logic

问题 I have spent the last 5 hours searching for an answer. Even though I have found many answers they have not helped in any way. What I am basically looking for is a mathematical, arithmetic only representation of the bitwise XOR operator for any 32bit unsigned integers. Even though this sounds really simple, nobody (at least it seems so) has managed to find an answer to this question. I hope we can brainstorm, and find a solution together. Thanks. 回答1: XOR any numerical input a + b - ab(1 + a +

问题 I am currently working on logic synthesis- given a high level description of a hardware I wish to convert it into a circuit of gates,flip flops etc. I am not very much familiar with the theory. I searched the internet, but most of them refer to online book stores. Could someone please refer me to any good tutorials on the net? Any help regarding it would be appreciated. 回答1: A flow primer can be found here: Advanced ASIC Chip Synthesis Using Synopsys® Design Compiler® Physical Compiler® and

问题 Is the following theorem provable in Coq? And if not, is there a way to prove it isn't provable? Theorem not_for_all_is_exists: forall (X : Set) (P : X -> Prop), ~(forall x : X, ~ P x) -> (exists x: X, P x). I know this related relationship is true: Theorem forall_is_not_exists : (forall (X : Set) (P : X -> Prop), (forall x, ~(P x)) -> ~(exists x, P x)). Proof. (* This could probably be shortened, but I'm just starting out. *) intros X P. intros forall_x_not_Px. unfold not. intros exists_x_Px

问题 I have found many solutions about all posible combinations between array values but I need something different, I hope you could support me. Basically is to create all posible objects that combine array keys with true|false values, something like this: Input: (Should return an array of 32 objects, 2exp5, two posible values in 5 keys) let properties = ['arm','lens','season','food','size']; Output: let combinations = [ {"arm": "false","lens": "false","season": "false","food": "false","size":

问题 So I was writing a rock paper scissors game when I came to writing this function: a is player one's move, b is player two's move. All I need to figure out is if player one won, lost, or tied. //rock=0, paper=1, scissors=2 processMove(a, b) { if(a == b) ties++; else { if(a==0 && b==2) wins++; else if(a==0 && b==1) losses++; else if(a==1 && b==2) losses++; else if(a==1 && b==0) wins++; else if(a==2 && b==1) wins++; else if(a==2 && b==0) losses++; } } My question is: What's the most elegant way

问题 I thought I understood these two singleton values in Python until I saw someone using return l1 or l2 in the code, where both l1 and l2 are linked list object, and (s)he wanted to return l1 if it is not None, otherwise, return l2. This piece of code is good because it is quite short and seems easy to understand. Then, I write some code to figure out what is going one here. print ( True or 'arbitrary' ) #True print ( False or 'arbitrary') #arbitrary print ( None or 'arbitrary' ) #arbitrary The

问题 How is it possible to traverse through any given sentence word by word? Is there any in-built functions in java? I have no idea how to begin. 回答1: Something like this: String sentence = "Your sentence here."; String[] words = sentence.split("\\s+"); // splits by whitespace for (String word : words) { System.out.println(word); } 回答2: A lot of people are suggesting to split on spaces, but even this very sentence contains commas, etc. You should split on more than just spaces; split on

问题 How is it possible to traverse through any given sentence word by word? Is there any in-built functions in java? I have no idea how to begin. 回答1: Something like this: String sentence = "Your sentence here."; String[] words = sentence.split("\\s+"); // splits by whitespace for (String word : words) { System.out.println(word); } 回答2: A lot of people are suggesting to split on spaces, but even this very sentence contains commas, etc. You should split on more than just spaces; split on

问题 Assume the matrices to be of the form, The required output on stdout using C language should be My code: #include<stdio.h> int main(void) { int size, i=0, j=0; printf("Enter the size of the array:"); scanf("%d",&size); int A[size][size], B[size][size], C[size][size]; //Entering the values in A[][] printf("enter the elements of Array A:\n"); for(int i=0; i<size; i++) for(int j=0; j<size; j++) scanf("%d",&A[i][j]); //Entering the values in B[][] printf("enter the elements of Array B:\n"); for

问题 So im trying to add 1+2+3... and so on...without using brute force. Y=∑_1^100▒X_i, the numbers Xi are stored in consecutive memory locations starting at location 100. I am using the IAS instruction set: I just cant seem to get this done. I dont even know where to begin, no real loops or if statements 回答1: You have 4 different possible approaches, that I will write in x86 since my knowledge of IAS is very limited, but you can apply the same logic 1/ Brute force xor eax, eax mov ecx, 100