matches

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm trying to find equal sub-string in big list about 50 000 strings, this way fine: var results = myList.FindAll(delegate (string s) { return s.Contains(myString); }); but it also looks for sub-string with part of word, for example, if I'm looking for "you do" it founds also extra "you dont" because contains "you do..". So, this answer to my previous question supposedly should work as i need, but I'm not sure, how to get strings list from regex matches for particular code: foreach (string phrase in matchWordsList) { foreach (string str in

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm new to ARM programming using Keil Microvision V5.12 compiler. I can't compile a simple assembly project getting this error: .\Objects\learn.sct(7): error: L6236E: No section matches selector - no section to be FIRST/LAST. I've tried searching and couldn't find any solution for this problem. This is what I do: Create a project ( without the startup file) Add a new assembly file (learn.s) Click Build Target . Can anybody help? 回答1: There is no 'FIRST' object in your source code. Your scatter file likely looks something like: LR_IROM1

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: For example, I would like to count how many numbers are in a string using a regex like: [0-9] 回答1: Regex.Matches(text, pattern).Count 回答2: Regex.Matches(input, @"\d").Count Since this is going to allocate a Match instance for each match, this may be sub-optimal performance-wise. My instinct would be to do something like the following: input.Count(Char.IsDigit) 回答3: var a = new Regex("[0-9]"); Console.WriteLine(a.Matches("1234").Count); Console.ReadKey(); 回答4: The MatchCollection instance returned from a call to the Matches method on RegEx

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I wonder if it is possible to get MatchCollection with all matches even if there's intersection among them. string input = "a a a"; Regex regex = new Regex("a a"); MatchCollection matches = regex.Matches(input); Console.WriteLine(matches.Count); This code returns 1, but I want it to return 2. How to achive it? Thank you for your help. 回答1: string input = "a a a"; Regex regexObj = new Regex("a a"); Match matchObj = regexObj.Match(input); while (matchObj.Success) { matchObj = regexObj.Match(input, matchObj.Index + 1); } will iterate over the

按书本代码运行出现错误代码： [ INFO:0] Initialize OpenCL runtime... OpenCV(3.4.1) Error: Assertion failed (K == 1 && update == 0 && mask.empty()) in tance.cpp, line 265 Traceback (most recent call last): cv2.error: OpenCV(3.4.1) D:\Build\OpenCV\opencv-3.4.1\modules\core\src\batch_dis tance.cpp:265: error: (-215) K == 1 && update == 0 && mask.empty() in function c v::batchDistance 更改脚本代码为： import numpy as np import cv2 from matplotlib import pyplot as plt img1 = cv2.imread('logo.jpg',0) img2 = cv2.imread('sing.jpg',0) orb = cv2.ORB_create() kp1,des1 = orb.detectAndCompute(img1,None) kp2,des2 = orb

正则表达式在 PHP 中的应用 在 PHP 应用中，正则表达式主要用于： 正则匹配：根据正则表达式匹配相应的内容 正则替换：根据正则表达式匹配内容并替换 正则分割：根据正则表达式分割字符串 在 PHP 中有两类正则表达式函数，一类是 Perl 兼容正则表达式函数，一类是 POSIX 扩展正则表达式函数。二者差别不大，而且推荐使用Perl 兼容正则表达式函数，因此下文都是以 Perl 兼容正则表达式函数为例子说明。 定界符 Perl 兼容模式的正则表达式函数，其正则表达式需要写在定界符中。任何不是字母、数字或反斜线（）的字符都可以作为定界符，通常我们使用 / 作为定界符。具体使用见下面的例子。 提示 尽管正则表达式功能非常强大，但如果用普通字符串处理函数能完成的，就尽量不要用正则表达式函数，因为正则表达式效率会低得多。关于普通字符串处理函数，请参见《 PHP 字符串处理 》。 preg_match() preg_match() 函数用于进行正则表达式匹配，成功返回 1 ，否则返回 0 。 语法： int preg_match( string pattern, string subject [, array matches ] ) 参数说明： 参数 说明 pattern 正则表达式 subject 需要匹配检索的对象 matches 可选，存储匹配结果的数组， $matches[0]

一,认识正则 首先看下面的代码 , $str声明一个字符串 , $patt 匹配规则, preg_match_all()函数用于执行一个全局正则表达式匹配。 <?php $str = 'hi,this is his history'; $patt = '/hi/'; preg_match_all($patt,$str,$matches); print_r($matches); 匹配结果 正则,我们平时用的不多,所以容易忘; 所以在记忆时着重点进行记忆,找谁?怎么找?找几个? 二,常用字符簇 三,单词匹配 <?php $str = 'hi,this is history111**+ '; $patt = '/\Bhi\B/'; preg_match_all($patt,$str,$matches); print_r($matches); $str = 'hi,this is history111**+ '; $patt = '/\bhi\b/'; preg_match_all($patt,$str,$matches); print_r($matches); 四,集合与补集 <?php //集合示例代码 $str = ['13800138000','13426060134','170235','18265432185932545']; //寻找包含0123456 同时又是11位的元素

1、下载swagger-ui GitHub地址： https://github.com/swagger-api/swagger-ui 2、把 swagger-ui 目录下的 dist 放到你的 public 目录下，然后更名为 swagger。 3、修改 swagger 下 index.html 的路径： window.onload = function() { // Begin Swagger UI call region const ui = SwaggerUIBundle({ url : window.location.href.replace(window.location.hash, "").replace(/[^/]+$/, "swagger.json"), dom_id: '#swagger-ui', deepLinking: true, presets: [ SwaggerUIBundle.presets.apis, SwaggerUIStandalonePreset ], plugins: [ SwaggerUIBundle.plugins.DownloadUrl ], layout: "StandaloneLayout" }) // End Swagger UI call region window.ui = ui } 4、在 public 下新建 api

//正则匹配获取img标签src内容-多个 function get_imgAllSrc($tag) { // print_r($tag);die; preg_match_all('/(id|alt|title|src)=("[^"]*")/i', $tag, $matches); $ret = array(); foreach($matches[0] as $i => $v) { $ret[] = trim($matches[2][$i],'"'); } return $ret; } 参考链接： https://blog.csdn.net/qq_27270307/article/details/90702259 来源： https://www.cnblogs.com/heanwanfeng/p/11685719.html

最近在看Spring 源码,源码中多次出现AntPatternMatcher 类, 此类作用用于实现对URL的匹配 关于此类的介绍,其中有些代码是从Apache Ant 那 "借"过来的 PathMatcher implementation for Ant-style path patterns. Examples are provided below. Part of this mapping code has been kindly borrowed from Apache Ant . The mapping matches URLs using the following rules: ? matches one character * matches zero or more characters ** matches zero or more 'directories' in a path Some examples: com/t?st.jsp - matches com/test.jsp but also com/tast.jsp or com/txst.jsp com/*.jsp - matches all .jsp files in the com directory com/**/test.jsp - matches all test.jsp files