nested-lists

问题 I know that the topic of flattening a nested list has been covered in great detail before, however I think my task is a bit different and I couldn't find any info. I am writing a scraper, and as output I get a nested list. The top level list elements are supposed to become rows for data in spreadsheet form. However, since the nested lists are often of different lengths, I need to expand them before flattening the list. Here's an example. I have [ [ "id1", [["x", "y", "z"], [1, 2]], ["a", "b",

问题 Hello I would like to create an Array from two Arrays but I do not want to create this new Array, with append() or extend(). Input arrays have the same number of rows and columns: listone = [1,2,3] listtwo = [4,5,6] Outcome we expect: mergedlist = [[1,4],[2,5],[3,6]] It can't be done via mergedlist = listone.append(listtwo) or mergedlist = listone.extend(listtwo) I would like to get mergedlist = [[1,4],[2,5],[3,6]] How can I get the desired output? This is a simple example to understand, real

问题 I am trying to get a footer menu styled in CSS using nested lists, since that seems the standard way nowadays most CMSes work with. However I am having a hell of a hard time getting the width and height dynamically expanding to the right sizes. So each top level list item is positioned horizontally, while each child level list item is then listed underneath. Problem 1: I want the total width of the top level list item to be the width of either the longest child list item or the top list item,

问题 I just started using Python and I just came across the following problem: Imagine I have the following list of lists: list = [["Word1","Word2","Word2","Word4566"],["Word2", "Word3", "Word4"], ...] The result (matrix) i want to get should look like this: The Displayed Columns and Rows are all appearing words (no matter which list). The thing that I want is a programm that counts the appearence of words in each list (by list). The picture is the result after the first list. Is there an easy way

问题 I have a static class 'Defaults' which shall hold default matrices that are forwarded to an interface that asks for double[][] in the end. So far I simply put static properties in this class that return double[][] s. Now to make this conform to our company's coding standards, the code must comply to FxCop's rule CA1819, which won't allow me to return a jagged array from a property like I did. And instead of arrays, I shall return IList or IEnumerable (as discussed here). "Fair enough" I

问题 Okay my problem is that my nested sub categories should be hidden until I hover over the parent category but when I hover over the main parent category all the sub categories and sub sub categories are displayed. How can I fix this problem so that only the parents sub categories are displayed and not the sub categories sub sub categories until I hover over them? Here is the CSS. #nav-container ul.cat-container ol ol ol ol li a { visibility: hidden; height: 0; display: none; } #nav-container

问题 I'm trying to write data from a list of lists to a csv file. This is a simplified version of what I have class Point(object): def __init__(self, weight, height): self.weight = weight self.height = height def get_BMI(self): return (self.weight * self.height) / 42 # this is not how you calculate BMI but let's say myList = [[Point(30, 183)],[Point(63, 153)]] Because of the way the data is set up, I store the points in a nested loop. If I wanted to access the first point object’s BMI, I would

问题 I have a multi-page form and each page is contained within a list item. Each of those list items contains an ordered list with questions in its list items. Each of those list items contains an unordered list with a selection of either radio or checkbox input types. I'm trying to get CSS counters to increment on the ordered list's list items. Here's a basic example: http://jsfiddle.net/wCbvb/ <ol> <li> <h1>Page 1</h1> <ol> <li> <h2>Question 1</h2> <ul> <li>Answer</li> <li>Answer</li> <li

问题 Newbie here trying to search for part of one sublist within another sublist. list_1 = [[1, 2, 9], [4, 5, 8]] list_2 = [[1, 2, 3], [4, 5, 6], [1, 2, 5]] for item in list_1: for otherItem in list_2: item[0:2] in otherItem[0:2] I was hoping this would return True False True False True False But instead I get false for every iteration. In a nutshell: list_1[0][0:2] == list_2[0][0:2] #this returns true list_1[0][0:2] in list_2[0][0:2] #this returns false I guess I don't understand how in works.

问题 I needed to create a list of lists in Python, so I typed the following: myList = [[1] * 4] * 3 The list looked like this: [[1, 1, 1, 1], [1, 1, 1, 1], [1, 1, 1, 1]] Then I changed one of the innermost values: myList[0][0] = 5 Now my list looks like this: [[5, 1, 1, 1], [5, 1, 1, 1], [5, 1, 1, 1]] which is not what I wanted or expected. Can someone please explain what's going on, and how to get around it? 回答1: When you write [x]*3 you get, essentially, the list [x, x, x] . That is, a list with