like this for int , long and similar types: switch (value) { case a: case b: case c: // .. break; case d: case e: // .. break; } Or

In SQL, you can use the following syntax: SELECT * FROM MY_TABLE WHERE VALUE_1 IN (1, 2, 3) Is there an equivalent in C#? The IDE seems to recognise "in" as a keyword, but I don't seem to be able to find any information on it. So, is it possible to do something like the following: int myValue = 1; if (myValue in (1, 2, 3)) // Do something Instead of int myValue = 1; if (myValue == 1 || myValue == 2 || myValue == 3) // Do something If you wanted to write .In then you could create an extension that allows you to do that. static class Extensions { public static bool In<T>(this T item, params T[]