keycode

Are they really the virtual codes?

流过昼夜 提交于 2019-12-05 11:54:25
Virtual key codes for some keys like shift, [ , ],Del etc are displayed as a different value in java compared to C++/C. For example : Key Java C / C++ Shift 16 160 [ 91 219 ] 93 221 \ 92 220 Del 127 46 Window 524 91 What is the reason for this ? Are these codes the virtual codes or they are a different type ? For the keys including alphabets,numbers,the function keys(F1-F12),backspace,`,etc are the same. I might be misunderstanding a concept,in that case please clarify. Checked in C/C++ KBDLLHOOKSTRUCT * kbhook = (KBDLLHOOKSTRUCT *) lParam; printf("%u\n",kbhook->vkCode); Checked in Java

How to convert a Windows native virtual key code to Qt::Key?

自闭症网瘾萝莉.ら 提交于 2019-12-05 09:46:03
I am working on a program which communicates with a windows native program, so it needs the actucal native virtual key code. How to convert from a Windows native virtual key code to Qt::Key? Michael Simpson If you have access to a QKeyEvent , key() and nativeVirtualKey may help. From Assistant, qthelp://com.trolltech.qt.472/qdoc/qkeyevent.html#details sat4ripe Look in the file qt\src\gui\kernel\qkeymapper_win.cpp 来源: https://stackoverflow.com/questions/7482213/how-to-convert-a-windows-native-virtual-key-code-to-qtkey

Form submit on keyCode == “enter” (13)

血红的双手。 提交于 2019-12-05 09:36:15
I need to submit the content of a form when I press the Enter key, but only if the form has no error message. I built up the following function: $(targetFormID).submit(function (e) { var mess = error_m(targetDiv); if (e.keyCode == 13 && mess.length > 0) { e.preventDefault(); e.stopPropagation(); } if (mess.length == 0 && e.keyCode == 13) $(targetFormID).submit(); }); In this function the mess variable is getting the error message returned by function error_m , the rest is simple code condtion but it doesn't work. Need some help with this!! Submitting the form when the Enter key is pressed is

Send NSEvent to background app

时光怂恿深爱的人放手 提交于 2019-12-05 05:19:11
I need to send the key combo ^⌘C to a background app with the bundle identifier com.company.app . The key combo should then activate a menu item in that application. Unfortunately, I have no clue how to do that. Some research pointed me to the NSEvent and CGEvent API using CGEventPostToPSN() , but I was unable to get it work correctly, as I don't know how to set up the key combo. CGEventPost() didn't seem to work with the events I created, even if the desired app is the active one. Here is the code I eventually came up with but that doesn't work: CGWindowID windowNumber; NSEvent *event =

jQuery Trigger keyCode Ctrl+Shift+z & Ctrl+z in wysiwyg textarea

耗尽温柔 提交于 2019-12-05 04:53:33
i was wondering how do i trigger the event keyCode composed by Ctrl+z and the event keycode composed by Ctrl+Shift+z ? If you want to trigger the event then it should be something like this: HTML <!DOCTYPE html> <html> <head> </head> <body> <input type=button value=CTRL+SHIFT+Z id=bcsz /> <input type=button value=CTRL+Z id=bcz /> <textarea id=t ></textarea> </body> </html> JavaScript var t = document.getElementById('t'), //textarea bcsz = document.getElementById('bcsz'), //button ctrl shift z bsz = document.getElementById('bcz'), // button ctrl z csz = document.createEvent('KeyboardEvents'), /

