manytomanyfield

I am running Django 1.1 and cannot get the "limit_choices_to" option for my ManytoManyField to work. I have two models: class MemberPhoto(ImageModel): title = models.CharField(_('title'), max_length=255, blank=True, null=True) caption = models.CharField(_('caption'), max_length=255, blank=True, null=True) date_added = models.DateTimeField(_('date added'), default=datetime.now, editable=False) member = models.ForeignKey(User) def __unicode__(self): return u'%s (%s)' % (self.member.username, self.id) and class lock(models.Model): user = models.ForeignKey(User, related_name="owner") to_user =

Suppose i have : class Album(models.Model): photos = models.ManyToManyField('myapp.Photo') photo_count = models.IntegerField(default = 0) class Photo(models.Model): photo = models.ImageField(upload_to = 'blahblah') What is want is, everytime i call .add() method, increment the photo_count on Album class, so i'm thinking to override .add() method. The problem is, i can't import the .add() 's class since it is inside a method, so it is like def->class->def . So is there anyway to override .add() ? Or there is a better way to do this? You can use django's signals and write a signal handler that

Given these two Models: class Item(models.Model): timestamp = models.DateTimeField() class Source(models.Model): items = models.ManyToManyField(Item, related_name="sources") I can find all of a Source's Items before a given time using this: source.items.filter(timestamp__lte=some_datetime) How do I efficiently remove all of the items that match that query? I suppose I could try something like this: items_to_remove = list(source.items.filter(timestamp__lte=some_datetime)) source.items.remove(*items_to_remove) but that seems bad. Note that I do not want to delete these items, since they may also

I have the following Django model: class Icon(models.Model): name = models.CharField(max_length=200,null=False,blank=False) class Post(models.Model): icons = models.ManyToManyField(Icon) When I write the following code: post = Post() icons = [] icon_id = form.cleaned_data['icon_1'] if (icon_id): i = Icon.objects.get(id=icon_id) icons.append(i) icon_id = form.cleaned_data['icon_2'] if (icon_id): i = Icon.objects.get(id=icon_id) icons.append(i) post.icons = icons post.save() It works fine for the most part, creating a Post object and the two Icon objects. However, if the icon_id is, say, 1 in

I've got a ManyToManyField in a user object and it's used to map the users that user is following. I'm trying to show a subset list of who they have most recently followed. Is there a trick in .order_by() that will allow me to sort by the id of the ManyToManyField? The data is there, right? # (people the user is following) following = models.ManyToManyField(User, related_name="following", blank=True) theuser.following.filter(user__is_active=True).order_by("user__id") That will give me a list of the users the user is following but ordered by when they joined. I want the order of the following

class Food_Tag(models.Model): name = models.CharField(max_length=200) related_tags = models.ManyToManyField('self', blank=True, symmetrical=False, through='Tag_Relation') def __unicode__(self): return self.name class Tag_Relation(models.Model): source = models.ForeignKey(Food_Tag, related_name='source_set') target = models.ForeignKey(Food_Tag, related_name='target_set') is_a = models.BooleanField(default=False); # True if source is a target has_a = models.BooleanField(default=False); # True if source has a target I want to be able to get the relations between Food_Tags like: >>> steak = Food

I've made a model (models.py): class opetest(models.Model): name = models.CharField(max_length=200) author = models.ForeignKey(User, related_name='author') description = models.TextField(u'Test description', help_text = u'Some words about quiz') pub_date = models.DateTimeField('date published', blank=False) vacancies = models.ManyToManyField(Vacancy, blank=True) students = models.ManyToManyField(User, blank=True, related_name='opetests') #This field I want to edit on "User change page" estimate = models.IntegerField(default = 0, help_text = u'Estimate time in hours. \'0\' - unlimited') then I