operator-keyword

Is the Is VB.NET keyword the same as Object.ReferenceEquals? Yes, it is, unless combined with a TypeOf check. Quote from MSDN: The Is operator determines if two object references refer to the same object. However, it does not perform value comparisons. If object1 and object2 both refer to the exact same object instance, result is True; if they do not, result is False. Is can also be used with the TypeOf keyword to make a TypeOf...Is expression, which tests whether an object variable is compatible with a data type. BTW, also note the IsNot operator (which gives the boolean inverse of the

F# lets you turn operators into functions by surrounding them with ( ) : for instance, (+) is of type int -> int -> int . Is it possible to do this with the list cons operator, :: ? It doesn't behave like a normal binary operator: FSI> (::);; (::);; -^^ c:\temp\stdin(3,2): error FS0010: Unexpected symbol '::' in expression. Expected ')' or other token. And the List.Cons method takes a tuple; it's not curried. (It's useful to be able to do this. For instance, you can use it to implement map in terms of fold ). Brian Paraphrased from http://cs.hubfs.net/forums/permalink/11713/11713/ShowThread

Considering the following code, I don't understand why "System.out.println( c2 instanceof D);" will result an "illegal compile time error" but not return "false"? Many thanks for your help! interface I { } class A { int x = 1;} class B extends A implements I { int y = 2;} class C extends B { } class D extends B{ } class E implements I { } C c2 = new C();` The error from Java 8 is: error: incompatible types: C cannot be converted to D And indeed, C and D are not in the same lineage (other than both being Object ). Since the compiler can tell you at compilation time that the instanceof will

Dear Java guru 's! Can you, please, explain me, why String concatenation does not work properly in Java when concatenating 2 results of ternary operators? Example: String str = null; String x = str != null ? "A" : "B" + str == null ? "C" : "D"; System.out.println(x); Output is "D", but I expected "BC". I am suspecting that it works like so because of operators priorities, but I am not sure, about how we exactly we get "D" for case above. What calculation algorithm takes place for this case? It's interpreted as following code: String x = str != null ? "A" : ("B" + str == null ? "C" : "D"); "B"

why if we have pure virtual assignment operator in a base class, then we implement that operator on the derived class, it give linker error on the base class? currently I only have the following explanation on http://support.microsoft.com/kb/130486 , it said that the behavior is by design since normal inheritance rules does not apply . it is not clear for me, why is it generate linker error by design? can someone give me more clear explanation about this? edit: added my simplified code of which the error occured: class __declspec(dllexport) BaseClass { public: int memberA; virtual BaseClass&

I'm trying to develop an Android App which shows the signal strength of various network operators on a map. The problem is that the only way to change the network operator is by doing it by hand. Any ideas on how I can get this information without changing it manually? I think that there are internal/private Android classes to do this. You will need to use one or more of Google's internal APIs to do this. They are not, by default, available to Android applications for various (usually good) reasons. The API for turning tethering on and off and configuring it, for example, is not a public API