objdump

问题 I have made the following dummy code for testing /tmp/test.c contains the following: #include "test.h" #include <stdio.h> #include <stdlib.h> struct s* p; unsigned char *c; void main(int argc, char ** argv) { memset(c, 0, 10); p->a = 10; p->b = 20; } /tmp/test.h contains the following: struct s { int a; int b; }; I compile and run objdump as follows: cd /tmp gcc -c test.c -o test.o objdump -gdsMIntel test.o I get the following output: test.o: file format elf32-i386 Contents of section .text:

问题 I have made the following dummy code for testing /tmp/test.c contains the following: #include "test.h" #include <stdio.h> #include <stdlib.h> struct s* p; unsigned char *c; void main(int argc, char ** argv) { memset(c, 0, 10); p->a = 10; p->b = 20; } /tmp/test.h contains the following: struct s { int a; int b; }; I compile and run objdump as follows: cd /tmp gcc -c test.c -o test.o objdump -gdsMIntel test.o I get the following output: test.o: file format elf32-i386 Contents of section .text:

问题 Is there a way to get the full address in objdump? Command being used is: objdump -d progname The leading zeros are the incorrect. The addresses should be as follows: The last three values in the address are correct; but, I'd much like the full address to be shown in objdump. 回答1: Before your application gets loaded, you cannot tell where it will end in the memory. Try the following code: #include <stdio.h> int main() { printf("%p\n", main); } Compile it with gcc test.c and run several times.

问题 I get the following output when I disassembled a simple ARM binary file using the command "arm-linux-gnueabihf-objdump -d a.out" 00008480 <_start>: 8480: f04f 0b00 mov.w fp, #0 8484: f04f 0e00 mov.w lr, #0 8488: bc02 pop {r1} 848a: 466a mov r2, sp What do different columns represent here? For example, 8480 and f04f 0b00 (from the 2nd line of code) 回答1: The first column is the address of the code in memory. 0x8480 means the memory address of this piece of code is 0x8480 . The second column is

问题 I get the following output when I disassembled a simple ARM binary file using the command "arm-linux-gnueabihf-objdump -d a.out" 00008480 <_start>: 8480: f04f 0b00 mov.w fp, #0 8484: f04f 0e00 mov.w lr, #0 8488: bc02 pop {r1} 848a: 466a mov r2, sp What do different columns represent here? For example, 8480 and f04f 0b00 (from the 2nd line of code) 回答1: The first column is the address of the code in memory. 0x8480 means the memory address of this piece of code is 0x8480 . The second column is

问题 I get the following output when I disassembled a simple ARM binary file using the command "arm-linux-gnueabihf-objdump -d a.out" 00008480 <_start>: 8480: f04f 0b00 mov.w fp, #0 8484: f04f 0e00 mov.w lr, #0 8488: bc02 pop {r1} 848a: 466a mov r2, sp What do different columns represent here? For example, 8480 and f04f 0b00 (from the 2nd line of code) 回答1: The first column is the address of the code in memory. 0x8480 means the memory address of this piece of code is 0x8480 . The second column is

问题 Hello i run the pin toll itrace.cpp file to get the trace of the code. #include <stdio.h> #include "pin.H" FILE * trace; // This function is called before every instruction is executed // and prints the IP VOID printip(VOID *ip) { fprintf(trace, "%p\n", ip); } // Pin calls this function every time a new instruction is encountered VOID Instruction(INS ins, VOID *v) { // Insert a call to printip before every instruction, and pass it the IP INS_InsertCall(ins, IPOINT_BEFORE, (AFUNPTR)printip,

问题 I'm trying to create a dispatch table which changes the location of some instruction in another address which is allocated by AllocateMemoryOnRemoteProcess . One of the problems that I encountered was almost all of Calls and all kind of Jumps are near and relative and as long as I load the assemblies in new location, then these instructions won't work. As I know I should convert these instructions to far jump or far call one of the solutions that I saw during my googling was using push and

问题 I'm trying to create a dispatch table which changes the location of some instruction in another address which is allocated by AllocateMemoryOnRemoteProcess . One of the problems that I encountered was almost all of Calls and all kind of Jumps are near and relative and as long as I load the assemblies in new location, then these instructions won't work. As I know I should convert these instructions to far jump or far call one of the solutions that I saw during my googling was using push and

问题 I am writing a C program thats shows instructions using ptrace. This is the code: #include<stdio.h> #include <stdint.h> #include <stdlib.h> #include <unistd.h> #include <sys/wait.h> #include <sys/ptrace.h> #include <sys/user.h> #include <sys/types.h> #include <sys/syscall.h> #include <string.h> void run_target() { ptrace(PTRACE_TRACEME, 0, 0, 0); execl("./test", "test", NULL); } void debugger(pid_t pid) { int status; wait(&status); while(WIFSTOPPED(status)) { struct user_regs_struct regs;