null-terminated

问题 I have a char array buffer that I am using to store characters that the user will input one by one. My code below works but has a few glitches that I can't figure out: when I execute a printf to see what's in Buffer, it does fill up but I get garbage characters at the end it won't stop at 8 characters despite being declared as char Buffer[8]; Can somebody please explain to me what is going on and perhaps how I could fix this? Thanks. char Buffer[8]; //holds the byte stream int i=0; if (/*

问题 I need to read zero-terminated strings from InputStream in Java. Is there similar to BufferedReader.readLine() method for reading zero-terminated strings? 回答1: No. Java doesn't recognise a zero-terminated string as such. You'll have to read the InputStream and look for a 0 byte. Note that this doesn't address the issue of character-encoding. The InputStream will give you the stream of bytes, and you'll then have to encode to characters via a Reader . If you have a multi-byte character

问题 Consider the following code: const char foo[] = "lorem ipsum"; // foo is an array of 12 characters const auto length = strlen(foo); // length is 11 string bar(length, '\0'); // bar was constructed with string(11, '\0') strncpy(data(bar), foo, length); cout << data(bar) << endl; My understanding is that string s are always allocated with a hidden null element. If this is the case then bar really allocates 12 characters, with the 12 th being a hidden '\0' and this is perfectly safe... If I'm

问题 I am using swift socket library with the following code: let client:TCPClient = TCPClient(addr: "127.0.0.1", port: 8080) var (success,errmsg)=client.connect(timeout: 1) if success{ var (success,errmsg)=client.send(str:"|~\0" ) if success{ let data=client.read(1024*10) if let d=data{ if let str=String(bytes: d, encoding: NSUTF8StringEncoding){ print(str) } } }else{ print(errmsg) } }else{ print(errmsg) } The code works great but my problem is that my server gets the data without null-terminator

问题 sgetn Takes a char* for it's first argument and writes characters to it. It does not write a trailing '\0' to the char* . This behavior seems to be inconsistent with every other time that I can find a char* written to. However, it is consistent across Clang, gcc, and Visual Studio, so I can't believe it's a bug that all the compilers have. Is there a reason that the standard doesn't require the trailing '\0' to the char* ? [Live Example] 回答1: Because it can be used to read arbitrary data, not

问题 I've been reading C++ for dummies lately and either the title is a misnomer or they didn't count on me. On a section about utilizing arrays of pointers with characters strings they show a function on which I've been completely stumped and don't know where to turn. char* int2month(int nMonth) { //check to see if value is in rang if ((nMonth < 0) || (nMonth > 12)) return "invalid"; //nMonth is valid - return the name of the month char* pszMonths[] = {"invalid", "January", "February", "March",

问题 How to replace \0 (NUL) in the String? String b = "2012yyyy06mm"; // sth what i want String c = "2\0\0\0012yyyy06mm"; String d = c.replaceAll("\\\\0", ""); // not work String e = d.replace("\0", ""); // er, the same System.out.println(c+"\n"+d+"\n"+e); String bb = "2012yyyy06mm"; System.out.println(b.length() + " > " +bb.length()); The above code will print 12 > 11 in console. Oops, What happened? String e = c.replace("\0", ""); System.out.println(e); // just print 2(a bad character)2yyyy06mm

问题 The function char* strrchr(const char *str, int ch) returns a pointer ( char* ) within str ( const char * ) where the last occurrence of ch is located. So we can write the following code without any cast: #include <string.h> int main() { const char CONSTSTR[] = "foo/bar/foobar.txt"; char *ptr = strrchr (CONSTSTR, '/'); *ptr++ = 'B'; *ptr++ = 'A'; *ptr++ = 'D'; } What is the advantage to return char* instead of const char* ? EDIT: As a Shafik Yaghmour pointed out, there are very good answers

问题 I'm trying to print some strings using printf() but they are null terminated having trailing newline and that messes with the formating: printf("The string \"%s\" was written onto the file \"%s\"", str, fname); Say the string contains "The Racing car." and the file name is "RandomText1.txt" This prints: The string "The Racing car. " was written onto the file "RandomText1.txt " However I want it to print in just one line: The string "The Racing car." was written onto the file "RandomText1.txt"

问题 I'm working with libxml2's sax parser to read large xml files. Most callback handlers are provided a NULL terminated char pointer. Using String.fromCString these can be converted to a regular string in Swift. However sax uses a buffer for reading the bytes, so one of the callbacks ( characters ) might be called with part of a string, namely the size of the buffer. This partial string might even start/end halfway a Unicode code point. The callback will be called multi times, until the complete