How to manually flatten a list in Racket (Scheme)
来源： https://stackoverflow.com/questions/28753729/how-to-manually-flatten-a-list-in-racket-scheme
list-processing
Given a list, how can I perform some transformation only on sub-lists whose each two elements satisfy a binary predicate?
来源： https://stackoverflow.com/questions/64066202/given-a-list-how-can-i-perform-some-transformation-only-on-sub-lists-whose-each
Ramda JS best way to get the tightest geographic bound
问题 I am attempting to use the Google Places API in order to get the place name of a location I am in. The returned data structure has the following types: descriptor1: 'street number' | 'neighborhood' | 'postcode' | 'route' | 'locality' | 'postal_town' | 'administrative_area_level_2' | 'administrative_area_level_1' | 'country' places: [ { address_components: [{ long_name: 'string', short_name: 'string', types: { 0: descriptor1, 1?: descriptor2 } }], other_fields not relevant here } ] There is no
List of dictionary in python as HTML Table format
问题 I have list of dictionary as the below format [{'duration': 0.7, 'project_id': 3, 'resource': u'Arya Stark', 'activity': u'Development'}, {'duration': 0.9, 'project_id': 4, 'resource': u'Ned Stark', 'activity': u'Development'}, {'duration': 2.88, 'project_id': 7, 'resource': u'Robb Stark', 'activity': u'Development'}, {'duration': 0.22, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'}, {'duration': 0.3, 'project_id': 9, 'resource': u'Jon Snow', 'activity': u'Support'}, {
What is the most elegant way to remove a path from the $PATH variable in Bash?
Or more generally, how do I remove an item from a colon-separated list in a Bash environment variable? I thought I had seen a simple way to do this years ago, using the more advanced forms of Bash variable expansion, but if so I've lost track of it. A quick search of Google turned up surprisingly few relevant results and none that I would call "simple" or "elegant". For example, two methods using sed and awk, respectively: PATH=$(echo $PATH | sed -e 's;:\?/home/user/bin;;' -e 's;/home/user/bin:\?;;') PATH=!(awk -F: '{for(i=1;i<=NF;i++){if(!($i in a)){a[$i];printf s$i;s=":"}}}'<<<$PATH) Does
What is the most elegant way to remove a path from the $PATH variable in Bash?
问题 Or more generally, how do I remove an item from a colon-separated list in a Bash environment variable? I thought I had seen a simple way to do this years ago, using the more advanced forms of Bash variable expansion, but if so I\'ve lost track of it. A quick search of Google turned up surprisingly few relevant results and none that I would call \"simple\" or \"elegant\". For example, two methods using sed and awk, respectively: PATH=$(echo $PATH | sed -e \'s;:\\?/home/user/bin;;\' -e \'s;