numberformatexception

How to avoid Number Format Exception in java? [duplicate]

删除回忆录丶 提交于 2019-12-17 16:00:51
问题 This question already has answers here : What is a NumberFormatException and how can I fix it? [duplicate] (9 answers) Closed 3 years ago . In my day to day web application development there are many instances where we need to take some number inputs from the user. Then pass on this number input to may be service or DAO layer of the application. At some stage since its a number (integer or float), we need to convert it into Integer as shown in the following code snippet. String cost = request

How i convert String to int? [duplicate]

徘徊边缘 提交于 2019-12-13 23:24:24
问题 This question already has answers here : Java: getMinutes and getHours (12 answers) How can I prevent java.lang.NumberFormatException: For input string: “N/A”? [closed] (5 answers) Closed last year . Here's Code, I am trying to convert Minutes which is String type, to integer type but I am having NumberFormatException error, can anyone help me, how i handle this situation. Thanks. import java.util.Date; class DateDemo { public static void main(String args[]) { // Instantiate a Date object

Number format exception for large inputs

拟墨画扇 提交于 2019-12-13 18:08:06
问题 This code works fine for some inputs. but I get a NumberFormatError for higher values of inputs such as 1000000. The input (taken for s[]) ranges from values 1-2000000 What could be the reason? import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { public static void main(String[] args) { /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */ try { BufferedReader

unable to convert string to integer using parseInt() [duplicate]

无人久伴 提交于 2019-12-13 10:52:49
问题 This question already has answers here : What is a NumberFormatException and how can I fix it? [duplicate] (9 answers) Closed 3 years ago . As a beginner I know that Integer.parseInt() is used to convert strings to integers but here I tried a program but its not working Public static void main(String args[]) { Scanner sr=new Scanner(System.in); String s=sr.nextLine(); int i=Integer.parseInt(s); System.out.println(i); } I want to take a line as input and convert it into integers and print but

Invalid Double. Number format exception in android

柔情痞子 提交于 2019-12-13 09:22:09
问题 I have this in xml. <EditText android:id="@+id/creditlimitfield2" android:hint="0" android:inputType="numberDecimal" /> So, the default value for edittext is 0. in code, I have this creditlimit = (EditText) findViewById(R.id.creditlimitfield2); double credit_limit = Double.valueOf(creditlimit.getText().toString()); Alternately, I have tried: double credit_limit = Double.parseDouble(creditlimit.getText().toString()); And double credit_limit = new Double(creditlimit.getText().toString()); When

NumberFormatException with Integer.parseInt() [duplicate]

﹥>﹥吖頭↗ 提交于 2019-12-13 07:46:59
问题 This question already has answers here : What is a NumberFormatException and how can I fix it? [duplicate] (9 answers) Closed 3 years ago . I've a problem with Integer.parseInt(). Specifically my code do this: serverPort variable is an int correctly initialized to 1910 byte[] multicastMessage = (serverAddress+"::"+String.valueOf(serverPort)).getBytes(); byte[] receivedBytes = receivePacket.getData(); receivedString = new String(receivedBytes, "UTF-8"); String[] decodedString = receivedString

java.lang.NumberFormatException while reading from a file

[亡魂溺海] 提交于 2019-12-13 07:36:03
问题 I'm trying to create a basic program, it reads a file of unknown number of numbers arranged in a matrix, creates a list of arrays in String format to read it and then parses that to int for multiple other processes. I'm getting a java.lang.NumberFormatException when parsing, I know its probably because of a blank value getting parsed to an int. I have looked at other questions but can't seem to get it fixed. Here's part of the code: public static void main(String[] args) { try { br = new

Error parsing Colors from String

最后都变了- 提交于 2019-12-12 11:13:22
问题 EDIT:A Pastebin consisting of the relevant parts of my project: Here is the updated code Also ColouredItem is a wrapper for: public class ColouredItem {//Only a wrapper class,no behaviour has been defined here String name,colour; } I get a NumberFormatException when trying to parse a colour from a String using the following code: row.setBackgroundColor(Color.parseColor(item.colour)); I use the following to create a list of items from a resource: for(int i=0;i<list.length;i++) { item=new

Encountering NumberFormatException

本小妞迷上赌 提交于 2019-12-12 04:59:35
问题 I am trying to convert a string to a double but get a NumberFormatException. Here is my code: String x = ""; // String ary[]=new String[10]; while (finalstr.charAt(stpr) != ' ') { // System.out.print(finalstr.charAt(stpr)); Character c = new Character(finalstr.charAt(stpr)); String s = c.toString(c); ary[i] = s; x = x + ary[i]; i++; stpr++; // first++; } // System.out.print(x); String yo = x; // System.out.print(yo); //it prints well // double d = Double.valueOf(yo.trim()).doubleValue();

NumberFormatException in Java for a string that is a number

前提是你 提交于 2019-12-12 04:49:07
问题 I am implementing socket programming using Java. I get this error. My code is: public class UDPServer { public static void main(String[] args) throws Exception { byte[] data = new byte[1024]; byte[] sendData = new byte[1024]; byte[] num1b = new byte[1024]; String num1String; DatagramPacket recievePacket; String sndmsg; int port; DatagramSocket serverSocket = new DatagramSocket(9676); System.out.println("UDP Server running"); byte[] buffer = new byte[65536]; while(true) { recievePacket = new