modulus

how to calculate (A*B*C)%10000007 where A,B,C can be at maximum 10^18

天大地大妈咪最大 提交于 2019-12-25 18:57:06
问题 how to calculate (A*B*C)%10000007 where A,B,C can be maximum 10^18 回答1: Let I = 10000007, so A = n1 * I + X1 B = n2 * I + X2 C = n3 * I + X3 A * B => (n1 * I + X1) (n2 * I + X2) => n1 * n2 * I^2 + n1 * X2 * I + n2 * X1 * I + X1 * X2 Only X1 * X2 can't div by I Hence, A * B % I === X1 * X2 % I === (A % I) * (B % I) % I Therefore (A * B * C) % I === [(A % I) * (B % I) % I] * (C % I) % I 来源: https://stackoverflow.com/questions/14189713/how-to-calculate-abc10000007-where-a-b-c-can-be-at-maximum

set Modulus and Exponent from VB.Net to Android/Java

£可爱£侵袭症+ 提交于 2019-12-25 09:16:02
问题 I have this RSA public key which is generated in VB.Net my server. <RSAKeyValue><Modulus>tv0tzng4pW7erDo2ke/Ku9TGKRukAzx+lihZVblIOE6GWIoiwlILOANeVliZLi1s5qMsXEUA4GV2woC1zFdhJvfFja8Nacl4I3CJ4JYmGqcSZinWKgo3MJdoEqFl9NliF4wTYLow3GYoUh03WxoeArozV1S03drP898b9PdbjPY+ji4jpZHJWnbfg+qWSziF1Q/pSAxpzabeoamz1+ekqlhuxZavQUl+hIhx/quHqy3ybFWcX6yE5NKeY1fzX3L7</Modulus> <Exponent>AQAB</Exponent> </RSAKeyValue> I want to set this value to my android RSA public key but converting with this code doesn't set the

Using javascript modulus to iterate through text slider with for loop

谁说我不能喝 提交于 2019-12-24 10:58:05
问题 I'm new to jQuery and stack overflow, so I'll try to be specific, but please bear with me. I'm trying to create a text slider with associated links from scratch, using modulus to iterate through the list and repeat. Here's the code I'm working with: ul#text { position: relative; margin-bottom: 40px; height: 40px; } ul#text li { position: absolute; display: none; } .active { font-weight: bold; } <ul id="text"> <li id="textBody">Suffering is not a result of physical pain alone. It can be

modulus operation division property

╄→гoц情女王★ 提交于 2019-12-24 09:13:10
问题 i have an equation , ((a*b*c*d)/(e*f*g*h))%m My question is , Can i first apply multiplication property (a*b) mod(n) = (a*mod(n)) * (b*mod(n) ) mod(n) to numerator and then denominator , so that numerator and denominator becomes a single value , and then solve the division operation? (a/b) mod(n) = (a*inv(b)) mod(n) 回答1: Let N = a*b*c*d and D = e*f*g*h . We want to calculate: (N/D) mod n = (N * inv(D)) mod n We can use the multiplication property here in the following way: (N * inv(D)) mod n

Angular2 modulus functionality to create rows of elements

耗尽温柔 提交于 2019-12-24 00:38:47
问题 I am having trouble recreating and imagining how to recreate the following piece of vanilla Javascript code in Angular2 (I just typed it out on the spot so don't worry about syntax or logic errors). As you can see, I am looping through an array of products and if the iteration modulus of 4 then I close the div with class 'row' and start a new div with a class of row. This is so I can add 'col-xs-3 col-sm-3 col-md-3 col-lg-3' classes onto the products to make them responsive. <div class='row'>

Generate RSA Public key from modulus and exponent in bytes in Objective-c

痞子三分冷 提交于 2019-12-22 10:54:16
问题 I'd searching many websites trying to understand how does RSA works. I have a modulus "A89F25A56FA6DA258C8CA8B40427D927B4A1EB4D7EA326BBB12F97DED70AE5E4480FC9C5E8A972177110A1CC318D06D2F8F5C4844AC5FA79A4DC470BB11ED635699C17081B90F1B984F12E92C1C529276D8AF8EC7F28492097D8CD5BECEA16FE4088F6CFAB4A1B42328A1B996F9278B0B7E3311CA5EF856C2F888474B83612A82E4E00D0CD4069A6783140433D50725F" and exponent "03" and i have to decrypt information formated in hex bytes. My questions are: How do i create a public

C: The Math Behind Negatives and Remainder

╄→гoц情女王★ 提交于 2019-12-22 10:44:06
问题 This seems to be the #1 thing that is asked when dealing with Remainder/Mod, and I'm kind of hitting a wall with it. I'm teaching myself to program with a textbook and a chuck of C code. Seeing as I don't really have an instructor to say, "No, no. It actually works like this", I thought I'd try my hand here. I haven't found a conclusive answer to the mathematical part of this, though. So... I'm under the impression that this is a pretty rare occurrence, but I'd still like to know what it is

Sorting a list alphabetically with a modulus

与世无争的帅哥 提交于 2019-12-20 21:21:18
问题 I don't have any trouble grabbing a list of elements and sorting them alphabetically, but I'm having difficulty understanding how to do it with a modulus. ### UPDATE ### Here's the code working 'my way', however, I like the re-usability of the answer provided below more, so have accepted that answer. <script type="text/javascript"> $(document).ready( function() { $('.sectionList2').each( function() { var oldList = $('li a', this), columns = 4, newList = []; for( var start = 0; start < columns

Please explain why 17 % 40 = 17

青春壹個敷衍的年華 提交于 2019-12-20 05:40:14
问题 I am new to Java, actually programming in general. I understand that the modulus operator (%) returns the remainder of two numbers, however, I do not understand why 17 % 40 = 17. I understand that 40 % 17 = 6, and 17 % 5 = 2, and 40 % 5 = 0. I get the gist of what value is returned as the remainder. But 17 % 40 = 17 has me stumped. The only rationalization I can devise is that since the remainder is less than 1 the total value 17 is returned, why not 0? Please help to explain this enigma to

`java (0 % 2 != 0) == false`

家住魔仙堡 提交于 2019-12-19 17:42:37
问题 The part I keep getting stuck on is boolean(0 % 2 !=0) == false. I mean if 2 goes into 0, 0 times then the remainder would be 2, and 2 does not equal 0. So it should be true. Yet but when I put the boolean in my java program it is treating it as false. Anyone know why? The only logical answer I can wrap my head around is that maybe integers go into 0 and infinite number of times and so are recognized as false, anyone? 回答1: There are two steps: 0 % 2 evaluates to 0 . 0 != 0 evaluates to false