mappedsuperclass

Doctrine2 / Symfony2 - Multiple entities on same table

由 南楼画角 提交于 2019-12-23 07:38:29
问题 In a Symfony2 application I have a MainBundle and distinct bundles which can be enabled or not. In the MainBundle I need to have the Model and a basic Entity . In an OtherBundle an Entity with the same table name than Entity in MainBundle . Fixtures in MainBundle need to be loaded with or without the other bundles than MainBundle : MainBundle - Model - Entity (Table name "test") - Fixtures OtherBundle - Entity (Table name "test") - Fixtures OtherBundle2 - Entity (Table name="test") - Fixtures

Can I use a generic Repository for all children of a MappedSuperClass with Spring Data JPA?

由 你离开我真会死。 提交于 2019-12-23 07:24:39
问题 Given the following class structure: @MappedSuperclass @Inheritance(strategy=InheritanceType.TABLE_PER_CLASS) public abstract class Animal {} @Entity public class Dog {} @Entity public class Cat {} With Spring Data JPA , is it possible to use a generic Animal Repository to persist an Animal at runtime without knowing which kind of Animal it is? I know I can do it using a Repository-per-entity and by using instanceof like this: if (thisAnimal instanceof Dog) dogRepository.save(thisAnimal);

“field jdoFieldFlags is conflicting” when using @MappedSuperclass on GAE/J & JPA

由 断了今生、忘了曾经 提交于 2019-12-20 07:26:27
问题 I got an error when querying to the entity extended by mappedsuperclass on GAE/J. MappedSuperClass import java.sql.Timestamp; import javax.persistence.MappedSuperclass; @MappedSuperclass public abstract class AbstractModel { private String lastModifiedBy; private Timestamp createTimestamp; private Timestamp modifyTimestamp; private Integer version; // setters & getters } Entity import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.Table; @Entity @Table(name =

Symfony / Doctrine: add annotiation to Attribute defined in 'MappedSuperclass'

由 笑着哭i 提交于 2019-12-14 03:18:07
问题 Edit: I learned, that there's an annotiation missing for my subclass ('here it's just an ID', thx to GreenLeaf). My actual problem now is, that I don't know, how to override this, I can't get it to work. Original: I just migrated a Symfony 2.0 Application to Symfony 2.2 and get an 'invalid entities'-information in the dev-profiler, regarding an unidirectional one-to-many-association. When using the console with php console doctrine:schema:validate I receive 2 Messages: * The association

JPA @MappedSuperclass in separate JAR in Eclipse

由 喜你入骨 提交于 2019-12-10 09:28:51
问题 I've got a @MappedSuperclass AbstractEntity that I use for all of my @Entity classes. It works perfectly as long as the superclass is in the same Eclipse project as my entities. But since I reuse this superclass among several projects, I just want to break it out into its own JAR file. When I do that (and of course I add the JAR file to the build path), Eclipse gives an error on every one of my @Entity classes: The entity has no primary key attribute defined. Eclipse highlights the @Entity

Apply generic class @MappedSuperclass as targetEntity.Error: @ManyToOne on models.Unit.parent references an unknown entity: models.GenericHierarchic

由 拥有回忆 提交于 2019-12-08 04:02:28
问题 I have generic class that extend other generic class. All of them is @MappedSuperclass . So they dont have own table in database. They are also abstract, so they dont have any objects. They are just skeleton for my entities @Entity My inheritance structure: Generic -> GenericDictionary -> GenericHierarchicalDictionary -> Unit Where Unit is @Entity class and have objects. @Entity public class Unit extends GenericHierarchicalDictionary<Unit> {} Unit entity has hierarchical structure which means

Symfony2 MappedSuperClass and doctrine:generate:entities

由 一世执手 提交于 2019-12-07 06:47:33
问题 I have a "Offer" class (MapperSuperclass) and 2 more classes extending it, "PrivateOffer" and "PublicOffer". The problem I have is, when I run "doctrine:generate:entities" command, both classes "PrivateOffer" and "PublicOffer" are fullfilled with the same properties than the MappedSuperclass "Offer" class, and also it's getter and setter methods. If I remove them and live them only in the "Offer" class, the "doctrine:schema:update" works well as expected, but I need to run the "doctrine

Overriding @Id defined in a @MappedSuperclass with JPA

由 爷，独闯天下 提交于 2019-12-07 03:30:34
问题 I have a class AbstractEntity that is extended by all the entities in my application and basically acts as an Identifier provider. @MappedSuperclass public class AbstractEntity implements DomainEntity { private static final long serialVersionUID = 1L; /** This object's id */ @Id @GeneratedValue(strategy = GenerationType.AUTO) protected long id; @Temporal(TemporalType.TIMESTAMP) @Column(name="creation_date", nullable = false, updatable=false) private Date creationDate = new Date(); /** *

Overriding @Id defined in a @MappedSuperclass with JPA

由 流过昼夜 提交于 2019-12-05 06:20:48
I have a class AbstractEntity that is extended by all the entities in my application and basically acts as an Identifier provider. @MappedSuperclass public class AbstractEntity implements DomainEntity { private static final long serialVersionUID = 1L; /** This object's id */ @Id @GeneratedValue(strategy = GenerationType.AUTO) protected long id; @Temporal(TemporalType.TIMESTAMP) @Column(name="creation_date", nullable = false, updatable=false) private Date creationDate = new Date(); /** * @return the id */ public long getId() { return this.id; } /** * @param id the id to set */ public void setId

Can I use @MappedSuperclass annotation on an interface?

由 泄露秘密 提交于 2019-12-01 23:42:10
问题 I want to group common mappings in an interface , but I cannot use an abstract superclass because my entities already extend another class . So I need an interface like below: @MappedSuperclass public interface NamedEntity { @Column(name = "name") String getName(); void setName(String name); } and I want to use it like below: public class Person { private Long id; private String name; public Long getId(){ return id; } public void setId(Long id){ this.id = id; } public String getName() {
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