iterator

Transforming an iterator into an iterator of chunks of duplicates

耗尽温柔 提交于 2021-01-28 13:47:03
问题 Suppose I am writing a function foo: Iterator[A] => Iterator[List[A]] to transform a given iterator into an iterator of chunks of duplicates : def foo[T](it: Iterator[A]): Iterator[List[A]] = ??? foo("abbbcbbe".iterator).toList.map(_.mkString) // List("a", "bbb", "c", "bb", "e") In order to implement foo I want to reuse function splitDupes: Iterator[A] => (List[A], Iterator[A]) that splits an iterator into a prefix with duplicates and the rest (thanks a lot to Kolmar who suggested it here)

Transforming an iterator into an iterator of chunks of duplicates

心不动则不痛 提交于 2021-01-28 13:43:32
问题 Suppose I am writing a function foo: Iterator[A] => Iterator[List[A]] to transform a given iterator into an iterator of chunks of duplicates : def foo[T](it: Iterator[A]): Iterator[List[A]] = ??? foo("abbbcbbe".iterator).toList.map(_.mkString) // List("a", "bbb", "c", "bb", "e") In order to implement foo I want to reuse function splitDupes: Iterator[A] => (List[A], Iterator[A]) that splits an iterator into a prefix with duplicates and the rest (thanks a lot to Kolmar who suggested it here)

How do I return an iterator over a 2D array with the enumeration indices included?

做~自己de王妃 提交于 2021-01-28 08:54:57
问题 I have a struct containing a 2D array: struct Block; struct World { blocks: [[Block; 10]; 10], } How could I write a function which returns an iterator over a 2D array, but with the enumeration indices included? fn enumerate_blocks(&self) -> impl Iterator<Item = (usize, usize, &Block)> I managed to write an implementation of the function which just returns an iterator without enumeration indices: fn blocks(&self) -> impl Iterator<Item = &Block> { self.blocks.iter().flat_map(|x| x.iter()) } If

How do I return an iterator over a 2D array with the enumeration indices included?

百般思念 提交于 2021-01-28 08:40:55
问题 I have a struct containing a 2D array: struct Block; struct World { blocks: [[Block; 10]; 10], } How could I write a function which returns an iterator over a 2D array, but with the enumeration indices included? fn enumerate_blocks(&self) -> impl Iterator<Item = (usize, usize, &Block)> I managed to write an implementation of the function which just returns an iterator without enumeration indices: fn blocks(&self) -> impl Iterator<Item = &Block> { self.blocks.iter().flat_map(|x| x.iter()) } If

How to properly pass Iterators to a function in Rust

别来无恙 提交于 2021-01-28 07:30:31
问题 I want to pass Iterators to a function, which then computes some value from these iterators. I am not sure how a robust signature to such a function would look like. Lets say I want to iterate f64. You can find the code in the playground: https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=c614429c541f337adb102c14518cf39e My first attempt was fn dot(a : impl std::iter::Iterator<Item = f64>,b : impl std::iter::Iterator<Item = f64>) -> f64 { a.zip(b).map(|(x,y)| x*y).sum() }

Techniques for turning recursive functions into iterators in Rust?

若如初见. 提交于 2021-01-28 04:00:56
问题 I'm struggling to turn a simple recursive function into a simple iterator. The problem is that the recursive function maintains state in its local variables and call stack -- and to turn this into a rust iterator means basically externalizing all the function state into mutable properties on some custom iterator struct. It's quite a messy endeavor. In a language like javascript or python, yield comes to the rescue. Are there any techniques in Rust to help manage this complexity? Simple

Techniques for turning recursive functions into iterators in Rust?

半城伤御伤魂 提交于 2021-01-28 03:45:37
问题 I'm struggling to turn a simple recursive function into a simple iterator. The problem is that the recursive function maintains state in its local variables and call stack -- and to turn this into a rust iterator means basically externalizing all the function state into mutable properties on some custom iterator struct. It's quite a messy endeavor. In a language like javascript or python, yield comes to the rescue. Are there any techniques in Rust to help manage this complexity? Simple

Implementing pandas function to numpy functions

ε祈祈猫儿з 提交于 2021-01-27 19:20:44
问题 Is there a way I could convert the xy_mean function to be computed using the pandas library just like the y_mean function. I found out that the pandas function Y_mean = pd.Series(PC_list).rolling(number).mean().dropna().to_numpy() is way faster than the numpy version ym = (np.convolve(PC_list, np.ones(shape=(number)), mode='valid')/number)[:-1] . The equation for the xy_mean would be ((index of value)*value + (index of value)*value)/number The index number would be dependent on the variable

Why doesn't the istreambuf_iterator advance work

本小妞迷上赌 提交于 2021-01-27 18:40:11
问题 I was reading Constructing a vector with istream_iterators which is about reading a complete file contents into a vector of chars. While I want a portion of a file to be loaded in to a vector of chars. #include <iostream> #include <fstream> #include <iterator> #include <vector> #include <algorithm> using namespace std; int main(int argc, char *argv[]) { ifstream ifs(argv[1], ios::binary); istreambuf_iterator<char> beginItr(ifs); istreambuf_iterator<char> endItr(beginItr); advance(endItr, 4);

Iterate over different dataframe

半腔热情 提交于 2021-01-27 18:37:48
问题 I am trying to iterate over three data frames to find the difference between them. I have a master data frame which contains everything and two other data frames which contains partial of master data frame. I am trying to write a python code to identify what is missing in the other two files. Master file looks like following: ID Name 1 Mike 2 Dani 3 Scott 4 Josh 5 Nate 6 Sandy second data frame looks like following: ID Name 1 Mike 2 Dani 3 Scott 6 Sandy Third data frame looks like following: