msxml

How to query default namespace with MSXML

由 女生的网名这么多〃 提交于 2019-12-04 17:03:39
问题 I have some XML: <?xml version="1.0" ?> <Project ToolsVersion="4.0"> <PropertyGroup Condition="'$(key)'=='1111'"> <Key>Value</Key> </PropertyGroup> </Project> Note : This isn't the actual XML i'm using, it's just prettier and shorter, and demonstrates the problem. Using MSXML i can query for nodes: IXMLDOMNode node = doc.selectSingleNode("//PropertyGroup/@Condition"); And it works fine: Condition="'$(key)'=='1111'" But that's not really the XML i have In reality the XML i have contains a

XSD: Define an element with any name

由 这一生的挚爱 提交于 2019-12-04 11:04:29
问题 Because of limitations of certain systems, we need to use XMLs that are formatted a bit inconveniently. Those we need to transform into a convenient form. The question: how do I define in an XSD schema an element that has the following properties: Does not have any children Does not have any attributes Has any name (that is what's causing problems) 回答1: You can use the <xsd:any /> element together with the Xml Schema Instance type attribute. Schema <?xml version="1.0" encoding="utf-8" ?> <xsd

XSD: Define an element with any name

由 浪尽此生 提交于 2019-12-03 06:57:08
Because of limitations of certain systems, we need to use XMLs that are formatted a bit inconveniently. Those we need to transform into a convenient form. The question: how do I define in an XSD schema an element that has the following properties: Does not have any children Does not have any attributes Has any name (that is what's causing problems) Filburt You can use the <xsd:any /> element together with the Xml Schema Instance type attribute . Schema <?xml version="1.0" encoding="utf-8" ?> <xsd:schema attributeFormDefault="qualified" elementFormDefault="qualified" xmlns:xsd="http://www.w3

Reference to undeclared namespace prefix when parsing MSXML

由 泪湿孤枕 提交于 2019-12-02 22:55:13
How do I solve the Reference to undeclared namespace prefix: '%s' problem with Microsoft's msxml implementation? I'm using an XML feed from a government web-site that contains values i need to parse. The xml contains namespaces: <?xml version="1.0" encoding="ISO-8859-1"?> <rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns="http://purl.org/rss/1.0/" xmlns:cb="http://www.cbwiki.net/wiki/index.php/Specification_1.1" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:dcterms="http://purl.org/dc/terms/" xmlns:xsi="http://www.w3c.org/2001/XMLSchema-instance" xsi:schemaLocation=

VBScript Can not Select XML nodes

由 感情迁移 提交于 2019-12-02 19:37:39
问题 I am trying to Select nodes from some webservice response XML to no avail. For some reason I am able to select the root node ("xmldata") however, when I try to drill deeper("xmldata/customers") everything is returned empty! Below is the a sample of the XML that is returned by the webservice. <xmldata> <customers> <customerid>22506</customerid> <firstname>Jim</firstname> <issuperadmin>N</issuperadmin> <lastname>Jones</lastname> </customers> </xmldata> and here is the code I am trying to select

How to get XML attribute value?

由 心已入冬 提交于 2019-12-02 14:54:30
问题 Set XmlDocument = Server.CreateObject("Msxml2.DOMDocument.3.0") XmlDocument.SetProperty "ServerHTTPRequest", True XmlDocument.Async = False XmlDocument.Load("books.xml") Set Items = XmlDocument.selectNodes("//book") For Each Item in Items Set title = Item.SelectSingleNode("title/text()") S_title = Trim(title.data) Set price = Item.SelectSingleNode("price/text()") S_price = Trim(price.data) response.Write S_title & S_price Set Objavail = price.GetAttribute("avail") S_avail = Objavail.value

Which version of MSXML began to support parsing XML 1.1?

由 a 夏天 提交于 2019-12-02 14:39:54
问题 If I use MSXML6.dll to parse XML 1.1, I will get this error: 0xC00CE57F MSG_E_INVALID_VERSION Invalid version number XML 1.1 was initially published on February 4, 2004. I'm surprised that MSXML6.dll can not parse it. The question: Does any MSXML4/5/6.dll support XML 1.1? Thanks in advance. 回答1: Sorry, no XML 1.1 with any MSXML version :( As Microsoft states (see data developer center and MSXML SDK Overview) MSXML is for applications that adhere to the XML 1.0 standard. 来源： https:/

VBScript Can not Select XML nodes

由 徘徊边缘 提交于 2019-12-02 11:52:57
I am trying to Select nodes from some webservice response XML to no avail. For some reason I am able to select the root node ("xmldata") however, when I try to drill deeper("xmldata/customers") everything is returned empty! Below is the a sample of the XML that is returned by the webservice. <xmldata> <customers> <customerid>22506</customerid> <firstname>Jim</firstname> <issuperadmin>N</issuperadmin> <lastname>Jones</lastname> </customers> </xmldata> and here is the code I am trying to select customerid, firstname, and lastname; ' Send the Xml oXMLHttp.send Xml_to_Send ' Validate the Xml dim

Which version of MSXML began to support parsing XML 1.1?

由 我怕爱的太早我们不能终老 提交于 2019-12-02 10:17:48
If I use MSXML6.dll to parse XML 1.1, I will get this error: 0xC00CE57F MSG_E_INVALID_VERSION Invalid version number XML 1.1 was initially published on February 4, 2004. I'm surprised that MSXML6.dll can not parse it. The question: Does any MSXML4/5/6.dll support XML 1.1? Thanks in advance. Sorry, no XML 1.1 with any MSXML version :( As Microsoft states (see data developer center and MSXML SDK Overview ) MSXML is for applications that adhere to the XML 1.0 standard. 来源： https://stackoverflow.com/questions/16269460/which-version-of-msxml-began-to-support-parsing-xml-1-1

How to get XML attribute value?

由 两盒软妹~` 提交于 2019-12-02 05:26:10
Set XmlDocument = Server.CreateObject("Msxml2.DOMDocument.3.0") XmlDocument.SetProperty "ServerHTTPRequest", True XmlDocument.Async = False XmlDocument.Load("books.xml") Set Items = XmlDocument.selectNodes("//book") For Each Item in Items Set title = Item.SelectSingleNode("title/text()") S_title = Trim(title.data) Set price = Item.SelectSingleNode("price/text()") S_price = Trim(price.data) response.Write S_title & S_price Set Objavail = price.GetAttribute("avail") S_avail = Objavail.value response.Write S_avail &"<br>" Next It seem to me identical like the method described here , but I can not
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