JavaScript keycode allow number and plus symbol only

流过昼夜 提交于 2019-12-05 00:59:04
I have this JavaScript function that is used to force user only type number in the textbox. Right now and I want to modify this function so it will allow the user to enter plus (+) symbol. How to achieve this? //To only enable digit in the user input function isNumberKey(evt) { var charCode = (evt.which) ? evt.which : event.keyCode if (charCode > 31 && (charCode < 48 || charCode > 57)) return false; return true; } Since the '+' symbol's decimal ASCII code is 43, you can add it to your condition. for example : function isNumberKey(evt) { var charCode = (evt.which) ? evt.which : event.keyCode if

form表单自动提交问题

一世执手 提交于 2019-12-04 23:09:45
1.form表单会自动提交的几种情况 1)表单里有一个type="submit"的按钮,回车键生效 2)表单里只有一个type="text"的input,回车键生效。 2.form表单自动提交的请求 如果form表单没有设置action属性,自动提交的请求是当前页面地址,即页面会自动刷新 详细分析参考:http://www.360doc.com/content/15/0121/23/14009801_442697693.shtml 另附上javascript中event.keycode。 keycode 8 = BackSpace BackSpace keycode 9 = Tab Tab keycode 12 = Clear keycode 13 = Enter keycode 16 = Shift_L keycode 17 = Control_L keycode 18 = Alt_L keycode 19 = Pause keycode 20 = Caps_Lock keycode 27 = Escape Escape keycode 32 = space space keycode 33 = Prior keycode 34 = Next keycode 35 = End keycode 36 = Home keycode 37 = Left keycode 38 = Up

vue中Enter触发登录事件和javascript中Enter触发点击事件

为君一笑 提交于 2019-12-04 18:36:48
created(){ window.addEventListener('keydown', this.handleKeyDown, true)//开启监听键盘按下事件 } 在methods中当keyCode的值为13触发登录绑定的事件即可 // 登录登录登录 async changeUser () { // 消息提示只弹出一个框 this.$message.closeAll() let s = checkPhone(this.dlPhone, 1) // 手机号 if (s.code === 500) { this.$message(s.msg) return } let ss = checkPhone(this.dlPassword, 2) // 密码 if (ss.code === 500) { this.$message(ss.msg) return } // if (s.code == 200 && ss.code == 200) { let res = await this.$http.post('/api/login', { mobile: this.dlPhone, password: this.dlPassword }) if (res.data.code === 200) { this.show = 2 this.$store.commit('CHANGE

pc端自动化

谁都会走 提交于 2019-12-04 18:20:20
一、为什么要使用自动化? 1.提高工作效率,节约时间,解脱双手。 二、自动化的使用场景是什么? 1.重复且大量的工作 2.此工作的工作方式是有一定的规律可循的 三、自动化的使用步骤 1.创建java项目 2.编写Robots类 1 import java.awt.AWTException; 2 import java.awt.Toolkit; 3 import java.awt.Robot; 4 import java.awt.event.InputEvent; 5 import java.awt.event.KeyEvent; 6 7 public class Robots { 8 /** 9 * 移动鼠标的方法 10 */ 11 public static final void move(int x,int y,int time) { 12 try { 13 /**创建工具包对象*/ 14 Toolkit toolkit = Toolkit.getDefaultToolkit(); 15 /**创建自动化对象*/ 16 Robot robot = new Robot(); 17 robot.mouseMove(x, y); //将鼠标移动到指定位置 18 robot.delay(time); //鼠标点击后的睡眠时间 19 }catch (Exception e) { 20

Xkb: How to increase the number of KeySyms in the client map of an XkbDescRec keyboard description?

别来无恙 提交于 2019-12-04 15:10:12
I'm trying to programmatically modify some of the properties of my xkb keyboard mapping in X11. In the XkbClientMapRec struct map member of the XkbDescRec struct, we have the following members: typedef struct { /* Client Map */ unsigned char size_types; /* # occupied entries in types */ unsigned char num_types; /* # entries in types */ XkbKeyTypePtr types; /* vector of key types used by this keymap */ unsigned short size_syms; /* length of the syms array */ unsigned short num_syms; /* # entries in syms */ KeySym * syms; /* linear 2d tables of keysyms, 1 per key */ XkbSymMapPtr key_sym_map; /*