non-equi-join

Merge 2 dataframes using conditions on “hour” and “min” of df1 in datetimes of df2

旧街凉风 提交于 2021-02-16 20:07:29
问题 I have a dataframe df.sample like this id <- c("A","A","A","A","A","A","A","A","A","A","A") date <- c("2018-11-12","2018-11-12","2018-11-12","2018-11-12","2018-11-12", "2018-11-12","2018-11-12","2018-11-14","2018-11-14","2018-11-14", "2018-11-12") hour <- c(8,8,9,9,13,13,16,6,7,19,7) min <- c(47,59,6,18,22,36,12,32,12,21,47) value <- c(70,70,86,86,86,74,81,77,79,83,91) df.sample <- data.frame(id,date,hour,min,value,stringsAsFactors = F) df.sample$date <- as.Date(df.sample$date,format="%Y-%m-

Merge 2 dataframes using conditions on “hour” and “min” of df1 in datetimes of df2

折月煮酒 提交于 2021-02-16 20:07:05
问题 I have a dataframe df.sample like this id <- c("A","A","A","A","A","A","A","A","A","A","A") date <- c("2018-11-12","2018-11-12","2018-11-12","2018-11-12","2018-11-12", "2018-11-12","2018-11-12","2018-11-14","2018-11-14","2018-11-14", "2018-11-12") hour <- c(8,8,9,9,13,13,16,6,7,19,7) min <- c(47,59,6,18,22,36,12,32,12,21,47) value <- c(70,70,86,86,86,74,81,77,79,83,91) df.sample <- data.frame(id,date,hour,min,value,stringsAsFactors = F) df.sample$date <- as.Date(df.sample$date,format="%Y-%m-

Merge 2 dataframes using conditions on “hour” and “min” of df1 in datetimes of df2

纵然是瞬间 提交于 2021-02-16 20:06:52
问题 I have a dataframe df.sample like this id <- c("A","A","A","A","A","A","A","A","A","A","A") date <- c("2018-11-12","2018-11-12","2018-11-12","2018-11-12","2018-11-12", "2018-11-12","2018-11-12","2018-11-14","2018-11-14","2018-11-14", "2018-11-12") hour <- c(8,8,9,9,13,13,16,6,7,19,7) min <- c(47,59,6,18,22,36,12,32,12,21,47) value <- c(70,70,86,86,86,74,81,77,79,83,91) df.sample <- data.frame(id,date,hour,min,value,stringsAsFactors = F) df.sample$date <- as.Date(df.sample$date,format="%Y-%m-

Merge 2 dataframes using conditions on “hour” and “min” of df1 in datetimes of df2

拜拜、爱过 提交于 2021-02-16 20:06:35
问题 I have a dataframe df.sample like this id <- c("A","A","A","A","A","A","A","A","A","A","A") date <- c("2018-11-12","2018-11-12","2018-11-12","2018-11-12","2018-11-12", "2018-11-12","2018-11-12","2018-11-14","2018-11-14","2018-11-14", "2018-11-12") hour <- c(8,8,9,9,13,13,16,6,7,19,7) min <- c(47,59,6,18,22,36,12,32,12,21,47) value <- c(70,70,86,86,86,74,81,77,79,83,91) df.sample <- data.frame(id,date,hour,min,value,stringsAsFactors = F) df.sample$date <- as.Date(df.sample$date,format="%Y-%m-

Why Hive can not support non-equi join?

感情迁移 提交于 2021-02-10 18:14:37
问题 I found that the Hive does not support non-equi join.Is it just because it is difficult to convert non-equi join to Map reduce? 回答1: Yes, the problem is in current map-reduce implementation. How common equi-join is implemented in MapReduce? Input records are being copied in chunks to the mappers, mappers produce output as key-value pairs, which are collected and distributed between reducers using some function in such way that each reducer will process the whole key, in other words, mapper

Why Hive can not support non-equi join?

醉酒当歌 提交于 2021-02-10 17:55:57
问题 I found that the Hive does not support non-equi join.Is it just because it is difficult to convert non-equi join to Map reduce? 回答1: Yes, the problem is in current map-reduce implementation. How common equi-join is implemented in MapReduce? Input records are being copied in chunks to the mappers, mappers produce output as key-value pairs, which are collected and distributed between reducers using some function in such way that each reducer will process the whole key, in other words, mapper

Join big dataframe in r and filter in the same time

笑着哭i 提交于 2021-01-28 14:30:35
问题 df1 = data.frame(id=1,start=as.Date("2012-07-05"),end=as.Date("2012-07-15")) df2 = data.frame(id=rep(1,1371),date = as.Date(as.Date("2012-05-06"):as.Date("2016-02-05"))) output = dplyr::inner_join(x=df1,y=df2,by="id") %>% filter(date>=start & date<= end) I have two dataframes which have each one about one millions rows and I want to join them by id and then filter so that for each row, value of column date is comprised between value of startdate and enddate. An dplyr::inner_join is not

R sum by group if date within date range

浪子不回头ぞ 提交于 2021-01-28 14:26:17
问题 Suppose I have two dataframes. The first one includes "Date" at which a "Name" issues a "Rec" for an "ID" and the "Stop.Date" at which "Rec" becomes invalid. df (only a part) structure(list(Date = structure(c(13236, 13363, 14074, 13199, 14554), class = "Date"), ID = c("AU0000XINAA9", "AU0000XINAA9", "AU0000XINAC5", "AU0000XINAI2", "AU0000XINAJ0"), Name = c("N+1 BREWIN", "N+1 BREWIN", "ARBUTHNOT SECURITIES LTD.", "INVESTEC BANK (UK) PLC", "AWRAQ INVESTMENTS"), Rec = c(1, 2, 2, 2, 1), Stop.Date

How to LEFT JOIN on ANY of the matching clauses in R?

我是研究僧i 提交于 2021-01-28 11:30:45
问题 could you please help me out with this: I have a dataframe ( df1 ) that has index of all articles published in the website's CMS. There's a column for current URL and a column of original URLs in case they were changed after publication (column name Origin ): URL Origin ArticleID Author Category Cost https://example.com/article1 https://example.com/article 001 AuthorName Politics 120 USD https://example.com/article2 https://example.com/article2 002 AuthorName Finance 68 USD Next I have an

Column name labelling in data.table joins

元气小坏坏 提交于 2021-01-05 07:15:06
问题 I am trying to join data.table x to z using a non-equi join. Table x contains two columns X1 and X2 that are used as the range to use for joining with column Z1 in z. The current code successfully does the non-equi join however certain columns are removed or renamed. I would like to return the 'ideal' data.table supplied, instead of the one I currently have which I would have to rename columns or join data further to get the 'ideal' data supplied. > library(data.table) > > x <- data.table(Id