operator-keyword

I am trying to find the greatest common factor. I wrote a bad (operation intensive) algorithm that decrements the lower value by one, checks using % to see if it evenly divides both the numerator and denominator, if it does then it exits the program. However, my while loop is not using the and operator, and thus once the numerator is divisible it stops, even though its not the correct answer. The numbers I am using are 54 and 42, the correct GCD (greatest common denominator) is 6. #heres a simple algorithm to find the greatest common denominator: iterations = 0; #used to calculate number of

In C#, what's the difference between A::B and A.B ? The only difference I've noticed is that only :: can be used with global , but other than that, what's the difference? Why do they both exist? with :: you can do things like... extern alias X; extern alias Y; class Test { X::N.A a; X::N.B b1; Y::N.B b2; Y::N.C c; } and there are times when . is ambiguous so :: is needed. here's the example from the C# language spec namespace N { public class A {} public class B {} } namespace N { using A = System.IO; class X { A.Stream s1; // Error, A is ambiguous A::Stream s2; // Ok } } http://download

Will the differences below matter significantly in C#? int a, b; double result; result = (double)a / b; result = a / (double)b; result = (double)a / (double)b; Which one do you use? The cast will occur before the division. In your examples, it doesn't matter which one you do as if one operand is a double, the runtime will cast/convert the other to a double as well. This looks like a micro-optimization - not something worth worrying about or dealing with unless measurements show it is indeed a bottleneck. I do this: result = (double)a / (double)b; It may be strictly unnecessary, but generally I

I know new and delete are keywords. int obj = new int; delete obj; int* arr = new int[1024]; delete[] arr; <new> header is a part of C++ standard headers. It has two operators (I am not sure they are operators or they are functions): ::operator new ::operator delete these operators used like below: #include <new> using namespace std; int* buff = (int*)::operator new(1024 * sizeof(int)); ::operator delete(buff); What are "::operator new" and "::operator delete"? Are they different from new and delete keywords? Alok Save :: tells the compiler to call the operators defined in global namespace. It

The example below defines a basic podtype container class. Using this class a series of typedefs are then created which represent an OOP version of the basic podtype. The problem originates when we start assigning those types to one another. I tried to define the operator as friend method with lhs and rhs arguments using plain PodObjects as type but without any succes. Is there anyone who might have experienced something simular or knows an other solution for this problem. Thanks in advance. #include <stdint.h> template <typename T> class PodObject { protected: T _value; public: PodObject<T>

Does declaration in c# allocate memory for the variable to be created or is it the new operator that allocates memory and enables to invoke the constructor to initialize the allocated variable in memory? To my understanding, you cannot call an constructor of any type without the new operator. Am I correct? Does declaration in c# allocate memory for the variable to be created or is it the new operator that allocates memory and enables to invoke the instructor to initialize the allocated variable in memory? First let's make sure that you're asking the question you think you're asking. For a

I had a tiny class:- class A{ public:int aField; } Below, while debugging, if I hover mouse around aField in a->aField , Visual Studio will pop up the value of the field nicely (like a tiny Watch). A* a=new A(); a->aField=1234; //^ hover here Then I upgraded code to override operator-> :- class APtr{ //my custom smart pointer A* ptr; A* operator->(){ return ptr; } } APtr a; ..... a->aField=1234; //^ hover here There is no pop up anymore. (There is a popup for a , but not for aField ) How to make the cute popup appear again? Edit (Bounty reason): "user1610015" has provided a doable solution,