manual

Manually sort a list of 10 integers in python

假如想象 提交于 2021-02-16 19:50:18
问题 I'm fairly new to programming; I've only been studying Python for a few weeks. I've been given an exercise recently that asks me to generate a list of integers, and then manually sort the numbers from lowest to highest in a separate list. import random unordered = list(range(10)) ordered = [] lowest = 0 i = 0 random.shuffle(unordered) lowest = unordered[0] while i in unordered: if unordered[i] < lowest: lowest = unordered[i] i += 1 if i >= len(unordered): i = 0 ordered.append(lowest)

Manually sort a list of 10 integers in python

∥☆過路亽.° 提交于 2021-02-16 19:50:05
问题 I'm fairly new to programming; I've only been studying Python for a few weeks. I've been given an exercise recently that asks me to generate a list of integers, and then manually sort the numbers from lowest to highest in a separate list. import random unordered = list(range(10)) ordered = [] lowest = 0 i = 0 random.shuffle(unordered) lowest = unordered[0] while i in unordered: if unordered[i] < lowest: lowest = unordered[i] i += 1 if i >= len(unordered): i = 0 ordered.append(lowest)

How to manually sort a list of numbers in Python?

折月煮酒 提交于 2020-04-13 17:04:42
问题 Specs: Ubuntu 13.04, Python 3.3.1 Background: total beginner to Python, came across this "manual sorting" problem. What I was asked to do: "Have the user enter 3 numeric values and store them in 3 different variables. Without using lists or sorting algorithms, manually sort these 3 numbers from smallest to largest." What I was able to come up with: number = input("Please enter 3 numbers: ") number = list(number) a = int(number[0]) b = int(number[1]) c = int(number[2]) new_l = [] if a > b and

How to manually sort a list of numbers in Python?

青春壹個敷衍的年華 提交于 2020-04-13 17:04:40
问题 Specs: Ubuntu 13.04, Python 3.3.1 Background: total beginner to Python, came across this "manual sorting" problem. What I was asked to do: "Have the user enter 3 numeric values and store them in 3 different variables. Without using lists or sorting algorithms, manually sort these 3 numbers from smallest to largest." What I was able to come up with: number = input("Please enter 3 numbers: ") number = list(number) a = int(number[0]) b = int(number[1]) c = int(number[2]) new_l = [] if a > b and

fancybox manual call to a specific target

生来就可爱ヽ(ⅴ<●) 提交于 2020-01-24 19:44:44
问题 I implemented the manual-script from fancybox: $("#manual2").click(function() { $.fancybox([ 'http://farm5.static.flickr.com/4044/4286199901_33844563eb.jpg', 'http://farm3.static.flickr.com/2687/4220681515_cc4f42d6b9.jpg', { 'href' : 'http://farm5.static.flickr.com/4005/4213562882_851e92f326.jpg', 'title' : 'Lorem ipsum dolor sit amet, consectetur adipiscing elit' } ], { 'padding' : 0, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'image', 'changeFade' : 0 }); }); now I'm

How Can I assign a sequence value to a sqlite field when the field UID value is NULL

我的未来我决定 提交于 2020-01-07 05:31:12
问题 How I can assign a sequence value to a field "UID" which is NUll in existing sqlite table, for example table: FOO name UID A 1 B 2 C 100 D NULL E NULL F NULL what I want is table: FOO name UID A 1 B 2 C 100 D 101 E 102 F 103 Can some body help? I want to seek an alternative for using autoincrement on my own reason... thanks! 回答1: Register a function that returns the number of times it's called, and then do UPDATE FOO SET UID = 100 + increment() WHERE UID IS NULL 回答2: a drafted approach in my

Where can I find informations about iOS image file naming in official manual?

亡梦爱人 提交于 2020-01-06 08:37:31
问题 Some of naming is described here: http://www.weston-fl.com/blog/?p=840/ However, I want to check this from official manual. Where can I find this info from official manual? 回答1: The official Apple document is Technical Q&A QA1686 “App Icons on iPad and iPhone”. 来源: https://stackoverflow.com/questions/9356874/where-can-i-find-informations-about-ios-image-file-naming-in-official-manual

Computing the mode (most frequent element) of a set in linear time?

点点圈 提交于 2020-01-01 09:53:34
问题 In the book "The Algorithm Design Manual" by Skiena, computing the mode (most frequent element) of a set, is said to have a Ω( n log n ) lower bound (this puzzles me), but also (correctly i guess) that no faster worst-case algorithm exists for computing the mode. I'm only puzzled by the lower bound being Ω( n log n ). See the page of the book on Google Books But surely this could in some cases be computed in linear time (best case), e.g. by Java code like below (finds the most frequent

Is there a CakePHP offline manual

别等时光非礼了梦想. 提交于 2019-12-31 10:23:44
问题 There used to be, but there don't seem to be any direct links. A little digging around revealed some answers which I thought it would be useful to share. These are links to the manual in one page - useful for offline use or creating a PDF using Dardo Sordi Bogado's build script. 1.2 Manual in one page https://web.archive.org/web/20120730003805/http://book.cakephp.org/complete/3/The-Manual 1.3 Manual in one page https://web.archive.org/web/20120730004040/http://book.cakephp.org/complete/876