loops

问题 I'm wondering why my code doesn't play the loop for the video. Everything is working except the loop option. And I really need it. Thanks a lot. <script src="jsapi.js"></script> <script src="swfobject.js"></script> <div id="ytapiplayer">You need Flash player 8+ and JavaScript enabled to view this video.</div> <script type="text/javascript"> google.load("swfobject", "2.1"); function onYouTubePlayerReady(playerId) { ytplayer = document.getElementById("myytplayer"); ytplayer.playVideo();

问题 I'm wondering why my code doesn't play the loop for the video. Everything is working except the loop option. And I really need it. Thanks a lot. <script src="jsapi.js"></script> <script src="swfobject.js"></script> <div id="ytapiplayer">You need Flash player 8+ and JavaScript enabled to view this video.</div> <script type="text/javascript"> google.load("swfobject", "2.1"); function onYouTubePlayerReady(playerId) { ytplayer = document.getElementById("myytplayer"); ytplayer.playVideo();

问题 I'm wondering why my code doesn't play the loop for the video. Everything is working except the loop option. And I really need it. Thanks a lot. <script src="jsapi.js"></script> <script src="swfobject.js"></script> <div id="ytapiplayer">You need Flash player 8+ and JavaScript enabled to view this video.</div> <script type="text/javascript"> google.load("swfobject", "2.1"); function onYouTubePlayerReady(playerId) { ytplayer = document.getElementById("myytplayer"); ytplayer.playVideo();

问题 Is it possible to compute several dot products without a loop? say you have the following: a = randn(100, 3, 3) b = randn(100, 3, 3) I want to get an array z of shape (100, 3, 3) such that for all i z[i, ...] == dot(a[i, ...], b[i, ...]) in other words, which verifies: for va, vb, vz in izip(a, b, z): assert (vq == dot(va, vb)).all() The straightforward solution would be: z = array([dot(va, vb) for va, vb in zip(a, b)]) which uses an implicit loop (list comprehension + array). Is there a more

问题 Is it possible to compute several dot products without a loop? say you have the following: a = randn(100, 3, 3) b = randn(100, 3, 3) I want to get an array z of shape (100, 3, 3) such that for all i z[i, ...] == dot(a[i, ...], b[i, ...]) in other words, which verifies: for va, vb, vz in izip(a, b, z): assert (vq == dot(va, vb)).all() The straightforward solution would be: z = array([dot(va, vb) for va, vb in zip(a, b)]) which uses an implicit loop (list comprehension + array). Is there a more

问题 This question already has answers here : How to compile a C project in C99 mode? (4 answers) Closed 4 years ago . I am getting the below error, what is std=c99/std=gnu99 mode? source Code: #include <stdio.h> void funct(int[5]); int main() { int Arr[5]={1,2,3,4,5}; funct(Arr); for(int j=0;j<5;j++) printf("%d",Arr[j]); } void funct(int p[5]) { int i,j; for(i=6,j=0;i<11;i++,j++) p[j]=i; } Error Message: hello.c: In function ‘main’: hello.c:11:2: error: ‘for’ loop initial declarations are only

问题 This question already has answers here : How to compile a C project in C99 mode? (4 answers) Closed 4 years ago . I am getting the below error, what is std=c99/std=gnu99 mode? source Code: #include <stdio.h> void funct(int[5]); int main() { int Arr[5]={1,2,3,4,5}; funct(Arr); for(int j=0;j<5;j++) printf("%d",Arr[j]); } void funct(int p[5]) { int i,j; for(i=6,j=0;i<11;i++,j++) p[j]=i; } Error Message: hello.c: In function ‘main’: hello.c:11:2: error: ‘for’ loop initial declarations are only

问题 This question already has answers here : How to compile a C project in C99 mode? (4 answers) Closed 4 years ago . I am getting the below error, what is std=c99/std=gnu99 mode? source Code: #include <stdio.h> void funct(int[5]); int main() { int Arr[5]={1,2,3,4,5}; funct(Arr); for(int j=0;j<5;j++) printf("%d",Arr[j]); } void funct(int p[5]) { int i,j; for(i=6,j=0;i<11;i++,j++) p[j]=i; } Error Message: hello.c: In function ‘main’: hello.c:11:2: error: ‘for’ loop initial declarations are only

问题 This question already has answers here : How to compile a C project in C99 mode? (4 answers) Closed 4 years ago . I am getting the below error, what is std=c99/std=gnu99 mode? source Code: #include <stdio.h> void funct(int[5]); int main() { int Arr[5]={1,2,3,4,5}; funct(Arr); for(int j=0;j<5;j++) printf("%d",Arr[j]); } void funct(int p[5]) { int i,j; for(i=6,j=0;i<11;i++,j++) p[j]=i; } Error Message: hello.c: In function ‘main’: hello.c:11:2: error: ‘for’ loop initial declarations are only

问题 This question already has answers here : How to compile a C project in C99 mode? (4 answers) Closed 4 years ago . I am getting the below error, what is std=c99/std=gnu99 mode? source Code: #include <stdio.h> void funct(int[5]); int main() { int Arr[5]={1,2,3,4,5}; funct(Arr); for(int j=0;j<5;j++) printf("%d",Arr[j]); } void funct(int p[5]) { int i,j; for(i=6,j=0;i<11;i++,j++) p[j]=i; } Error Message: hello.c: In function ‘main’: hello.c:11:2: error: ‘for’ loop initial declarations are only