jpql

How to get the SQL String From JPQLQuery

别说谁变了你拦得住时间么 提交于 2020-05-27 05:17:24
问题 I'm using EclipseLink. I've a JPQLquery and I want to get the sql String.. Now I'm doing in this way: EJBQueryImpl qi = (EJBQueryImpl)jpqlQuery; String sqlQueryString = qi.getDatabaseQuery().getSQLString(); The problem is that in the sqlQueryString the constant are replaced with ? I've tried to get the values navigating the expressions trees ( getSelectionCriteria() and getHavingCriteria() ) but in this way I loose the type... Do any one ever have a problem like this one? 回答1: Quoted from the

MySQL's LPAD String Function in JPA Query?

谁说胖子不能爱 提交于 2020-05-15 09:57:11
问题 May I know how to convert the following MySQL SQL to JPA query? SELECT * FROM ORDER WHERE LPAD(BATCH, 2, ' ') < LPAD('X', 2, ' ') ; What I couldn't figure out is the LPAD() string function in JPA. Do you have any idea? 回答1: I know that is a very old post, but i am always be questioned by some colleagues when they are building JPA queries how to do the same thing. Almost never you will find a perfect fit function to do what do you want. But, using some logic you can get the same result, in

Spring Data JPA findBy a collection [duplicate]

本小妞迷上赌 提交于 2020-05-13 06:15:06
问题 This question already has answers here : Spring CrudRepository findByInventoryIds(List<Long> inventoryIdList) - equivalent to IN clause (3 answers) Closed 2 years ago . Im working on a route planing system in Java, using JPA. I need to create a findBy method to find an route by a list of the cities its containing. Here are the classes: @Entity public class Route { @ManyToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER) private List<City> cities = new ArrayList<>(); . . } @Entity

How can I avoid the Warning “firstResult/maxResults specified with collection fetch; applying in memory!” when using Hibernate?

百般思念 提交于 2020-05-12 07:30:08
问题 I'm getting a warning in the Server log "firstResult/maxResults specified with collection fetch; applying in memory!" . However everything working fine. But I don't want this warning. My code is public employee find(int id) { return (employee) getEntityManager().createQuery(QUERY).setParameter("id", id).getSingleResult(); } My query is QUERY = "from employee as emp left join fetch emp.salary left join fetch emp.department where emp.id = :id" 回答1: Reason for this warning is that when fetch

JPA: How to fetch eagerly an embedded element collection

可紊 提交于 2020-05-10 08:58:34
问题 Consider the following model @Entity // JPA and JAXB annotations here public class Employee implements Serializable { // other fields, annotations, stuffs ... @ElementCollection(fetch = FetchType.LAZY, targetClass = Address.class) @CollectionTable(name = "employee_address", schema = "hris", joinColumns = @JoinColumn(name = "employee_id", nullable = false, referencedColumnName = "employee_id", foreignKey = @ForeignKey(ConstraintMode.CONSTRAINT))) protected Set<Address> addresses; // setters,

JPA: How to fetch eagerly an embedded element collection

喜你入骨 提交于 2020-05-10 08:57:58
问题 Consider the following model @Entity // JPA and JAXB annotations here public class Employee implements Serializable { // other fields, annotations, stuffs ... @ElementCollection(fetch = FetchType.LAZY, targetClass = Address.class) @CollectionTable(name = "employee_address", schema = "hris", joinColumns = @JoinColumn(name = "employee_id", nullable = false, referencedColumnName = "employee_id", foreignKey = @ForeignKey(ConstraintMode.CONSTRAINT))) protected Set<Address> addresses; // setters,

JPA: How to fetch eagerly an embedded element collection

淺唱寂寞╮ 提交于 2020-05-10 08:57:39
问题 Consider the following model @Entity // JPA and JAXB annotations here public class Employee implements Serializable { // other fields, annotations, stuffs ... @ElementCollection(fetch = FetchType.LAZY, targetClass = Address.class) @CollectionTable(name = "employee_address", schema = "hris", joinColumns = @JoinColumn(name = "employee_id", nullable = false, referencedColumnName = "employee_id", foreignKey = @ForeignKey(ConstraintMode.CONSTRAINT))) protected Set<Address> addresses; // setters,

JPA “contains one of”

跟風遠走 提交于 2020-03-21 20:19:52
问题 I'm writing a Dao to fetch all Messages relevant to a Person . But I can't find the correct JPQL syntax. In my model: a Person has multiple Roles (I pass these into the query as a parameter: Set of enum values). a Message is relevant to multiple Roles . So I want to find all messages relevant to a person: SELECT m FROM Message m WHERE m.roles [contains one of] :userRoles Giving it :userRoles as a Set<Role> parameter. What is the correct syntax for that missing [contains one of] section? I've

JPA “contains one of”

走远了吗. 提交于 2020-03-21 20:18:06
问题 I'm writing a Dao to fetch all Messages relevant to a Person . But I can't find the correct JPQL syntax. In my model: a Person has multiple Roles (I pass these into the query as a parameter: Set of enum values). a Message is relevant to multiple Roles . So I want to find all messages relevant to a person: SELECT m FROM Message m WHERE m.roles [contains one of] :userRoles Giving it :userRoles as a Set<Role> parameter. What is the correct syntax for that missing [contains one of] section? I've

JPA “contains one of”

谁说我不能喝 提交于 2020-03-21 20:17:43
问题 I'm writing a Dao to fetch all Messages relevant to a Person . But I can't find the correct JPQL syntax. In my model: a Person has multiple Roles (I pass these into the query as a parameter: Set of enum values). a Message is relevant to multiple Roles . So I want to find all messages relevant to a person: SELECT m FROM Message m WHERE m.roles [contains one of] :userRoles Giving it :userRoles as a Set<Role> parameter. What is the correct syntax for that missing [contains one of] section? I've