median

问题 I am trying to find median of constant size array. But array is always uptading. I mean new numbers are replaced with old numbers. I call this process running median, or we can say on the fly median.. Here is my code and inside the code, when rand() function generates 78, the code cannot find the correct median. (Before 78; 41, 67, 34, 0, 69, 24 was generated) #include <iostream> #include <stdlib.h> #include <algorithm> #define MAX_SIZE 5 using namespace std; bool isOdd( int integer ) { if (

问题 How can I calculate the median value of a list in tensorflow? Like node = tf.median(X) X is the placeholder In numpy, I can directly use np.median to get the median value. How can I use the numpy operation in tensorflow? 回答1: edit: This answer is outdated, use Lucas Venezian Povoa's solution instead. It is simpler and faster. You can calculate the median inside tensorflow using: def get_median(v): v = tf.reshape(v, [-1]) mid = v.get_shape()[0]//2 + 1 return tf.nn.top_k(v, mid).values[-1] If X

问题 I want to modify QuickSort (in Java) so that every time Partition is called, the median of the proportioned array is used as the pivot. I have a median selection algorithm in Java that returns the kth smallest element, in this case the median. I have tons of quicksort algorithms in java that all work by themselves and sort an array. Unfortunately I can't combine those two in order to achieve the above... Everytime I try it i usually get stackoverflow erros. Can anybody show me code to see how

问题 I have data on monthly sales like this Company Month Sales Adidas 2018-09 100 Adidas 2018-08 95 Adidas 2018-07 120 Adidas 2018-06 155 ...and so on I need to add another column stating the median over the past 12 months (or as many as there is data for if 12 months are not available). In Python I figured out how to do it with for loops, but I'm not sure how to do in BigQuery. Thank you! 回答1: Here is an approach that might work: CREATE TEMP FUNCTION MEDIAN(arr ANY TYPE) AS (( SELECT IF( MOD

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I need to write a program in java to find the median of an array of three or more integers without sorting. I need some ideas. thanks 回答1: You can use a Selection Algorithm. You'll also find relevant information looking for Median of Medians. 回答2: You can use Quick sort partitioning step with random pivots,

问题 How do you find the median of a list in Python? The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. Here are some examples (sorted for display purposes): median([1]) == 1 median([1, 1]) == 1 median([1, 1, 2, 4]) == 1.5 median([0, 2, 5, 6, 8, 9, 9]) == 6 median([0, 0, 0, 0, 4, 4, 6, 8]) == 2 回答1: Python 3.4 has statistics.median: Return the median

问题 I have a report that i use Mean and Median measures that were calculated in SSAS 2012 tabular, the reports as follows: when i use the Mean and Median directly, the values in the green box are correct and the column and row totals are incorrect. after using aggregate instead of sum the following happens: 1- the blank row and blank column are now gone along with their values. 2- Then total of the Mean is correct in every cell except the grand total(2nd cell from right bottom corner), it appears

问题 I'm quite new to R and I have a problem on which I couldn't find a solution so far. I have a folder of 1000 raster files. I have to get the median of all rasters for each cell. The files contain NoData Cells (I think therefore they have different extents) Is there any solution to loop through the folder, adding together all files an getting the median? Error in rep(value, times = ncell(x)) : invalid 'times' argument In addition: Warning message: In setValues(x, rep(value, times = ncell(x))) :

问题 I have column A for Job Type. I have column B for Experience Range. I have column C for salary. These are in a sheet named 'Data'. I have created a pivot table with Job Type as rows and Experience Range as columns. (in another sheet) I want to find median for each cell in the Pivot Table. How do I do that? e.g. how do I find the median of Salary for all 'Stage Manager' (cell A2) with 'less than 2 years' (cell B1) experience? Please help. Thank you! 回答1: As you've no doubt discovered, the

问题 I have the following vector A: A = [34 35 36 5 6 7 78 79 7 9 10 80 81 82 84 85 86 102 3 4 6 103 104 105 106 8 11 107 201 12 202 203 204]; For n = 2 , I counted the elements larger or equal to 15 within A : D = cellfun(@numel, regexp(char((A>=15)+'0'), [repmat('0',1,n) '+'], 'split')); The above expression gives the following output as duration values: D = [3 2 7 4 6] = [A(1:3) **stop** A(7:8) **stop** A(12:18) **stop** A(22:25) **stop** A(28:33)]; The above algorithm computes the duration