keyboardinterrupt

问题 I'm writing a command line utility in Python which, since it is production code, ought to be able to shut down cleanly without dumping a bunch of stuff (error codes, stack traces, etc.) to the screen. This means I need to catch keyboard interrupts. I've tried using both a try catch block like: if __name__ == '__main__': try: main() except KeyboardInterrupt: print 'Interrupted' sys.exit(0) and catching the signal itself (as in this post): import signal import sys def sigint_handler(signal,

问题 I'm running 64-bit Python 2.7.3 on Win7 64-bit. I can reliably crash the Python interpreter by doing this: >>> from scipy import stats >>> import time >>> time.sleep(3) and pressing Control-C during the sleep. A KeyboardInterrupt is not raised; the interpreter crashes. The following is printed: forrtl: error (200): program aborting due to control-C event Image PC Routine Line Source libifcoremd.dll 00000000045031F8 Unknown Unknown Unknown libifcoremd.dll 00000000044FC789 Unknown Unknown

问题 Is there some way in Python to capture KeyboardInterrupt event without putting all the code inside a try - except statement? I want to cleanly exit without trace if user presses Ctrl + C . 回答1: Yes, you can install an interrupt handler using the module signal, and wait forever using a threading.Event: import signal import sys import time import threading def signal_handler(signal, frame): print('You pressed Ctrl+C!') sys.exit(0) signal.signal(signal.SIGINT, signal_handler) print('Press Ctrl+C

问题 How can I handle KeyboardInterrupt events with python\'s multiprocessing Pools? Here is a simple example: from multiprocessing import Pool from time import sleep from sys import exit def slowly_square(i): sleep(1) return i*i def go(): pool = Pool(8) try: results = pool.map(slowly_square, range(40)) except KeyboardInterrupt: # **** THIS PART NEVER EXECUTES. **** pool.terminate() print \"You cancelled the program!\" sys.exit(1) print \"\\nFinally, here are the results: \", results if __name__ =