nsinteger

Possible Duplicates: When to use NSInteger vs int? Why is there is an NSInteger? Can we use int and NSInteger interchangably? Is there any specific situation to use NSInteger only, instead of using int ? Can we use int and NSInteger interchangably? No. On the LP64 architecture used by Apple, for modern OS X Cocoa, NSInteger is 64 bits wide. This means that if you cast an NSInteger to an int, comparisons against NSNotFound may fail. Here's an example: NSRange theRange = [@"foo" rangeOfString @"x"]; int location = theRange.location; if (location == NSNotFound) // comparison is broken due to

I am trying to convert a NSInteger to a NSUInteger and I googled it and found no real answer. How would I do this? NSInteger and NSUInteger are just typedefs for primitive integer types: #if __LP64__ || NS_BUILD_32_LIKE_64 typedef long NSInteger; typedef unsigned long NSUInteger; #else typedef int NSInteger; typedef unsigned int NSUInteger; #endif As such, you don't need to "convert" between them. A simple cast should be sufficient. Like: NSInteger myInt = 0; NSUInteger unsignedInt = (NSUInteger)myInt; Since this might be useful for other coming across this issue here is a little table showing

Possible Duplicate: How to convert An NSInteger to an int? I am new to iOS programming, how do I convert int to NSInteger. I have found references on how to convert NSInteger to NSNumber but I wasn't able to figure it out. Any help would be appreciated. Thanks. Aleksejs Mjaliks An improved answer On 64-bit systems NSInteger is long . On 32-bit systems NSInteger is int . https://developer.apple.com/library/content/documentation/Cocoa/Conceptual/Cocoa64BitGuide/64BitChangesCocoa/64BitChangesCocoa.html All you need just cast your int to NSInteger . int i = 1; NSInteger nsi = (NSInteger) i; You

I wonder if someone can explain something, I setup a loop where I wanted to count backwards from 10 to 0 : for(NSUInteger index = 10; index >= 0; index--) { NSLog(@"INDEX: %ld", (long)index); } This loop runs forever, it does not stop at 0, but keeps going into negative numbers. When I noticed this I changed my code to : for(NSInteger index = 10; index >= 0; index--) { NSLog(@"INDEX: %ld", (long)index); } The above works fine, but I am curious, why the first example does not work as the numbers generated are all unsigned integers? An unsigned type can't "keep going into negative numbers".

How can i get the last digit of an integer (or NSInteger) outputted to integer? example: int time = CFAbsoluteGetCurrent(); int lastDigit; Use modulo : int lastDigit = time % 10; 来源： https://stackoverflow.com/questions/4559654/c-objective-c-read-and-get-last-digit-of-integer

What is the main difference between int , NSInteger and NSUInteger in Objective-C? Which one is better to use in an application and why? In such cases you might right click and go to definition: #if __LP64__ || (TARGET_OS_EMBEDDED && !TARGET_OS_IPHONE) || TARGET_OS_WIN32 || NS_BUILD_32_LIKE_64 typedef long NSInteger; typedef unsigned long NSUInteger; #else typedef int NSInteger; typedef unsigned int NSUInteger; #endif zaph The difference is for abstract types and their associates sized from hardware. In a manner that now we don't have to worry about what size an int is or how big it's pointer

UITextField *textField; NSInteger intRollNumber; I want to take rollNumber as input from the textField and store the value into intRollNumber . How i do that? Because I am unable to convert the string into integer. dermdaly Like this? NSString *str = [textField text] int RollNumber = [str intValue]; See the text property and integerValue . 来源： https://stackoverflow.com/questions/886925/retrieving-integer-value-from-the-uitextfield-into-a-nsinteger-variable