models

How to store functions in django models

风流意气都作罢 提交于 2020-01-23 13:24:26
问题 edit: I completely rewrote the question as the original one didn't clearly explain my question I want to run a function which is specific to each particular model instance. Ideally I want something like this: class MyModel(models.Model): data = models.CharField(max_length=100) perform_unique_action = models.FunctionField() #stores a function specific to this instance x = MyModel(data='originalx', perform_unique_action=func_for_x) x.perform_unique_action() #will do whatever is specified for

Character-level Convolutional Networks for Text Classification

余生长醉 提交于 2020-01-22 23:31:30
Abstract Semantic word spaces have been very useful but cannot express the meaning of longer phrases in a principled way. 语义词空间是非常有用的,但它不能有原则地表达较长短语的意义。 Further progress towards understanding compositionality in tasks such as sentiment detection requires richer supervised training and evaluation resources and more powerful models of composition. 要想在情感检测等任务中进一步理解构成,需要更丰富的监督训练和评估资源,以及更强大的构成模型。 To remedy this, we introduce a Sentiment Treebank. 为了解决这个问题,我们引入了一个情绪树库。 It includes fine grained sentiment labels for 215,154 phrases in the parse trees of 11,855 sentences and presents new challenges for

How to import django models in scrapy pipelines.py file

天涯浪子 提交于 2020-01-22 16:17:26
问题 I'm trying to import models of one django application in my pipelines.py to save data using django orm. I created a scrapy project scrapy_project in the first involved django application "app1" (is it a good choice by the way?). I added these lines to my scrapy settings file: def setup_django_env(path): import imp, os from django.core.management import setup_environ f, filename, desc = imp.find_module('settings', [path]) project = imp.load_module('settings', f, filename, desc) setup_environ

015.CI4框架CodeIgniter数据库操作之:带参数查询数

我与影子孤独终老i 提交于 2020-01-21 23:51:49
01.我们在Models中写数据库的操作。具体的查询代码如下: <?php namespace App\Models\System; use CodeIgniter\Model; class User_model extends Model { var $Db; function __construct() { parent::__construct(); //创建数据库连接 $this->Db = \Config\Database::connect(); } function getdata() { //带参数条件查询 $sql = "SELECT * FROM tp_user WHERE ( ID = ? AND ( MARK = ?))"; $sqlrst = $this->Db->query($sql, array('143', '2019091500000143')); $rst = $sqlrst->getRow(); return $rst; } } 02. 在控制器调用的代码如下: <?php namespace App\Controllers; class Home extends BaseController { // http://127.0.0.1/CI4/public/index.php/home/showdata var $User_Models;

django No migrations to apply 问题解决

匆匆过客 提交于 2020-01-20 07:09:26
最近在用django写项目,有的时候字段不够用,需要models增加字段,但是想回滚或者修改或者修改了属性等,例如忘了添加meta table于是操作了migrations 导致makemigrations没问题,migrate提示No migrations to apply 1.首先确认makemigrations的py是否存在,或者是否应当删除 这个时候再makemigrations一切顺利,但是执行migrate就除了问题 2.原因在数据库表django_migrations中存在,删除models的记录就可以了。 python manage.py makemigrations python manage.py migrate 来源: https://www.cnblogs.com/sevck/p/9719306.html

.net core自动生成ef代码

▼魔方 西西 提交于 2020-01-19 05:23:10
.net core使用mysql,需引入三个包: install-package Pomelo.EntityFrameworkCore.MySql install-package Pomelo.EntityFrameworkCore.MySql.Design install-package Microsoft.EntityFrameworkCore.Tools 在工具--Nuget包管理器--程序包管理器控制台中输入: Scaffold-DbContext "Database=test;Data Source=localhost;port=3306;User Id=root;Password=root;" Pomelo.EntityFrameworkCore.MySql -OutputDir Models 点击确定,执行完上面的代码Models文件夹中自动生成EF代码 Scaffold-DbContext "Server=(local);Database=test;Trusted_Connection=True;" Microsoft.EntityFrameworkCore.SqlServer -OutputDir Model -Force 命令来修改 来源: CSDN 作者: fei-01171 链接: https://blog.csdn.net/feixiang_01171

Ruby on Rails: Simple way to select all records of a nested model?

前提是你 提交于 2020-01-17 08:30:32
问题 Just curious, I spent an embarrassing amount of time trying to get an array of all the records in a nested model. I just want to make sure there is not a better way. Here is the setup: I have three models that are nested under each other (Facilities >> Tags >> Inspections), producing code like this for routes.rb: map.resources :facilities do |facilities| facilities.resources :tags, :has_many => :inspections end I wanted to get all of the inspections for a facility and here is what my code

django06: ORM示例2--uer 与file

半城伤御伤魂 提交于 2020-01-16 18:49:26
存放路径: https://git.lug.ustc.edu.cn/ 笔记 外键与多键 path = models.ForeignKey(to="Path") file = models.ManyToManyField(to="File") code 处理方式 new_path = request.POST.get("new_path",None) models.File.objects.create(name=new_user,path_id=new_path) // 多键 files = request.POST.getlist("files") user_obj = models.User.objects.create(name=new_user) user_obj.file.set(files) 来源: CSDN 作者: 砌砖 链接: https://blog.csdn.net/winterye12/article/details/104007603

授之以渔-运维平台Saltstack Web 管理一(模块管理篇)

对着背影说爱祢 提交于 2020-01-16 10:30:19
写在片头:2011年接触到了Puppet ,感叹老美对自动化的理解高了咱不是一个档次。2015年接触到了Saltstack,再次感叹。当时Saltstack还没有类似Puppet Foreman之类的Web管理,,从那时起,我就有了一个小小目标,我要山寨Foreman… ####Saltstack Web分为几块,下面用与Puppet Foreman对比的方式进行说明: ##一、 环境 Master和遍历程序在同一台服务器(Saltstack是否有对应的API可以远程操作models,暂时没研究) Django运行版本1.6.1 Python运行版本2.7.1 ##二、 食用过程 思路:在Saltstack master 写好相应的模块,按照一定的格式放到对应的目录中,通过遍历将类的名称,路径,sls名称写入Mysql中,然后通过Web方式进行展现。先取出所有本地模块列表,组成一个本地模块列表。然后用本地模块列表的数量和远端数据库内所存的模块列表数量进行比较。本地多了,就在远端数据库添加,本地少了,就在远端数据库删除。 ###1.导入模块代码如下(根据实际情况调整目录) def salt_model_import(request): if request.method == 'POST': os_list = [] add_count = 0 del_count = 0 try:

ASP.NET MVC 2.0 - IList<T> CheckBoxes

寵の児 提交于 2020-01-15 08:40:34
问题 What is the best way to handle this: class Option { int id; string name; } class QuoteItem { IList<Option> options; } class QuoteViewModel { IList<Option> allOptions; QuoteItem quoteItem; } Basically, I have all the available options in allOptions . I want to have a checkbox that puts another Option (even if its just its id ) into the QuoteItem.options list when it is checked. How would I accomplish this? Would it best be an IList<bool> and bind it after the fact? 回答1: I suggest you take look