negation

Negative form of isinstance() in Python

折月煮酒 提交于 2021-01-18 07:38:31
问题 How would I use a negative form of Python's isinstance()? Normally negation would work something like x != 1 if x not in y if not a I just haven't seen an example with isinstance(), so I'd like to know if there's a correct way to used negation with isinstance(). 回答1: Just use not . isinstance just returns a bool , which you can not like any other. 回答2: That would seem strange, but: if not isinstance(...): ... The isinstance function returns a boolean value. That means that you can negate it

Negative form of isinstance() in Python

此生再无相见时 提交于 2021-01-18 07:37:12
问题 How would I use a negative form of Python's isinstance()? Normally negation would work something like x != 1 if x not in y if not a I just haven't seen an example with isinstance(), so I'd like to know if there's a correct way to used negation with isinstance(). 回答1: Just use not . isinstance just returns a bool , which you can not like any other. 回答2: That would seem strange, but: if not isinstance(...): ... The isinstance function returns a boolean value. That means that you can negate it

Why use abs() or fabs() instead of conditional negation?

梦想的初衷 提交于 2020-08-20 18:48:12
问题 In C/C++, why should one use abs() or fabs() to find the absolute value of a variable without using the following code? int absoluteValue = value < 0 ? -value : value; Does it have something to do with fewer instructions at lower level? 回答1: The "conditional abs" you propose is not equivalent to std::abs (or fabs ) for floating point numbers, see e.g. #include <iostream> #include <cmath> int main () { double d = -0.0; double a = d < 0 ? -d : d; std::cout << d << ' ' << a << ' ' << std::abs(d)

Negating typescript types?

不羁的心 提交于 2020-05-14 19:58:09
问题 I wanted to create a simple NOT operator in typescript where you get all primitives combined into the union of some type A that are NOT primitive members of the union of a second type B. This can be done using conditional types. For example, if you have types: type A = 'a' | 'b' | 'c'; type B = 'c' | 'd' | 'e'; ... then I want to map them to a third derived type [A - B] that, in this case, would yield: type C = 'a' | 'b' This seems to be doable using conditionals of the form shown below.

Negation in np.select() condition

别等时光非礼了梦想. 提交于 2020-02-23 07:13:43
问题 Here is my code: import pandas as pd import numpy as np df = pd.DataFrame({ 'var1': ['a', 'b', 'c',np.nan, np.nan], 'var2': [1, 2, np.nan , 4, np.nan] }) conditions = [ (not(pd.isna(df["var1"]))) & (not(pd.isna(df["var2"]))), (pd.isna(df["var1"])) & (pd.isna(df["var2"]))] choices = ["No missing", "Both missing"] df['Result'] = np.select(conditions, choices, default=np.nan) Output: File "C:\ProgramData\Anaconda3\lib\site-packages\pandas\core\generic.py", line 1478, in __nonzero__ f"The truth

Negation in np.select() condition

半腔热情 提交于 2020-02-23 07:13:39
问题 Here is my code: import pandas as pd import numpy as np df = pd.DataFrame({ 'var1': ['a', 'b', 'c',np.nan, np.nan], 'var2': [1, 2, np.nan , 4, np.nan] }) conditions = [ (not(pd.isna(df["var1"]))) & (not(pd.isna(df["var2"]))), (pd.isna(df["var1"])) & (pd.isna(df["var2"]))] choices = ["No missing", "Both missing"] df['Result'] = np.select(conditions, choices, default=np.nan) Output: File "C:\ProgramData\Anaconda3\lib\site-packages\pandas\core\generic.py", line 1478, in __nonzero__ f"The truth

Does PHP negation check with `!` coprrespond to `!=` or to `!==`?

て烟熏妆下的殇ゞ 提交于 2020-01-30 13:09:27
问题 In PHP, is if(!$foo) equivalent with if($foo != true) or with if($foo !== true) or is it even something completly different of both? 回答1: if(!$foo) is the equivalent to if($foo != true) so $foo = null; if(!$foo){ echo "asd"; } will ouptut "asd" 回答2: Note that, == OR != compares the values of variables for equality, type casting as necessary. === OR !== checks if the two variables are of the same type AND have the same value. This answer will give you better explanation of this concept: https:

negation handling in R, how can I replace a word following a negation in R?

谁说我不能喝 提交于 2020-01-13 20:23:10
问题 I'm doing sentiment analysis for financial articles. To enhance the accuracy of my naive Bayes classifier, I'd like to implement negation handling. Specifically, I want to add the prefix "not_" to the word following a "not" or "n't" So if there's something like this in my corpus: x <- "They didn't sell the company." I want to get the following: "they didn't not_sell the company." (the stopword "didn't" will be removed later) I could find only the gsub() function, but it doesn't seem to work

negation handling in R, how can I replace a word following a negation in R?

不羁的心 提交于 2020-01-13 20:23:07
问题 I'm doing sentiment analysis for financial articles. To enhance the accuracy of my naive Bayes classifier, I'd like to implement negation handling. Specifically, I want to add the prefix "not_" to the word following a "not" or "n't" So if there's something like this in my corpus: x <- "They didn't sell the company." I want to get the following: "they didn't not_sell the company." (the stopword "didn't" will be removed later) I could find only the gsub() function, but it doesn't seem to work

python3: How to get logical complement (negation) of a binary number, eg. '010' => '101'?

时光总嘲笑我的痴心妄想 提交于 2020-01-04 06:05:40
问题 Maybe I'm missing something but I can't find a straightforward way to accomplish this simple task. When I go to negate a binary number through the "~" operator it returns a negative number due to the two's complement: >>> bin(~0b100010) # this won't return '0b011101' '-0b100011' What about if I just want to switch 0s into 1s and vice-versa, like in classic logical complement? 回答1: >>> bin(0b111111 ^ 0b100010) '0b11101' >>> 回答2: YOU's answer as a function: def complement(n): size = len(format