object-reference

C++ object referencing in classes

喜夏-厌秋 提交于 2019-12-06 16:01:07
I am wondering how to store a reference of an object inside of another object, and also set that reference as a private property. Example (pseudo-code): class foo { public: int size; foo( int ); }; foo::foo( int s ) : size( s ) {} class bar { public: bar( foo& ); private: foo fooreference; }; bar::bar( foo & reference ) { fooreference = reference; } foo firstclass( 1 ); bar secondclass( firstclass ); As you may be able to see, I just want to be able to store the reference of foo inside this bar class. I know how to simply bring it into a method and use it just in the scope of that method, but

How to determine whether object reference is null?

被刻印的时光 ゝ 提交于 2019-12-04 23:39:09
What is the best way to determine whether an object reference variable is null ? Is it the following? MyObject myObjVar = null; if (myObjVar == null) { // do stuff } Yes, you are right, the following snippet is the way to go if you want to execute arbitrary code: MyObject myObjVar; if (myObjVar == null) { // do stuff } BTW: Your code wouldn't compile the way it is now, because myObjVar is accessed before it is being initialized. The way you are doing is the best way if (myObjVar == null) { // do stuff } but you can use null-coalescing operator ?? to check, as well as assign something var obj =

Swift class-property update

♀尐吖头ヾ 提交于 2019-12-04 07:09:42
问题 So I have to pass instance of my custom class from one UIViewController to another: targetVC.reservation = self.reservation! print(self.reservation!.id, "before") targetVC.reservation!.phoneNumber = self.phoneTextField.text!.phoneToString() targetVC.reservation!.id = id print(self.reservation!.id, "after") My problem is that self.reservation!.id is also changed: " before " it is "" , and " after " it is id . Why does it happen and how to avoid this? 回答1: You can use mutableCopy() with your

how are C# object references represented in memory / at runtime (in the CLR)?

落花浮王杯 提交于 2019-12-03 05:53:35
I'm curious to know how C# object references are represented in memory at runtime (in the .NET CLR). Some questions that come to mind are: How much memory does an object reference occupy? Does it differ when defined in the scope of a class vs the scope of a method? Does where it live differ based on this scope (stack vs heap)? What is the actual data maintained within an object reference? Is it simply a memory address that points to the object it refers to or is there more to it? Does this differ based on whether it is defined within the scope of a class or method? Same questions as above, but

object reference is same in function calling

丶灬走出姿态 提交于 2019-12-02 14:58:14
问题 -(UserDetail *)functionCheck :(NSString *)str { UserDetail *d2=[[UserDetail alloc] init]; NSLog(@"check address::::::> %p",&d2); d2.auth_token=str; return d2; } whenever i am calling functionCheck() function print same address check address::::::> 0xbfffd500 means it allocate same address. how to deallocate UserDetail d2 object after return. 回答1: d2 is a pointer to the allocated object, so what you want is to log the value of d2 , not its address &d2 : NSLog(@"check address::::::> %p", d2); /

object reference is same in function calling

瘦欲@ 提交于 2019-12-02 11:58:02
-(UserDetail *)functionCheck :(NSString *)str { UserDetail *d2=[[UserDetail alloc] init]; NSLog(@"check address::::::> %p",&d2); d2.auth_token=str; return d2; } whenever i am calling functionCheck() function print same address check address::::::> 0xbfffd500 means it allocate same address. how to deallocate UserDetail d2 object after return. d2 is a pointer to the allocated object, so what you want is to log the value of d2 , not its address &d2 : NSLog(@"check address::::::> %p", d2); // remove the & ! ( &d2 is the address of the local stack variable, and that may be the same for each call.)

.NET Binary Serialize object with references to other objects . . . what happens?

六月ゝ 毕业季﹏ 提交于 2019-12-01 23:49:43
问题 If you have an object instance A that references other objects (for example instances B and C), and you binary serialize A to a file, what happens? Do you now have serialized data that includes A, B and C? How does it work exactly? What will I get if I deserialize the data? A, B, and C?? (Feel free to include internal workings explanations as well). 回答1: All of the references to other objects will be serialized as well. If you deserialize the data, you will end up with a complete, working set

Does Javascript equal sign reference objects or clones them?

隐身守侯 提交于 2019-12-01 10:43:48
In MyApp.something.BigObject I have a memory expensive object and I like to do this var theObject = MyApp.something.BigObject; . My question is would that take up double the memory or not? The "equals sign" is the assignment operator. If the RHS is an object, then a reference is assigned to the LHS, it does not clone or copy the object. So given: var obj = {}; var b = obj; both obj and b reference the same object. 来源: https://stackoverflow.com/questions/7467335/does-javascript-equal-sign-reference-objects-or-clones-them

Does Javascript equal sign reference objects or clones them?

 ̄綄美尐妖づ 提交于 2019-12-01 09:18:00
问题 In MyApp.something.BigObject I have a memory expensive object and I like to do this var theObject = MyApp.something.BigObject; . My question is would that take up double the memory or not? 回答1: The "equals sign" is the assignment operator. If the RHS is an object, then a reference is assigned to the LHS, it does not clone or copy the object. So given: var obj = {}; var b = obj; both obj and b reference the same object. 来源: https://stackoverflow.com/questions/7467335/does-javascript-equal-sign

How Java String pool works when String concatenation?

北战南征 提交于 2019-11-30 16:34:20
Beware: I'm not trying to compare if the characters are equals. Because I know how to use the String.equals() method. This question is about String reference I was studying for the OCA exam when I started to learn about the class String and it properties as immutability, etc. According to what I read or may understand about String pool is that when a string is created Java stores this object on what they call String pool and if a new string is created with the same value it is going to make reference to the string on the String pool except is the case we use the new keyword as this creates a