jax-ws

How to get the URL of my WSDL?

由 喜你入骨 提交于 2020-02-21 13:05:59
问题 I have created a very simple web service using Netbeans, Java EE6, JAX-WS and TomCat. It just have one @WebMethod getWsdlURL(), which is supposed to return the URL of my wsdl, and it should be something similar to: http://192.168.70.44:8088/SimpleWebService/WebService?wsdl However I don't have any idea on how to do that. Can anyone help me? 回答1: Don't add your own service to return the URL. Depend on the runtime, that already supplies it. Just open the url in a browser. The url would be....

How to get the URL of my WSDL?

由 点点圈 提交于 2020-02-21 13:03:33
问题 I have created a very simple web service using Netbeans, Java EE6, JAX-WS and TomCat. It just have one @WebMethod getWsdlURL(), which is supposed to return the URL of my wsdl, and it should be something similar to: http://192.168.70.44:8088/SimpleWebService/WebService?wsdl However I don't have any idea on how to do that. Can anyone help me? 回答1: Don't add your own service to return the URL. Depend on the runtime, that already supplies it. Just open the url in a browser. The url would be....

WebService学习（一）——简介

由 生来就可爱ヽ(ⅴ＜●) 提交于 2020-02-10 18:38:16
一、什么是WebService Web Service是一个平台独立的，低耦合的，自包含的、基于可编程的web的应用程序，可使用开放的XML（标准通用标记语言下的一个子集）标准来描述、发布、发现、协调和配置这些应用程序，用于开发分布式的交互操作的应用程序。 Web Service技术， 能使得运行在不同机器上的不同应用无须借助附加的、专门的第三方软件或硬件， 就可相互交换数据或集成。依据Web Service规范实施的应用之间， 无论它们所使用的语言、 平台或内部协议是什么， 都可以相互交换数据。Web Service是自描述、 自包含的可用网络模块， 可以执行具体的业务功能。Web Service也很容易部署， 因为它们基于一些常规的产业标准以及已有的一些技术，诸如标准通用标记语言下的子集XML、HTTP。Web Service减少了应用接口的花费。Web Service为整个企业甚至多个组织之间的业务流程的集成提供了一个通用机制。 二、WebService规范 JAVA 有三种WebService 规范，分别是JAXM&SAAJ、JAX-WS（JAX-RPC）、JAX-RS JAXM&SAAJ： JAXM（JAVA API For XML Message）主要定义了包含了发送和接收消息所需的API，相当于Web 服务的服务器端。SAAJ（SOAP With Attachment

JAX-WS on Tomcat server

由 三世轮回 提交于 2020-02-03 10:20:35
问题 I am trying to deploy a JAX-WS on a Tomcat server. I have looked around the web and followed instructions I found here and here but to no avail. I get the following error and have no idea how to correct the issue. SEVERE: WSSERVLET11: failed to parse runtime descriptor: java.lang.NoClassDefFoundError: javax/xml/stream/XMLStreamException java.lang.NoClassDefFoundError: javax/xml/stream/XMLStreamException at com.sun.xml.ws.transport.http.servlet.WSServletContextListener.contextInitialized

JAX-WS on Tomcat server

由 余生长醉 提交于 2020-02-03 10:20:06
问题 I am trying to deploy a JAX-WS on a Tomcat server. I have looked around the web and followed instructions I found here and here but to no avail. I get the following error and have no idea how to correct the issue. SEVERE: WSSERVLET11: failed to parse runtime descriptor: java.lang.NoClassDefFoundError: javax/xml/stream/XMLStreamException java.lang.NoClassDefFoundError: javax/xml/stream/XMLStreamException at com.sun.xml.ws.transport.http.servlet.WSServletContextListener.contextInitialized

Java SOAP “wsimport” - force wrapped binding from document/literal wrapped WSDL?

由 丶灬走出姿态 提交于 2020-01-30 14:17:25
问题 The Java 6 JAX-WS "wsimport" utility does a great job of generating a web service skeleton (interface) given a WSDL file but with one personally annoying exception. When given a WSDL that uses the SOAP Document/literal wrapped style (also described here) it generates a service interface with a "bare" SOAP binding parameter style (with multiple arguments and return values expanded as "holder" objects in the method signatures) instead of the simple wrapped parameter and return value specified

ArrayOfXXX class out of soap input param of array type

由 末鹿安然 提交于 2020-01-23 09:34:26
问题 I have a method with input param as Array. When I generate stub out of it creates List type. But I want to know how to create a wrapper class around array type e.g. for class Apple it should create ArrayOfApple . Is there any change needs to be done in class or any specific plugin need to be used? Note: I am using JAXWS with Apache CXF implementation Below is the sample code: EmployeeService.java : @WebService(endpointInterface="com.test.EmployeeService") @SOAPBinding(style=Style.DOCUMENT)

ArrayOfXXX class out of soap input param of array type

由 坚强是说给别人听的谎言 提交于 2020-01-23 09:33:46
问题 I have a method with input param as Array. When I generate stub out of it creates List type. But I want to know how to create a wrapper class around array type e.g. for class Apple it should create ArrayOfApple . Is there any change needs to be done in class or any specific plugin need to be used? Note: I am using JAXWS with Apache CXF implementation Below is the sample code: EmployeeService.java : @WebService(endpointInterface="com.test.EmployeeService") @SOAPBinding(style=Style.DOCUMENT)

ArrayOfXXX class out of soap input param of array type

由 五迷三道 提交于 2020-01-23 09:33:12
问题 I have a method with input param as Array. When I generate stub out of it creates List type. But I want to know how to create a wrapper class around array type e.g. for class Apple it should create ArrayOfApple . Is there any change needs to be done in class or any specific plugin need to be used? Note: I am using JAXWS with Apache CXF implementation Below is the sample code: EmployeeService.java : @WebService(endpointInterface="com.test.EmployeeService") @SOAPBinding(style=Style.DOCUMENT)

ServerSOAPFaultException and how to read it?

由 笑着哭i 提交于 2020-01-23 05:21:30
问题 I did a request and my program spit out WARNING: Input Action on WSDL operation Search and @Action on its associated Web Method search did not match and will cause problems in dispatching the requests Exception in thread "main" com.sun.xml.internal.ws.fault.ServerSOAPFaultException: Client received SOAP Fault from server: Client error Please see the server log to find more detail regarding exact cause of the failure. at com.sun.xml.internal.ws.fault.SOAP11Fault.getProtocolException
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