linked-list

问题 First, I defined my node using a struct called listrec. So each node has 3 parts: prev (used to store the address of the previous node), value (used to store the value), and next (used to store the address of next node). #include <iostream> using namespace std; struct listrec { struct listrec *prev; float value; struct listrec *next; }; listrec *head, *tail; Then, I used a loop to initialize the linked list (based on the number of nodes requested by the user. for (float i = 0; i < number; i++

问题 I want to implement the sorted bag(collection) data structure(with a singly-linked list) in C++ and I have a problem when I want to test the add function. This is the test: SortedBag sb(relation1); (relation1 is e1<=e2) sb.add(5); std::cout << sb.size()<<" "; sb.add(6); std::cout << sb.size() << " "; sb.add(0); std::cout << sb.size() << " "; sb.add(5); std::cout << sb.size() << " "; sb.add(10); std::cout << sb.size() << " "; sb.add(8); std::cout << sb.size() << " "; And it will print 1 2 3 3

问题 I've just started learning about graphs, and something that's confusing me is why we need to use external data structures (like matrices or lists) to store which vertexes of the graph are connected to other vertices. Why can't each vertex just hold references to the vertices its connected to, like the way nodes do in a decision tree? That, to me, seems more intuitive. Thanks! 回答1: Well, this comes from a design philosophy. Whenever you have a many to many relationships, you introduce a broker

问题 I want to create a linked list of vectors and with the help of GLUT library get the positions of the clicks and append them to the linked list. These are the structs i wrote. typedef struct vector{int x;int y;}Vector; typedef struct VectorList{Vector X; struct VectorList*next; }node_v; I globally defined a P vector and linked list of vectors prev. Vector P; node_v * prev=NULL; Inside the mouse callback function _mouse_CB everytime left mouse button is clicked, i want to update the P vector

问题 This document says std::list is inefficient: std::list is an extremely inefficient class that is rarely useful. It performs a heap allocation for every element inserted into it, thus having an extremely high constant factor, particularly for small data types. Comment: that is to my surprise. std::list is a doubly linked list, so despite its inefficiency in element construction, it supports insert/delete in O(1) time complexity, but this feature is completely ignored in this quoted paragraph.

问题 In main function read the data and sort according to number(ascending order using insertion sort) in a linked list. typedef struct { char * name; int no; } tele; In this part the elements of the structure ‘tele’ are to be put in a linked list. typedef struct _node{ tele data; struct _node *next; } node; Input File (First five lines): 80043 CHEBIYYAM 80131 SHUKLA 80200 GANGARAPU 85400 GAURAV 80001 MUDIT Code: #include <stdio.h> #include <stdlib.h> #include <string.h> #define row 100 // total

问题 In main function read the data and sort according to number(ascending order using insertion sort) in a linked list. typedef struct { char * name; int no; } tele; In this part the elements of the structure ‘tele’ are to be put in a linked list. typedef struct _node{ tele data; struct _node *next; } node; Input File (First five lines): 80043 CHEBIYYAM 80131 SHUKLA 80200 GANGARAPU 85400 GAURAV 80001 MUDIT Code: #include <stdio.h> #include <stdlib.h> #include <string.h> #define row 100 // total

问题 In main function read the data and sort according to number(ascending order using insertion sort) in a linked list. typedef struct { char * name; int no; } tele; In this part the elements of the structure ‘tele’ are to be put in a linked list. typedef struct _node{ tele data; struct _node *next; } node; Input File (First five lines): 80043 CHEBIYYAM 80131 SHUKLA 80200 GANGARAPU 85400 GAURAV 80001 MUDIT Code: #include <stdio.h> #include <stdlib.h> #include <string.h> #define row 100 // total

问题 hey for some reason my linked list is printing in the reversed ordear for example if my input is 2->4->6 my output is 6->4->2 list* add_int_list(list* a,int b) { list *temp; temp = (list*)malloc(sizeof(list*)); temp->next = NULL; if (a->next == NULL)//insert to the first node { temp->data = b; temp->next = a; a = temp; } else { temp->data = b; temp->next = a; a = temp;//I think the problem is here, couldnt find how to fix } 回答1: For starters in this statement temp = (list*)malloc(sizeof(list*

问题 hey for some reason my linked list is printing in the reversed ordear for example if my input is 2->4->6 my output is 6->4->2 list* add_int_list(list* a,int b) { list *temp; temp = (list*)malloc(sizeof(list*)); temp->next = NULL; if (a->next == NULL)//insert to the first node { temp->data = b; temp->next = a; a = temp; } else { temp->data = b; temp->next = a; a = temp;//I think the problem is here, couldnt find how to fix } 回答1: For starters in this statement temp = (list*)malloc(sizeof(list*