object-comparison

How can I do a shallow comparison of the properties of two objects with Javascript or lodash?

蓝咒 提交于 2020-03-18 10:30:08
问题 Is there a way I can do a shallow comparison that will not go down and compare the contents of objects inside of objects in Javascript or lodash? Note that I did check lodash, but it appears to perform a deep comparison which I don't want to do. var a = { x: 1, y: 2} var b = { x: 1, y: 3} Is there some way for example to compare a and b ? 回答1: function areEqualShallow(a, b) { for(var key in a) { if(!(key in b) || a[key] !== b[key]) { return false; } } for(var key in b) { if(!(key in a) || a

Javascript: Deep Comparison

丶灬走出姿态 提交于 2020-01-11 08:43:08
问题 I was checking this question Javascript Deep Comparison The solution of the question asker did not convince me so I tried to analyze the problem and came up with that var obj = {here: 2}; console.log(deepEqual(obj, obj)); // → true console.log(deepEqual(obj, {here: 1})); // → false console.log(deepEqual(obj, {here: 2})); // → true function deepEqual(a,b) { if( (typeof a == 'object' && a != null) && (typeof b == 'object' && b != null) ) { var count = [0,0]; for( var key in a) count[0]++; for(

How can I write custom comparison (definition for binary operator Equal) for entityframework object to an int?

蹲街弑〆低调 提交于 2020-01-06 08:32:26
问题 I'm getting this error: ex = {"The binary operator Equal is not defined for the types 'MySite.Domain.DomainModel.EntityFramework.NickName' and 'System.Int32'."} What I tried to do was do a select all where the NickNameId = someIntPassedIn ... the problem is that the NickNameId is a foreign key, so when it compares the someIntPassedIn to the NickNameId it pulls the whole NickName object that the NickNameId refers to and tries to compare the int to that object. I need a solution here to allow

Python pickle: pickled objects are not equal to source objects

浪子不回头ぞ 提交于 2020-01-05 10:16:31
问题 I think this is expected behaviour but want to check and maybe find out why, as the research I have done has come up blank I have a function that pulls data, creates a new instance of my custom class, then appends it to a list. The class just contains variables. I then pickle that list to a file using protocol 2 as binary, later I re-run the script, re-pull the data from my source, I have a new list with my custom class instances, for testing I keep the data the source data the same. Reload

Python: Why does (“hello” is “hello”) evaluate as True? [duplicate]

拈花ヽ惹草 提交于 2019-12-27 17:29:37
问题 This question already has answers here : About the changing id of an immutable string (5 answers) Closed last year . Why does "hello" is "hello" produce True in Python? I read the following here: If two string literals are equal, they have been put to same memory location. A string is an immutable entity. No harm can be done. So there is one and only one place in memory for every Python string? Sounds pretty strange. What's going on here? 回答1: Python (like Java, C, C++, .NET) uses string

Does the equals method work with objects? If so, how?

冷暖自知 提交于 2019-12-19 07:39:06
问题 I have a program that is zoo and in the zoo there are branched subgroups of animals that are reptiles. When I do an equals method the main program compiles and it runs. I'm confused how does java know to use the equals method if I'm comparing objects and not specifically int or String? public class Zoo { public static void main(String[]args) { Animal a=new Animal("Bob"); Reptile komodo= new Reptile("Snakey"); komodo.bask(); a.size=3; komodo.size=5; System.out.println(a); System.out.println

Proper way to write GetHashCode() when Equality Comparer is based on OR operation?

可紊 提交于 2019-12-11 07:39:14
问题 I'm trying to write an Equality Comparer for a simple class with 3 fields, like so: public class NumberClass { public int A { get; set; } public int B { get; set; } public int C { get; set; } } My condition for two objects of NumberClass to be equal is if Obj1.A == Obj2.A || Obj1.B == Obj2.B (in other words, OR), Obj1 and Obj2 being instances of NumberClass . I can easily write the Equals() of my comparer as follows, but I don't know what to do with my GetHashCode() method. public bool Equals

Checking object equality in Jasmine

家住魔仙堡 提交于 2019-12-03 07:20:50
问题 Jasmine has built-in matchers toBe and toEqual . If I have an object like this: function Money(amount, currency){ this.amount = amount; this.currency = currency; this.sum = function (money){ return new Money(200, "USD"); } } and try to compare new Money(200, "USD") and the result of sum, these built-in matchers will not work as expected. I have managed to implement a work-around based on a custom equals method and custom matcher, but it just seems to much work. What is the standard way to

Checking object equality in Jasmine

三世轮回 提交于 2019-12-02 19:53:25
Jasmine has built-in matchers toBe and toEqual . If I have an object like this: function Money(amount, currency){ this.amount = amount; this.currency = currency; this.sum = function (money){ return new Money(200, "USD"); } } and try to compare new Money(200, "USD") and the result of sum, these built-in matchers will not work as expected. I have managed to implement a work-around based on a custom equals method and custom matcher, but it just seems to much work. What is the standard way to compare objects in Jasmine? lukas.pukenis I was looking for the same thing and found an existing way to do

Javascript: Deep Comparison

本小妞迷上赌 提交于 2019-12-01 17:23:40
I was checking this question Javascript Deep Comparison The solution of the question asker did not convince me so I tried to analyze the problem and came up with that var obj = {here: 2}; console.log(deepEqual(obj, obj)); // → true console.log(deepEqual(obj, {here: 1})); // → false console.log(deepEqual(obj, {here: 2})); // → true function deepEqual(a,b) { if( (typeof a == 'object' && a != null) && (typeof b == 'object' && b != null) ) { var count = [0,0]; for( var key in a) count[0]++; for( var key in b) count[1]++; if( count[0]-count[1] != 0) {console.log('1');return false;} for( var key in