mongodb-query

MongoDB find and return all with max value

孤者浪人 提交于 2021-02-20 18:07:25
问题 I'm trying to get a list of documents that have the max value. I can specify it if I know the number of documents with max value (like in the solution in this another stackoverflow solution 'mongodb how to get max value from collections'), but I don't know how to do it if I don't know what the number of documents is. For example, using the following documents: {name:"a", age:10} {name:"b", age:11} {name:"d", age:12} {name:"c", age:12} So I know that there are 2 documents with max age of 12.

MongoDB find and return all with max value

﹥>﹥吖頭↗ 提交于 2021-02-20 18:05:43
问题 I'm trying to get a list of documents that have the max value. I can specify it if I know the number of documents with max value (like in the solution in this another stackoverflow solution 'mongodb how to get max value from collections'), but I don't know how to do it if I don't know what the number of documents is. For example, using the following documents: {name:"a", age:10} {name:"b", age:11} {name:"d", age:12} {name:"c", age:12} So I know that there are 2 documents with max age of 12.

How to insert new object without deleting previous one

坚强是说给别人听的谎言 提交于 2021-02-19 07:44:09
问题 I'm setting up my new RocketChat Server. The problem is that actually, Rocket Chat doesn't support CAS Account if they are not created by CAS. We have old accounts. I can add the CAS feature by doing this : Enter in the MongoDB Database with MongoDB Compass software on Windows, and add cas object in services object with my keyboard... https://i.imgur.com/AIMAlA6.png So as you can see I can add the CAS feature by doing this. I want to do that with code so I did this : 1 - Enter in rocketchat

MongoDB Can't canonicalize query: BadValue Too many text expressions

坚强是说给别人听的谎言 提交于 2021-02-19 05:20:26
问题 I am attempting to build a query for MongoDB in Java and I am running into this error, "Can't canonicalize query: BadValue Too many text expressions" whenever I run the query. The database is full of documents with a text property that is indexed for full text searching. I am trying to build a query to find any documents that match one or more of the queries in queryList and are within a certain time range. It works fine if there is only one query in the queryList, but fails otherwise. Any

Get ID of affected document by using update()

女生的网名这么多〃 提交于 2021-02-18 20:59:53
问题 I'm using this for doing an upsert: Articles.update( { title: title }, { title: title, parent: type }, { upsert: true }, function(res) { return console.log(res); } ); console.log(needToGetID); Now I need to get the _id of the document which has been updated or inserted. I thought I can get that via callback, but res is undefined. I assume there is just one unique document which is defined by the query. Update Forgot to mention that I'm using meteor... 回答1: The intent of .update() is to

Mongoose find all documents where array.length is greater than 0 & sort the data

血红的双手。 提交于 2021-02-18 04:13:44
问题 I am using mongoose to perform CRUD operation on MongoDB. This is how my schema looks. var EmployeeSchema = new Schema({ name: String, description: { type: String, default: 'No description' }, departments: [] }); Each employee can belong to multiple department. Departments array will look like [1,2,3]. In this case departments.length = 3. If the employee does not belong to any department, the departments.length will be equal to 0. I need to find all employee where EmployeeSchema.departments

Mongoose find all documents where array.length is greater than 0 & sort the data

拥有回忆 提交于 2021-02-18 04:07:40
问题 I am using mongoose to perform CRUD operation on MongoDB. This is how my schema looks. var EmployeeSchema = new Schema({ name: String, description: { type: String, default: 'No description' }, departments: [] }); Each employee can belong to multiple department. Departments array will look like [1,2,3]. In this case departments.length = 3. If the employee does not belong to any department, the departments.length will be equal to 0. I need to find all employee where EmployeeSchema.departments

Mongoose find all documents where array.length is greater than 0 & sort the data

我的未来我决定 提交于 2021-02-18 04:07:13
问题 I am using mongoose to perform CRUD operation on MongoDB. This is how my schema looks. var EmployeeSchema = new Schema({ name: String, description: { type: String, default: 'No description' }, departments: [] }); Each employee can belong to multiple department. Departments array will look like [1,2,3]. In this case departments.length = 3. If the employee does not belong to any department, the departments.length will be equal to 0. I need to find all employee where EmployeeSchema.departments

MongoDB: How to query a time-series with incomplete data?

时光总嘲笑我的痴心妄想 提交于 2021-02-17 04:40:28
问题 I'm storing time series data in a mongoDB collection with one data point every 15min. But sometimes, due to bad conditions, some data points get lost. I have a dataset as follows: {"device_id": "ABC","temp": 12,"timestamp": 2020-01-04T17:48:09.000+00:00} {"device_id": "ABC","temp": 10,"timestamp": 2020-01-04T18:03:09.000+00:00} {"device_id": "ABC","temp": 14,"timestamp": 2020-01-04T18:18:09.000+00:00} missing frame missing frame {"device_id": "ABC","temp": 13,"timestamp": 2020-01-04T19:03:09

How to directly query nested field without specify parent field?

拥有回忆 提交于 2021-02-17 03:17:42
问题 I have next 3 documents in mongodb: document 1: { "name": "device1", "camera": { "number": 3 } } document 2: { "name": "device2", "camera": { "number": 1 } } document 3: { "name": "device3", "wifi": { "number": 2 } } My aim is to find all devices which modules' number > 1, the module maybe camera , wifi or others. I know I can use next to get the device: > db.devices.find({"camera.number":{$gt:1}}) { "_id" : ObjectId("5f436a3df716cb47d319245e"), "name" : "device1", "camera" : { "number" : 3 }