jpa

How to select just the foreign key value using Criteria Query?

ⅰ亾dé卋堺 提交于 2021-02-08 13:52:54
问题 Suppose I have two entities as: @Entity public class A { @Id private int id; @ManyToOne private B b; //more attributes } @Entity public class B { @Id private int id; } So, the table for A is having a column as b_id as the foreign key. Now, I want to select just the b_id based on some criteria on other fields. How can I do this using criteria query? I tried doing following which throws IllegalArgumentException saying "Unable to locate Attribute with the given name [b_id] on this ManagedType [A

Angularjs + Spring jpa repository Many-to-one field is not saving

落花浮王杯 提交于 2021-02-08 11:38:47
问题 I am using Angularjs, Spring jpa repository, hibernate. The problem is "Unable to save the id of the Customer in the order table." table names: Order, CustomerGlobal reference col name for Customer in Order table is customerGlobal_id. Order belongs to a Customer. Order table has a customerGlobal_id field. In the Entity (Order), I have defined @ManyToOne(optional = false) @JsonIgnore CustomerGlobal customerGlobal; Order belongs to one Customer. If I specify a JoinColumn, hibernate is

Angularjs + Spring jpa repository Many-to-one field is not saving

ぐ巨炮叔叔 提交于 2021-02-08 11:37:57
问题 I am using Angularjs, Spring jpa repository, hibernate. The problem is "Unable to save the id of the Customer in the order table." table names: Order, CustomerGlobal reference col name for Customer in Order table is customerGlobal_id. Order belongs to a Customer. Order table has a customerGlobal_id field. In the Entity (Order), I have defined @ManyToOne(optional = false) @JsonIgnore CustomerGlobal customerGlobal; Order belongs to one Customer. If I specify a JoinColumn, hibernate is

Hibernate Annotation relations does not work with spring.jpa.generate-ddl=true

走远了吗. 提交于 2021-02-08 08:55:23
问题 I am creating some simple Spring Boot project with Hibernate JPA. I created some data model which consists 5 tables for now and created entities reflecting tables. I have set spring.jpa.generate-ddl=true and my entities was correctly reflected by schema created in PostgreSQL. Next step was to start adding relations. Part of my assumed datamodel is (paron my UML) Very simple one to many relation. My entities look that way (getters and setters omitted below, exist in code): @Entity public class

CriteriaBuilder and isMember of list on entity (Hibernate)

北城余情 提交于 2021-02-08 07:05:03
问题 Okay, I'm trying to do something quite strange. I'm trying to use CriteriaBuilder and CriteriaQuery to return all entities who contain a given object in a collection on the entity. I've been banging my head against this for hours and the relevant documentation is little and not particularly useful. Any help would be greatly appreciated. Relevant excerpts of the classes are as follows. @Entity public class Entry { @ManyToMany(fetch=FetchType.EAGER) private List<Tag> tags = new ArrayList<Tag>()

CriteriaBuilder and isMember of list on entity (Hibernate)

六月ゝ 毕业季﹏ 提交于 2021-02-08 07:04:28
问题 Okay, I'm trying to do something quite strange. I'm trying to use CriteriaBuilder and CriteriaQuery to return all entities who contain a given object in a collection on the entity. I've been banging my head against this for hours and the relevant documentation is little and not particularly useful. Any help would be greatly appreciated. Relevant excerpts of the classes are as follows. @Entity public class Entry { @ManyToMany(fetch=FetchType.EAGER) private List<Tag> tags = new ArrayList<Tag>()

CriteriaBuilder and isMember of list on entity (Hibernate)

安稳与你 提交于 2021-02-08 07:02:48
问题 Okay, I'm trying to do something quite strange. I'm trying to use CriteriaBuilder and CriteriaQuery to return all entities who contain a given object in a collection on the entity. I've been banging my head against this for hours and the relevant documentation is little and not particularly useful. Any help would be greatly appreciated. Relevant excerpts of the classes are as follows. @Entity public class Entry { @ManyToMany(fetch=FetchType.EAGER) private List<Tag> tags = new ArrayList<Tag>()

$expand not working in my JPA/Olingo 2.0.11 OData Service

核能气质少年 提交于 2021-02-08 06:59:27
问题 Would be really interesting if the expand system query option works for any of you when using this library version. Library and Frameworks combination: Java OData 2 JPA Library 2.0.11 + JPA Hibernate + MySQL I am trying to use the system query option "expand" (eg. /books?$expand=PublisherDetails) in an OData query. At UriParserImpl#handleSystemQueryOptionExpand - L#796 occurs a NPE cause the edmType of the fetched property at L#792 is null If i want to query data from another table using

JPA Hibernate - Mapping Embedded Collections to a Single Table

守給你的承諾、 提交于 2021-02-08 05:57:34
问题 I have a table with lot of fields such as Account OrderNo Term LegNo LegSymbol LegSymbolType LegExchangeType etc etc The primary key of the above table is a composite key comprising of Account, OrderNo & LegNo The data in the DB would look something like this 1234 1 2 1 AAA BBB CCC 1234 1 2 2 DDD EEE FFF The bolded ones are Account,Order,LegNo respectively. While designing the entity for the above table, we want to group all the Leg related information (All bolded columns ) in a separate

Custom @Column JPA Annotations, how to?

左心房为你撑大大i 提交于 2021-02-08 03:47:32
问题 Been trying hard to search for a solution to create some Custom JPA Annotations to replace repetitive fields when declaring Entity POJOs. Any help? Here what I am trying to achieve: //@Column(name = "is_enabled", nullable = false, columnDefinition = "tinyint(1) DEFAULT 1") @ColumnBooleanNotNullDefaultOne private Boolean isEnabled; or //@Column(name = "created", nullable = false, updatable = false, insertable = false, columnDefinition = "TIMESTAMP DEFAULT CURRENT_TIMESTAMP") @ColumnTimestamp