mysql-error-1064

问题 The error message I got: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''word','group','selfnote') VALUES ('item','a','note to self')' at line 1 The PHP code is: $toq="INSERT INTO articles ('word','group','selfnote') VALUES ('$ttle','$wrdr','$snote')"; I was trying to find solutins, but they didn't seem to work as echoing gives: INSERT INTO articles ('word','group','selfnote') VALUES ('item','a','note to

问题 CREATE TRIGGER b_I_O AFTER UPDATE ON book FOR EACH ROW BEGIN IF (OLD.status IS NOT NULL AND NEW.status IS NOT NULL AND NEW.status != OLD.status ) THEN INSERT INTO book_in_out (astatus, bid, time) VALUES(NEW.status, OLD.id, NOW()); END IF; END; First post here after hours of searching. I'm trying to insert into book_in_out using trigger after updating booking table, I was able to do this but if I update bookName the trigger will try to run. I only want the trigger to run only when status

问题 There always be the error: "Cannot add foreign key constraint" when I create my last table . System: Mac OS X 10.9 DB : MySQL 5.6.14 DBM : Sequel Pro CREATE TABLE users ( uid INT AUTO_INCREMENT PRIMARY KEY, uname VARCHAR(20) NOT NULL, uemail VARCHAR(20) NOT NULL, ucity VARCHAR(20), upassw VARCHAR(20) NOT NULL ); CREATE TABLE songs( sid INT AUTO_INCREMENT PRIMARY KEY, sname VARCHAR(20) NOT NULL, srldate DATE NOT NULL ); CREATE TABLE albums ( albid INT AUTO_INCREMENT PRIMARY KEY, albname

问题 Is it possible to set the result from a prepared statement into a variable? I am trying to create the following stored procedure but it is failing: ERROR 1064 (42000) at line 31: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'stmt USING @m, @c, @a; DROP PROCEDURE IF EXISTS deleteAction; DELIMITER $$ CREATE PROCEDURE deleteAction( IN modul CHAR(64), IN controller CHAR(64), IN actn CHAR(64)) MODIFIES SQL

问题 I keep getting the following error message ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right systax to use near ''isbn10','isbn13','title','edition','author_f_name','author_m_name','author_l_na' at line 1 when trying to populate my MySQL database from the (MySQL) command line with the following command: source C:\myFilePath\myFileName.sql Here is an excerpt from my mysqldump (showing the table structure for

问题 I have MySQL workbench installed on my computer and always worked correctly. Now try to run it and do not run. Gives an error: MySql Workbench has encountered a problem External component has throw an exception. We are sorry for the inconvenience but an unexpected exception has been raised by one of the MySQL Workbench modules. In order to fix this issue we would kindly ask you to file a bug report. You can do that by pressing the [Report Bug] button below. Please make sure to include a

问题 hi every one i was reading a sans book about blind sql injection the author of the book mention that if you want to trigger an error in mysql use this query and inject it in the target 1 and (select 1 from (select count(*),concat(/*your malicious query here*/,floor(rand(0)*2)x from users group by x) a) and he says (author) that count(*) on a group by "floor(rand(0)*2)" causes a duplicate key in internal table and display the key My questions: first why he put the x there ? second what is

问题 hi every one i was reading a sans book about blind sql injection the author of the book mention that if you want to trigger an error in mysql use this query and inject it in the target 1 and (select 1 from (select count(*),concat(/*your malicious query here*/,floor(rand(0)*2)x from users group by x) a) and he says (author) that count(*) on a group by "floor(rand(0)*2)" causes a duplicate key in internal table and display the key My questions: first why he put the x there ? second what is

问题 I cannot seem to create a trigger. I have tried it the two ways below for the update. I keep getting a syntax error with the insert statement. I have searched forums and web searches for the past 4 hrs with no change. There is alot more code to this, It basically repeats itself. Any help would be appreciated. Thank You. I am running MySQL 5.0 and acessing via phpMyAdmin 2.8.2.4 as Administrator/Root. TRY 1 (with and without qoutes on all fields and names) CREATE TRIGGER insert_classes AFTER

问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . I am trying to use a UNION statement in an old BugZilla MySQL DB running MySQL 3.23. Here is a simplified version of what I am trying to do. It's really