neo4j.rb

Neo4j.rb create unique relationship

做~自己de王妃 提交于 2019-12-10 09:02:26
问题 Here is my Neo4j Active Node class User include Neo4j::ActiveNode has_many :out, :following, type: :following, model_class: 'User' end john = User.find(:name => "John") tom = User.find(:name => "Tom") # create following relationship john --> tom john.following << tom # check count john.following.count #=> 1 # again create the relationship john.following << tom # again check count john.following.count #=> 2 I want to create unique relationship. To avoid duplication we have to use create unique

Neo4j.rb create unique relationship

亡梦爱人 提交于 2019-12-05 14:52:24
Here is my Neo4j Active Node class User include Neo4j::ActiveNode has_many :out, :following, type: :following, model_class: 'User' end john = User.find(:name => "John") tom = User.find(:name => "Tom") # create following relationship john --> tom john.following << tom # check count john.following.count #=> 1 # again create the relationship john.following << tom # again check count john.following.count #=> 2 I want to create unique relationship. To avoid duplication we have to use create unique in creating relation cypher query. Example: MATCH (root { name: 'root' }) CREATE UNIQUE (root)-[:LOVES

How do I remove ActiveRecord from an existing Rails 4 Application?

a 夏天 提交于 2019-11-30 16:18:48
问题 I started off a Ruby on Rails Project which includes a simple recommender system with ActiveRecord and Neography. Now I found out about neo4j.rb, which is going to simplify my life by a lot. :-) I learned by now, that I could create a new Application without ActiveRecord as follows: rails new xyz -O I could do that and copy paste most of my files / code into that new project. Or is there an easier way? I am still thinking about if that step is even necessary. Is it possible to use both neo4j

How do I remove ActiveRecord from an existing Rails 4 Application?

橙三吉。 提交于 2019-11-30 15:55:30
I started off a Ruby on Rails Project which includes a simple recommender system with ActiveRecord and Neography. Now I found out about neo4j.rb , which is going to simplify my life by a lot. :-) I learned by now, that I could create a new Application without ActiveRecord as follows: rails new xyz -O I could do that and copy paste most of my files / code into that new project. Or is there an easier way? I am still thinking about if that step is even necessary. Is it possible to use both neo4j.rb and ActiveRecord in parallel? I am thinking of running the authentication system (e.g. Devise) with

neo4j Cypher hierarchical tree build response to JSON

冷暖自知 提交于 2019-11-28 13:02:36
Can you help me to build cypher query? i have following graph db structure: (parent:Category)-[:subcategory]->(child:Category) With this graph data i have hierarchical tree with deep level. I found following code on Stackoverfllow.com and changed for my data: MATCH (root:Category)-[:subcategory]->(parent:Category)-[:subcategory]->(child:Category) WITH root, {category: parent, children: collect(child)} AS parent_with_children WHERE NOT(()-[:subcategory]->(root)) RETURN {category: root, children: collect(parent_with_children)} But he is build response only for depth with 3 levels of tree. I need

neo4j Cypher hierarchical tree build response to JSON

非 Y 不嫁゛ 提交于 2019-11-27 07:26:22
问题 Can you help me to build cypher query? i have following graph db structure: (parent:Category)-[:subcategory]->(child:Category) With this graph data i have hierarchical tree with deep level. I found following code on Stackoverfllow.com and changed for my data: MATCH (root:Category)-[:subcategory]->(parent:Category)-[:subcategory]->(child:Category) WITH root, {category: parent, children: collect(child)} AS parent_with_children WHERE NOT(()-[:subcategory]->(root)) RETURN {category: root,