non-static

问题 Is it possible to create non-static template field in a class? If no, how to workaround? Such fields should be created at compile time as needed. Example I have a lot of B -class, like B1 , B2 , B3 . (In real case, they have more meaningful names.) I want to create a class D that has non-static template function add<BX>() that have to counter++ every time I call it, for each individual BX , for a certain instance of D. (In real case, it does somethings more complex.) Here is a working demo to

问题 I am trying to mock an inner method call of my test method My class looks like this public class App { public Student getStudent() { MyDAO dao = new MyDAO(); return dao.getStudentDetails();//getStudentDetails is a public //non-static method in the DAO class } When I write the junit for the method getStudent(), is there a way in PowerMock to mock the line dao.getStudentDetails(); or make the App class use a mock dao object during junit execution instead of the actual dao call which connects to

问题 I have 2 classes both non-static. I need to access a method on one class to return an object for processing. But since both classes is non-static, I cant just call the method in a static manner. Neither can I call the method in a non-static way because the program doesnt know the identifier of the object. Before anything, if possible, i would wish both objects to remain non-static if possible. Otherwise it would require much restructuring of the rest of the code. Heres the example in code

问题 io_iterator_t enumerator; kern_return_t result; result = IOServiceAddMatchingNotification( mNotifyPort, kIOMatchedNotification, IOServiceMatching( "IOFireWireLocalNode" ), serviceMatchingCallback, (void *)0x1234, & enumerator ); serviceMatchingCallback((void *)0x1234, enumerator); if i declare serviceMatchinCallback as static then it works, but i do not want it to be static. Is there a way to pass it a non-static callback function? Thank you 回答1: You could keep it static, but use the userdata

问题 I've recently started working with C++ and I have stumbled across a problem that I cannot seem to understand. class MyClass { bool eventActive = false; static bool JoinCommand() { if (eventActive == true) // eventActive error: "a nonstatic member reference must be relative to a specific object" { // do something here... } else { } }; I need JoinCommand to be static but I also need to use eventActive which is required to be non-static and is used/modified by other functions in the same class.

问题 I'm just starting on Java and I need some help. I know I cannot make a non-static reference on a static method but I need help trying to work around it. I was reading you can access non-static member variables, by creating an instance of the object but I'm not sure exactly how to do it. Here is some on the code. Any help or directions would be reallya appreciated. package tweetClassification; public class PriorityRules { public static void prioritize( final String userInput ){

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 8 years ago . I'm just trying to see if I can fully understand the concept of static and the reason of static in a main class. The keyword static refers to the main class. the reason why methods in a main class are static is

问题 Doing Java course, at UNI atm, and I'm having a bit of trouble with a dice-problem. I have the following: public class Die { public int eyes; private java.util.Random r; private int n; public Die (int n) { r = new Random(); this.n = n; } public void roll() { eyes = r.nextInt(Die.n); } When compiling I get: non-static variable n cannot be referenced from a static context. How would I go about fixing this, whilst having it randomize from a user given value? 回答1: n is not a static variable, so

问题 The error comes from this line BoardState addme = new BoardState(); For some reason the non-static variable that it is pointing at is "new". I am unclear of how I can fix this error as new is not meant to be a variable, and is not. Looking through the stackoverflow records this error usually comes from a non-static method which is usually solved by making the method static or bypassing the method entirely. T This code below is to reference what is going on before and after this statement.

问题 I have recently done an update to PHP 5.4, and I get an error about static and non-static code. This is the error: PHP Strict Standards: Non-static method VTimer::get() should not be called statically in /home/jaco/public_html/include/function_smarty.php on line 371 This is the line 371: $timer = VTimer::get($options['magic']); I hope somebody can help. 回答1: That means it should be called like: $timer = (new VTimer)->get($options['magic']); The difference between static and non-static is that